DC Machines MCQs 2026

66 questions with detailed answers · 12 from past papers · 7 quiz batches available

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Page 1 of 1 Questions 110 of 66
  1. Q1 medium

    Reversal of rotation of DC motor can be by

    1. A reversing armature OR field (not both together for same direction change twice)
    2. B shorting armature only
    3. C opening field only
    4. D increasing Ra only
    💡 Explanation:

    Reverse Ia or If direction.

  2. Q2 hard

    Maximum efficiency of DC machine often occurs when

    1. A copper loss zero
    2. B iron loss zero
    3. C variable loss equals constant loss approximately
    4. D speed zero
    💡 Explanation:

    Max eta when I²R var ≈ constant losses.

  3. Q3 hard

    Armature reaction shift causes

    1. A brush position adjustment (neutral axis shift)
    2. B no effect on commutation
    3. C infinite speed
    4. D zero Eb always
    💡 Explanation:

    Geometric neutral shifts with load.

  4. Q4 easy

    Main poles produce

    1. A only armature copper
    2. B primary working flux in air gap
    3. C only brush friction
    4. D only reactive power
    💡 Explanation:

    Field poles create main phi.

  5. Q5 easy

    Yoke in DC machine provides

    1. A mechanical support and part of magnetic flux path
    2. B only electrical insulation
    3. C only commutation
    4. D only cooling air path only without structure
    💡 Explanation:

    Yoke carries flux and supports poles.

  6. Q6 easy

    Cooling methods for DC machines include

    1. A only vacuum
    2. B only heating
    3. C natural air, forced air, and liquid cooling
    4. D no cooling needed ever
    💡 Explanation:

    Heat removal extends rating.

  7. Q7 easy

    Rating of DC machine specifies

    1. A only color of paint
    2. B output power, voltage, speed (and current)
    3. C only brush count without power
    4. D only field resistance
    💡 Explanation:

    Nameplate ratings.

  8. Q8 medium

    Eb in generator on open circuit equals

    1. A zero always
    2. B Ia Ra only
    3. C terminal voltage (no Ia Ra drop)
    4. D twice supply V
    💡 Explanation:

    No load → V = Eb.

  9. Q9 medium

    Load characteristic of motor shows

    1. A speed always increases with load
    2. B torque independent of Ia
    3. C Eb equals zero at load
    4. D speed decreasing as torque (load) increases for shunt type
    💡 Explanation:

    Shunt motor drooping speed-load curve.

  10. Q10 hard

    Over-compounded generator has

    1. A falling voltage always
    2. B rising terminal voltage with load due to series field
    3. C zero regulation
    4. D AC output only
    💡 Explanation:

    Over-compound boosts V with load.

  11. Q11 Past Paper · PPSC/FPSC/CSS medium

    Speed control of DC shunt motor by field flux weakening

    1. A decreases speed always
    2. B stops motor instantly
    3. C increases speed above rated
    4. D reverses rotation always
    💡 Explanation:

    Lower phi → higher N.

  12. Q12 medium

    Back EMF constant relates Eb to

    1. A only armature resistance
    2. B only brush drop
    3. C speed and flux
    4. D only load torque
    💡 Explanation:

    Eb = K phi omega.

  13. Q13 medium

    Torque constant relates T to

    1. A only speed
    2. B only Eb
    3. C only field resistance
    4. D flux and armature current
    💡 Explanation:

    T = K phi Ia.

  14. Q14 medium

    DC motor mechanical output is

    1. A V times Ia always
    2. B Eb times Ia (approx developed power)
    3. C Ia squared R only
    4. D field copper loss
    💡 Explanation:

    Developed power ≈ Eb Ia.

  15. Q15 hard

    Swamping resistance in generator

    1. A starts motor only
    2. B measures speed
    3. C makes parallel field diverter for voltage regulation
    4. D replaces commutator
    💡 Explanation:

    Used in compound generator regulation.

  16. Q16 hard

    Equalizer connection in lap winding

    1. A increases field flux
    2. B balances parallel path currents
    3. C reduces Eb to zero
    4. D eliminates armature
    💡 Explanation:

    Equalizer for lap winding balance.

  17. Q17 hard

    Commutator pitch relates to

    1. A coil span and number of commutator segments
    2. B only field poles count
    3. C only supply frequency
    4. D only AC phase
    💡 Explanation:

    Commutator/ coil pitch design.

  18. Q18 hard

    Sparkless commutation requires

    1. A current in coil near zero at brush short-circuit
    2. B maximum Ia always
    3. C zero field flux
    4. D open circuited armature
    💡 Explanation:

    Reactance voltage compensated.

  19. Q19 medium

    Three-point starter protects DC shunt motor from

    1. A low field (high speed runaway) and overload
    2. B only reverse rotation always
    3. C only low voltage starting
    4. D AC supply only
    💡 Explanation:

    No-volt and OLR coils.

  20. Q20 hard

    Four-point starter separates

    1. A armature from supply
    2. B commutator from brushes
    3. C Eb from speed
    4. D field circuit from OLR so field is not affected by OLR drop
    💡 Explanation:

    Better for shunt field control.

  21. Q21 easy

    Motor characteristic curve plots

    1. A flux vs voltage only
    2. B PF vs frequency
    3. C B vs H only
    4. D speed vs torque or speed vs current
    💡 Explanation:

    Performance curves for motors.

  22. Q22 medium

    Generator external characteristic plots

    1. A speed vs torque only
    2. B B vs H only
    3. C XL vs f only
    4. D terminal voltage vs load current
    💡 Explanation:

    V vs I load curve.

  23. Q23 medium

    Voltage regulation of generator is

    1. A Ia times Ra only
    2. B Eb only
    3. C (V no-load minus V full-load)/V rated times 100%
    4. D speed times flux only
    💡 Explanation:

    Regulation measures V drop with load.

  24. Q24 medium

    Reason for armature resistance drop is

    1. A Eb increases with load always
    2. B field flux zero
    3. C Ia times Ra reduces terminal voltage in generator
    4. D speed zero
    💡 Explanation:

    V = Eb - IaRa (generator).

  25. Q25 medium

    Motor armature equation V equals

    1. A Eb minus Ia Ra only always
    2. B Eb plus Ia Ra plus brush drop
    3. C Ia Ra only
    4. D Eb only
    💡 Explanation:

    V = Eb + IaRa + Vbrush.

  26. Q26 medium

    If load on DC shunt motor increases, armature current

    1. A decreases always
    2. B increases and speed drops slightly
    3. C stays exactly constant always
    4. D becomes zero
    💡 Explanation:

    More load → more Ia → speed drops.

  27. Q27 medium

    If field flux of shunt motor decreases, speed

    1. A decreases always
    2. B increases
    3. C unchanged always
    4. D becomes zero instantly
    💡 Explanation:

    N proportional to 1/phi.

  28. Q28 hard

    Series motor should not be run on no-load because

    1. A Eb becomes infinite always
    2. B field is too strong
    3. C torque is maximum at no load
    4. D speed may dangerously increase (flux proportional to Ia)
    💡 Explanation:

    Light load → low Ia → low phi → high speed.

  29. Q29 medium

    DC machine armature is made of

    1. A solid copper block
    2. B laminated silicon steel to reduce eddy losses
    3. C plastic only
    4. D air gap only
    💡 Explanation:

    Laminations reduce eddy currents.

  30. Q30 hard

    Number of parallel paths A affects

    1. A armature current per path and conductor sizing
    2. B only field turns
    3. C only brush material
    4. D only supply frequency
    💡 Explanation:

    More paths → lower current per path.

  31. Q31 hard

    Hysteresis loss in core depends on

    1. A armature I only
    2. B brush voltage only
    3. C material, flux density, and frequency of reversal
    4. D external load resistance only
    💡 Explanation:

    Steinmetz-type dependence on Bmax, f.

  32. Q32 medium

    Windage and friction losses depend on

    1. A field current only
    2. B speed primarily
    3. C load current only at standstill
    4. D supply PF only
    💡 Explanation:

    Mechanical losses ∝ speed.

  33. Q33 hard

    Over-compounded generator has

    1. A falling voltage always
    2. B rising terminal voltage with load due to series field
    3. C zero regulation
    4. D AC output only
    💡 Explanation:

    Over-compound boosts V with load.

  34. Q34 medium

    Load characteristic of motor shows

    1. A speed always increases with load
    2. B torque independent of Ia
    3. C Eb equals zero at load
    4. D speed decreasing as torque (load) increases for shunt type
    💡 Explanation:

    Shunt motor drooping speed-load curve.

  35. Q35 medium

    Eb in generator on open circuit equals

    1. A zero always
    2. B Ia Ra only
    3. C terminal voltage (no Ia Ra drop)
    4. D twice supply V
    💡 Explanation:

    No load → V = Eb.

  36. Q36 easy

    Rating of DC machine specifies

    1. A only color of paint
    2. B output power, voltage, speed (and current)
    3. C only brush count without power
    4. D only field resistance
    💡 Explanation:

    Nameplate ratings.

  37. Q37 easy

    Cooling methods for DC machines include

    1. A only vacuum
    2. B only heating
    3. C natural air, forced air, and liquid cooling
    4. D no cooling needed ever
    💡 Explanation:

    Heat removal extends rating.

  38. Q38 easy

    Yoke in DC machine provides

    1. A mechanical support and part of magnetic flux path
    2. B only electrical insulation
    3. C only commutation
    4. D only cooling air path only without structure
    💡 Explanation:

    Yoke carries flux and supports poles.

  39. Q39 easy

    Main poles produce

    1. A only armature copper
    2. B primary working flux in air gap
    3. C only brush friction
    4. D only reactive power
    💡 Explanation:

    Field poles create main phi.

  40. Q40 hard

    Armature reaction shift causes

    1. A brush position adjustment (neutral axis shift)
    2. B no effect on commutation
    3. C infinite speed
    4. D zero Eb always
    💡 Explanation:

    Geometric neutral shifts with load.

  41. Q41 hard

    Maximum efficiency of DC machine often occurs when

    1. A copper loss zero
    2. B iron loss zero
    3. C variable loss equals constant loss approximately
    4. D speed zero
    💡 Explanation:

    Max eta when I²R var ≈ constant losses.

  42. Q42 medium

    Reversal of rotation of DC motor can be by

    1. A reversing armature OR field (not both together for same direction change twice)
    2. B shorting armature only
    3. C opening field only
    4. D increasing Ra only
    💡 Explanation:

    Reverse Ia or If direction.

  43. Q43 medium

    Brush contact drop is typically assumed

    1. A proportional to square of speed only
    2. B zero always
    3. C nearly constant (~2 V total for carbon brushes pair)
    4. D equal to Eb
    💡 Explanation:

    Approx constant drop per brush set.

  44. Q44 medium

    Differential compound motor has

    1. A series aiding shunt
    2. B only series field
    3. C only permanent magnet
    4. D series flux opposing shunt flux
    💡 Explanation:

    Differential: series opposes shunt.

  45. Q45 medium

    Cumulative compound motor has

    1. A series flux opposing shunt
    2. B series flux aiding shunt flux
    3. C no shunt field
    4. D only AC excitation
    💡 Explanation:

    Cumulative: series aids shunt.

  46. Q46 hard

    Wave winding in DC machine has

    1. A paths equal to poles always
    2. B zero paths
    3. C only shunt field
    4. D two parallel paths typically
    💡 Explanation:

    Wave: usually 2 parallel paths.

  47. Q47 hard

    Lap winding in DC machine has

    1. A always one path
    2. B no commutator
    3. C parallel paths equal to number of poles (typical)
    4. D only AC output
    💡 Explanation:

    Lap: A = P paths common.

  48. Q48 medium

    Brush and commutator function is to

    1. A increase frequency
    2. B convert internal AC in armature to external DC
    3. C measure flux only
    4. D eliminate back EMF
    💡 Explanation:

    Commutator rectifies armature AC.

  49. Q49 medium

    Input 400 W, total losses 60 W: output power is

    1. A 460 W
    2. B 60 W
    3. C 340 W W
    4. D NaN W
    💡 Explanation:

    Pout = Pin - losses = 340 W W.

  50. Q50 medium

    Input 800 W, total losses 120 W: output power is

    1. A 680 W W
    2. B 920 W
    3. C 120 W
    4. D NaN W
    💡 Explanation:

    Pout = Pin - losses = 680 W W.

  51. Q51 medium

    Input 2000 W, total losses 300 W: output power is

    1. A 2300 W
    2. B 300 W
    3. C 1700 W W
    4. D NaN W
    💡 Explanation:

    Pout = Pin - losses = 1700 W W.

  52. Q52 medium

    Input 500 W, total losses 75 W: output power is

    1. A 575 W
    2. B 75 W
    3. C NaN W
    4. D 425 W W
    💡 Explanation:

    Pout = Pin - losses = 425 W W.

  53. Q53 medium

    Input 1000 W, total losses 150 W: output power is

    1. A 850 W W
    2. B 1150 W
    3. C 150 W
    4. D NaN W
    💡 Explanation:

    Pout = Pin - losses = 850 W W.

  54. Q54 easy

    Input 100 W, output 70 W: efficiency is

    1. A 30%
    2. B 70%
    3. C 140%
    4. D 35%
    💡 Explanation:

    eta = 70/100 = 70%.

  55. Q55 Past Paper · PPSC/FPSC/CSS easy

    Input 750 W, output 600 W: efficiency is

    1. A 20%
    2. B 80%
    3. C 160%
    4. D 40%
    💡 Explanation:

    eta = 600/750 = 80%.

  56. Q56 Past Paper · PPSC/FPSC/CSS easy

    Input 2000 W, output 1700 W: efficiency is

    1. A 15%
    2. B 170%
    3. C 85%
    4. D 42.5%
    💡 Explanation:

    eta = 1700/2000 = 85%.

  57. Q57 Past Paper · PPSC/FPSC/CSS easy

    Input 500 W, output 400 W: efficiency is

    1. A 20%
    2. B 160%
    3. C 40%
    4. D 80%
    💡 Explanation:

    eta = 400/500 = 80%.

  58. Q58 Past Paper · PPSC/FPSC/CSS easy

    Input 1000 W, output 800 W: efficiency is

    1. A 80%
    2. B 20%
    3. C 160%
    4. D 40%
    💡 Explanation:

    eta = 800/1000 = 80%.

  59. Q59 Past Paper · PPSC/FPSC/CSS medium

    DC motor V=440 V, Eb=400 V: armature voltage equation net driving (V-Eb) is

    1. A 40 V drop
    2. B 840 V
    3. C 40 V
    4. D -40 V
    💡 Explanation:

    V = Eb + IaRa; net = V-Eb = 40 V.

  60. Q60 Past Paper · PPSC/FPSC/CSS medium

    DC motor V=110 V, Eb=90 V: armature voltage equation net driving (V-Eb) is

    1. A 20 V drop
    2. B 200 V
    3. C 20 V
    4. D -20 V
    💡 Explanation:

    V = Eb + IaRa; net = V-Eb = 20 V.

  61. Q61 Past Paper · PPSC/FPSC/CSS medium

    DC motor V=230 V, Eb=210 V: armature voltage equation net driving (V-Eb) is

    1. A 20 V
    2. B 20 V drop
    3. C 440 V
    4. D -20 V
    💡 Explanation:

    V = Eb + IaRa; net = V-Eb = 20 V.

  62. Q62 Past Paper · PPSC/FPSC/CSS medium

    DC motor V=220 V, Eb=180 V: armature voltage equation net driving (V-Eb) is

    1. A 40 V
    2. B 40 V drop
    3. C 400 V
    4. D -40 V
    💡 Explanation:

    V = Eb + IaRa; net = V-Eb = 40 V.

  63. Q63 Past Paper · PPSC/FPSC/CSS medium

    DC motor V=240 V, Eb=200 V: armature voltage equation net driving (V-Eb) is

    1. A 40 V drop
    2. B 440 V
    3. C -40 V
    4. D 40 V
    💡 Explanation:

    V = Eb + IaRa; net = V-Eb = 40 V.

  64. Q64 hard

    Ward-Leonard system provides

    1. A only AC starting
    2. B smooth wide-range DC motor speed control
    3. C only field reversal without speed change
    4. D only generator protection
    💡 Explanation:

    Motor-generator set for speed control.

  65. Q65 Past Paper · PPSC/FPSC/CSS medium

    Armature voltage control of DC motor

    1. A varies speed below rated by changing V
    2. B increases flux only
    3. C controls only field
    4. D eliminates back EMF
    💡 Explanation:

    Lower V → lower speed.

  66. Q66 Past Paper · PPSC/FPSC/CSS medium

    Speed control of DC shunt motor by field flux weakening

    1. A decreases speed always
    2. B stops motor instantly
    3. C increases speed above rated
    4. D reverses rotation always
    💡 Explanation:

    Lower phi → higher N.