Three-Phase Induction Motors MCQs 2026
90 questions with detailed answers · 32 from past papers · 9 quiz batches available
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- Q1 Past Paper · PPSC/FPSC/CSS easy
The slip of a three-phase induction motor is defined as
💡 Explanation:Slip s expresses how far rotor speed Nr lags synchronous speed Ns.
- Q2 easy
Synchronous speed of a 50 Hz, 4-pole induction motor is
💡 Explanation:Ns = 120f/P = 120×50/4 = 1500 rpm.
- Q3 Past Paper · PPSC/FPSC/CSS easy
At standstill, slip of an induction motor is
💡 Explanation:When Nr = 0, s = (Ns - 0)/Ns = 1.
- Q4 easy
At synchronous speed, slip of an induction motor is
💡 Explanation:When Nr = Ns, s = 0 and no torque is developed.
- Q5 Past Paper · PPSC/FPSC/CSS medium
Rotor frequency in a running induction motor equals
💡 Explanation:Rotor induced EMF and current frequency is sf where s is slip.
- Q6 medium
For a 50 Hz motor at 4% slip, rotor frequency is
💡 Explanation:sf = 0.04 × 50 = 2 Hz.
- Q7 Past Paper · PPSC/FPSC/CSS medium
The torque-slip curve of an induction motor is approximately linear in the region
💡 Explanation:In normal load range, torque rises nearly linearly with slip.
- Q8 medium
Breakdown torque of an induction motor occurs at
💡 Explanation:Maximum torque point on the torque-slip curve is breakdown or pull-out torque.
- Q9 Past Paper · PPSC/FPSC/CSS medium
Starting torque of a squirrel-cage motor is typically
💡 Explanation:Design of rotor bars sets starting torque relative to full-load torque.
- Q10 easy
Direct-on-line (DOL) starting applies
💡 Explanation:DOL gives highest starting current and torque for a given motor.
- Q11 Past Paper · PPSC/FPSC/CSS easy
Main disadvantage of DOL starting for large motors is
💡 Explanation:High inrush current causes voltage dip and thermal stress.
- Q12 medium
Star-delta starting reduces starting current to approximately
💡 Explanation:Line current in star is 1/√3 of delta; power and torque scale similarly at start.
- Q13 Past Paper · PPSC/FPSC/CSS medium
Star-delta starter is applicable only when
💡 Explanation:Stator must be reconnectable between star start and delta run.
- Q14 medium
Autotransformer starting reduces voltage to motor by
💡 Explanation:Reduced stator voltage lowers starting current and torque proportionally to V².
- Q15 Past Paper · PPSC/FPSC/CSS easy
Rotor resistance starting is used with
💡 Explanation:External resistance in rotor circuit increases starting torque and limits current.
- Q16 medium
Adding external resistance in wound-rotor circuit at start
💡 Explanation:Higher rotor resistance shifts breakdown torque toward higher slip, aiding start.
- Q17 Past Paper · PPSC/FPSC/CSS easy
Squirrel-cage rotor construction uses
💡 Explanation:Cage rotor is rugged, maintenance-free, and low cost.
- Q18 easy
Wound-rotor motors differ from cage motors mainly by
💡 Explanation:Slip rings allow resistance control and slip energy recovery schemes.
- Q19 Past Paper · PPSC/FPSC/CSS hard
Crawling in induction motors is caused by
💡 Explanation:Harmonic torques can make motor run stably at about 1/7th of synchronous speed.
- Q20 hard
Cogging in induction motors occurs when
💡 Explanation:Magnetic locking between stator and rotor teeth prevents smooth starting.
- Q21 Past Paper · PPSC/FPSC/CSS medium
Ratio of starting torque to full-load torque is called
💡 Explanation:Tst defines ability to accelerate load from rest.
- Q22 medium
High-resistance rotor bars increase
💡 Explanation:Trade-off between start performance and running losses.
- Q23 Past Paper · PPSC/FPSC/CSS medium
DOL starting torque is proportional to
💡 Explanation:Torque ∝ V² for induction motor at fixed frequency and slip.
- Q24 medium
Star connection at start compared to delta run gives starting torque
💡 Explanation:Voltage per phase is 1/√3, so torque ∝ V² gives 1/3 torque.
- Q25 Past Paper · PPSC/FPSC/CSS hard
Autotransformer starter set at 70% tap gives approximately
💡 Explanation:Torque scales with V²: 0.7² ≈ 0.49 of DOL torque.
- Q26 hard
For maximum starting torque with rotor resistance, total rotor circuit resistance should equal
💡 Explanation:Condition R2 = X2 places breakdown at s=1 for maximum start torque.
- Q27 Past Paper · PPSC/FPSC/CSS easy
Slip rings on wound-rotor motors are used to
💡 Explanation:Brushes ride on rings to access three-phase rotor winding.
- Q28 easy
Maintenance of squirrel-cage motors is generally lower because
💡 Explanation:Eliminating slip-ring assembly reduces wear and inspection.
- Q29 Past Paper · PPSC/FPSC/CSS hard
To reduce cogging, designers often choose
💡 Explanation:Skew and slot ratio selection minimizes locking torque.
- Q30 medium
Skewing rotor bars helps reduce
💡 Explanation:Skew smooths torque variation as bars traverse stator field.
- Q31 Past Paper · PPSC/FPSC/CSS hard
Outer cage in double-cage rotor has
💡 Explanation:Outer cage carries high-frequency start current due to leakage flux path.
- Q32 hard
Inner cage of double-cage rotor primarily carries
💡 Explanation:Low frequency at run allows inner low-resistance cage to dominate.
- Q33 Past Paper · PPSC/FPSC/CSS medium
Below base speed in V/f drive, increasing frequency without raising voltage causes
💡 Explanation:Constant V/f keeps air-gap flux near rated value.
- Q34 hard
Above base speed, V/f drives often operate in
💡 Explanation:Voltage ceiling limits flux; torque falls with speed above base.
- Q35 Past Paper · PPSC/FPSC/CSS medium
Pole-changing from 4 poles to 8 poles at same 50 Hz halves
💡 Explanation:Ns inversely proportional to pole count P.
- Q36 medium
Two separate windings for two speeds is
💡 Explanation:Dual-winding motors cost more but allow non-2:1 speed ratios.
- Q37 Past Paper · PPSC/FPSC/CSS hard
Static Kramer drive inserts
💡 Explanation:Controlled slip power return improves efficiency at variable speed.
- Q38 medium
Air-gap power Pg in an induction motor is approximately
💡 Explanation:Pg = T×ωs where ωs is synchronous angular speed.
- Q39 Past Paper · PPSC/FPSC/CSS medium
Efficiency of induction motor is highest near
💡 Explanation:Stray and copper losses dominate away from rated point.
- Q40 medium
Stator copper loss in equivalent circuit is represented by
💡 Explanation:R1 carries stator winding I²R independent of slip representation.
- Q41 hard
Referred rotor leakage reactance X2 in equivalent circuit is
💡 Explanation:Magnetic referral combines turns ratio with frequency referral.
- Q42 hard
No-load current in circle diagram is mainly
💡 Explanation:No-load point lies near top of current locus with low power factor.
- Q43 hard
Blocked-rotor point on circle diagram corresponds to
💡 Explanation:Short-circuit rotor test maps to standstill slip.
- Q44 medium
NEMA design A motors have
💡 Explanation:Design A suits applications needing high overload capability.
- Q45 Past Paper · PPSC/FPSC/CSS medium
IP23 enclosure typically indicates
💡 Explanation:IP23 suits indoor industrial environments with limited moisture.
- Q46 Past Paper · PPSC/FPSC/CSS hard
Double-cage rotor design improves
💡 Explanation:Outer high-resistance cage aids start; inner low-resistance cage carries running flux.
- Q47 hard
Deep-bar or double-cage rotors increase starting torque because
💡 Explanation:Skin effect raises bar resistance when rotor frequency is high at start.
- Q48 Past Paper · PPSC/FPSC/CSS medium
V/f control of induction motors maintains
💡 Explanation:Stator voltage is varied proportionally with frequency to avoid saturation or weak flux.
- Q49 medium
Pole-changing speed control alters
💡 Explanation:Ns = 120f/P; doubling poles halves synchronous speed.
- Q50 Past Paper · PPSC/FPSC/CSS hard
Dahlander winding arrangement allows
💡 Explanation:Dahlander connection switches pole groups for 1:2 speed ratio commonly.
- Q51 hard
Slip energy recovery (Scherbius/Kramer system) returns
💡 Explanation:Recovering sPg improves efficiency when operating with large slip.
- Q52 Past Paper · PPSC/FPSC/CSS medium
Rotor copper loss in an induction motor equals
💡 Explanation:Air-gap power Pg splits into rotor copper loss sPg and mechanical power (1-s)Pg.
- Q53 medium
If air-gap power is 10 kW and slip is 0.04, rotor copper loss is
💡 Explanation:Rotor I²R loss = sPg = 0.04 × 10000 = 400 W.
- Q54 Past Paper · PPSC/FPSC/CSS medium
Mechanical power developed by rotor equals
💡 Explanation:Fraction (1-s) of air-gap power converts to shaft power minus friction/windage.
- Q55 hard
The per-phase approximate equivalent circuit of an induction motor includes
💡 Explanation:Referred rotor impedance R2/s captures slip-dependent rotor behavior.
- Q56 Past Paper · PPSC/FPSC/CSS hard
In the equivalent circuit, R2/s represents
💡 Explanation:As s decreases at higher speed, R2/s rises, modeling reduced rotor current effects.
- Q57 hard
Circle diagram of an induction motor graphically shows
💡 Explanation:Locus of stator current with slip is circular for approximate equivalent circuit.
- Q58 Past Paper · PPSC/FPSC/CSS hard
From circle diagram, maximum torque corresponds to
💡 Explanation:Breakdown torque is read where tangent from origin meets the circle.
- Q59 medium
NEMA design B squirrel-cage motors typically have
💡 Explanation:Design B is general-purpose with moderate start characteristics.
- Q60 Past Paper · PPSC/FPSC/CSS hard
NEMA design D motors are characterized by
💡 Explanation:Design D uses high-resistance rotors for punch-press type loads.
- Q61 medium
IP55 motor enclosure rating means
💡 Explanation:First digit 5 = dust; second digit 5 = water jet protection per IEC 60529.
- Q62 easy
Induction motors are preferred for constant-speed industrial drives because
💡 Explanation:Squirrel-cage machines dominate pumps, fans, and conveyors.
- Q63 Past Paper · PPSC/FPSC/CSS easy
A 6-pole, 50 Hz motor has synchronous speed of
💡 Explanation:Ns = 120×50/6 = 1000 rpm.
- Q64 easy
If a 4-pole, 50 Hz motor runs at 1455 rpm, slip is
💡 Explanation:s = (1500-1455)/1500 = 45/1500 = 0.03.
- Q65 Past Paper · PPSC/FPSC/CSS easy
Frequency of rotor currents at standstill equals
💡 Explanation:At s=1, sf = 1×f = f.
- Q66 easy
As motor accelerates, rotor frequency
💡 Explanation:sf = s×f drops toward zero near full speed.
- Q67 Past Paper · PPSC/FPSC/CSS medium
Operating point of motor on torque-slip curve at rated load is
💡 Explanation:Normal loads lie on rising portion before maximum torque.
- Q68 medium
If load torque exceeds breakdown torque, the motor
💡 Explanation:Beyond pull-out torque, equilibrium is lost on unstable side.
- Q69 medium
NEMA design C motors provide
💡 Explanation:Design C uses higher rotor resistance than design B.
- Q70 medium
Service factor of 1.15 on a motor nameplate means
💡 Explanation:SF allows temporary overload without insulation damage.
- Q71 medium
IP44 enclosure offers protection against
💡 Explanation:Common for washdown or outdoor protected installations.
- Q72 easy
Totally enclosed fan-cooled (TEFC) motors dissipate heat by
💡 Explanation:TEFC prevents internal contamination while forcing air over casing.
- Q73 medium
Induction motors driving centrifugal pumps are often selected with
💡 Explanation:Pump torque rises with speed squared; power with speed cubed.
- Q74 medium
Conveyor belt applications may require motors with
💡 Explanation:High Tst prevents prolonged high-slip starting on heavy belts.
- Q75 medium
Crane hoist duty often uses wound-rotor motors because
💡 Explanation:Hoisting needs controlled torque and plugging/braking options.
- Q76 medium
Large compressor motors may use soft starters to
💡 Explanation:Soft start ramps voltage, reducing mechanical and electrical stress.
- Q77 easy
A 2-pole, 60 Hz motor synchronous speed is
💡 Explanation:Ns = 120×60/2 = 3600 rpm.
- Q78 easy
At 3% slip, rotor speed of 4-pole 50 Hz motor is approximately
💡 Explanation:Nr = Ns(1-s) = 1500×0.97 = 1455 rpm.
- Q79 hard
Negative slip in induction motor operation indicates
💡 Explanation:Super-synchronous operation returns power to supply.
- Q80 easy
In motoring mode, rotor always turns
💡 Explanation:Forward motoring requires 0 < s < 1 typically.
- Q81 medium
Torque is maximum on stable operating region when
💡 Explanation:Equilibrium at torque-slip and load-speed curve intersection defines speed.
- Q82 easy
Pull-out torque is also known as
💡 Explanation:Terminology interchangeably describes torque peak on curve.
- Q83 medium
Increasing supply voltage to a running induction motor generally
💡 Explanation:Higher V raises developed torque for same slip, reducing slip for same load.
- Q84 medium
Inserting too much rotor resistance at full speed causes
💡 Explanation:Resistance should be cut out as motor accelerates.
- Q85 medium
Thermal limit during repeated DOL starts is critical because
💡 Explanation:Limited starts per hour protect insulation from overtemperature.
- Q86 easy
Phase sequence reversal of three-phase supply to motor
💡 Explanation:Swapping any two line connections reverses rotation.
- Q87 medium
Single phasing during operation can
💡 Explanation:One open supply line causes severe heating in remaining phases.
- Q88 medium
Core loss in induction motor depends mainly on
💡 Explanation:Hysteresis and eddy losses in stator core follow flux level.
- Q89 medium
Friction and windage loss component increases approximately with
💡 Explanation:Mechanical losses rise with running speed near full load.
- Q90 medium
Power factor of induction motor at light load is usually
💡 Explanation:Magnetizing VARs keep PF poor until load current adds in-phase component.