Algebra MCQs 2026
45 questions with detailed answers · 17 from past papers · 5 quiz batches available
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- Q1 Past Paper · PPSC/FPSC/NTS medium
Find the 10th term of the AP: 3, 7, 11, 15, ...
💡 Explanation:T10 = 3 + 9(4) = 39.
- Q2 medium
The sum of an infinite geometric progression with |r| < 1 is given by
💡 Explanation:For an infinite GP with |r|<1, the sum is a/(1-r).
- Q3 Past Paper · PPSC/FPSC/NTS medium
Find the 5th term of the GP: 2, 6, 18, 54, ...
💡 Explanation:T5 = 2 * 3^4 = 2 * 81 = 162.
- Q4 medium
The nth term of a geometric progression with first term a and common ratio r is
💡 Explanation:The nth term of a GP is a * r^(n-1).
- Q5 Past Paper · PPSC/FPSC/NTS hard
Find the sum of the first 20 natural numbers
💡 Explanation:Sum = n(n+1)/2 = 20(21)/2 = 210.
- Q6 medium
The sum of the first n terms of an AP with first term a and last term l is
💡 Explanation:Sum of first n terms of an AP = n/2 (a+l), where l is the last term.
- Q7 medium
The nth term of an arithmetic progression with first term a and common difference d is
💡 Explanation:The nth term of an AP is a + (n-1)d.
- Q8 easy
Solve the inequality: 2x - 3 > 7
💡 Explanation:Adding 3 to both sides and dividing by 2: x > 5.
- Q9 hard
Find k if (x - 2) is a factor of x^2 + kx - 10
💡 Explanation:p(2) = 4 + 2k - 10 = 0 gives k = 3.
- Q10 hard
Find the remainder when p(x) = x^3 - 3x^2 + 2x - 5 is divided by (x - 1)
💡 Explanation:p(1) = 1 - 3 + 2 - 5 = -5.
- Q11 medium
Solve the inequality: 3 - x >= 1
💡 Explanation:Dividing by -1 reverses the inequality direction: x <= 2.
- Q12 Past Paper · PPSC/FPSC/NTS hard
By the Factor Theorem, (x - a) is a factor of p(x) if and only if
💡 Explanation:By the Factor Theorem, (x-a) is a factor of p(x) if and only if p(a) = 0.
- Q13 Past Paper · PPSC/FPSC/NTS hard
By the Remainder Theorem, when a polynomial p(x) is divided by (x - a), the remainder equals
💡 Explanation:By the Remainder Theorem, dividing p(x) by (x-a) leaves remainder p(a).
- Q14 medium
Rationalize: 1/sqrt(2)
💡 Explanation:Multiply numerator and denominator by sqrt(2): 1/sqrt(2) = sqrt(2)/2.
- Q15 medium
Simplify: sqrt(2) * sqrt(8)
💡 Explanation:sqrt(2) * sqrt(8) = sqrt(16) = 4.
- Q16 Past Paper · PPSC/FPSC/NTS easy
Simplify: x^-2
💡 Explanation:A negative exponent gives the reciprocal: x^-2 = 1/x^2.
- Q17 medium
For a quadratic equation ax^2 + bx + c = 0, the product of the roots is
💡 Explanation:For ax^2+bx+c=0, product of roots = c/a.
- Q18 medium
For a quadratic equation ax^2 + bx + c = 0, the sum of the roots is
💡 Explanation:For ax^2+bx+c=0, sum of roots = -b/a.
- Q19 Past Paper · PPSC/FPSC/NTS medium
What is the larger root of the equation x^2 + x - 6 = 0
💡 Explanation:Factoring gives (x+3)(x-2) = 0, so x = -3 or x = 2; the larger root is 2.
- Q20 Past Paper · PPSC/FPSC/NTS medium
What are the roots of the equation x^2 - 9 = 0
💡 Explanation:x^2 = 9 gives x = 3 or x = -3.
- Q21 Past Paper · PPSC/FPSC/NTS easy
Solve for x: 3x + 7 = 22
💡 Explanation:Subtract 7 from both sides: 3x = 15, so x = 5.
- Q22 easy
If x - 5 = 12, find the value of x
💡 Explanation:Add 5 to both sides: x = 12 + 5 = 17.
- Q23 easy
Expand: (a-b)^2
💡 Explanation:(a-b)^2 = a^2-2ab+b^2.
- Q24 Past Paper · PPSC/FPSC/NTS easy
a^2 - b^2 is equal to
💡 Explanation:a^2-b^2 factors as (a+b)(a-b).
- Q25 medium
Expand: (a+b)^3
💡 Explanation:(a+b)^3 = a^3+3a^2b+3ab^2+b^3.
- Q26 medium
a^3 + b^3 is equal to
💡 Explanation:a^3+b^3 = (a+b)(a^2-ab+b^2).
- Q27 medium
a^3 - b^3 is equal to
💡 Explanation:a^3-b^3 = (a-b)(a^2+ab+b^2).
- Q28 Past Paper · PPSC/FPSC/NTS easy
Simplify: x^2 * x^3
💡 Explanation:When multiplying powers with the same base, add exponents: x^2 * x^3 = x^5.
- Q29 easy
Simplify: x^4 / x^2
💡 Explanation:When dividing powers with the same base, subtract exponents: x^4/x^2 = x^2.
- Q30 easy
Simplify: (x^3)^2
💡 Explanation:When raising a power to a power, multiply exponents: (x^3)^2 = x^6.
- Q31 easy
What is the value of x^0 for any nonzero x
💡 Explanation:Any nonzero number raised to the power 0 equals 1.
- Q32 Past Paper · PPSC/FPSC/NTS medium
What is the product of the roots of the equation x^2 - 5x + 6 = 0
💡 Explanation:Product of roots = c/a = 6/1 = 6.
- Q33 Past Paper · PPSC/FPSC/NTS easy
Solve for x: 2(x + 3) = 16
💡 Explanation:Divide by 2: x + 3 = 8, so x = 5.
- Q34 easy
Solve for x: 5x - 3 = 3x + 9
💡 Explanation:Bring like terms together: 2x = 12, so x = 6.
- Q35 medium
If x + y = 10 and x - y = 4, find the value of x
💡 Explanation:Adding the two equations gives 2x = 14, so x = 7.
- Q36 medium
If 2x + y = 11 and x - y = 1, find the value of y
💡 Explanation:Subtracting the equations gives x = 4, then y = 11 - 2(4) = 3.
- Q37 medium
If x + 2y = 8 and 2x + y = 7, find the value of x + y
💡 Explanation:Solving the system gives x = 2 and y = 3, so x + y = 5.
- Q38 medium
Solve for x: x/3 + x/4 = 7
💡 Explanation:Multiply through by 12: 4x + 3x = 84, so x = 12.
- Q39 Past Paper · PPSC/FPSC/NTS medium
What is the sum of the roots of the equation x^2 - 5x + 6 = 0
💡 Explanation:Sum of roots = -b/a = -(-5)/1 = 5.
- Q40 Past Paper · PPSC/FPSC/NTS easy
Expand: (a+b)^2
💡 Explanation:(a+b)^2 = a^2+2ab+b^2.
- Q41 medium
Factorize: 2x^2 + 5x + 3
💡 Explanation:(2x+3)(x+1) expands to 2x^2+5x+3.
- Q42 Past Paper · PPSC/FPSC/NTS easy
Factorize: x^2 + 7x + 12
💡 Explanation:3 and 4 multiply to 12 and add to 7, so x^2+7x+12 = (x+3)(x+4).
- Q43 Past Paper · PPSC/FPSC/NTS easy
Factorize: x^2 - 16
💡 Explanation:This is the difference of squares: x^2 - 16 = (x-4)(x+4).
- Q44 hard
If the discriminant b^2 - 4ac = 0, the roots of the quadratic equation are
💡 Explanation:When the discriminant equals zero, the roots are real and equal.
- Q45 hard
The discriminant of the quadratic equation ax^2 + bx + c = 0 is
💡 Explanation:The discriminant is defined as b^2 - 4ac.