Continuous Probability Distributions MCQs 2026

50 questions with detailed answers · 34 from past papers · 5 quiz batches available

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  1. Q1Past Paper · PPSC/FPSC/CSSmedium

    Normal approximation to binomial applies when

    1. An is very small
    2. Bp is exactly 0
    3. Cnp and n(1−p) are both sufficiently large (often ≥ 5 or 10)
    4. Dnp is near 0 only
    💡 Explanation:

    CLT/de Moivre–Laplace: large n with moderate p.

  2. Q2Past Paper · PPSC/FPSC/CSSeasy

    The standard normal distribution Z has

    1. Amean 0 and variance 1
    2. Bmean 1 and variance 0
    3. Cmean μ and variance σ
    4. Duniform on 0 to 1
    💡 Explanation:

    Z ~ N(0,1) is the reference normal.

  3. Q3Past Paper · PPSC/FPSC/CSSeasy

    If X ~ N(μ, σ²), the standardized variable Z equals

    1. AX / μ
    2. B(X − σ) / μ
    3. Cμ / σ
    4. D(X − μ) / σ
    💡 Explanation:

    Z-score measures deviation in standard deviation units.

  4. Q4Past Paper · PPSC/FPSC/CSSeasy

    For X ~ N(100, 25), σ equals

    1. A25
    2. B5
    3. C100
    4. D12.5
    💡 Explanation:

    σ = √25 = 5.

  5. Q5Past Paper · PPSC/FPSC/CSSeasy

    For X ~ N(100, 25), P(Z=0) corresponds to X equal to

    1. A100
    2. B25
    3. C5
    4. D0
    💡 Explanation:

    Z=0 when X=μ=100.

  6. Q6Past Paper · PPSC/FPSC/CSSeasy

    The normal curve is

    1. Abell-shaped and symmetric about μ
    2. Bskewed right always
    3. Cuniform
    4. Ddiscrete
    💡 Explanation:

    Normal PDF is symmetric unimodal bell curve.

  7. Q7Past Paper · PPSC/FPSC/CSSeasy

    Total area under the normal PDF equals

    1. A1
    2. B0.5
    3. C0
    4. Dμ
    💡 Explanation:

    Any valid PDF integrates to 1.

  8. Q8Past Paper · PPSC/FPSC/CSSeasy

    For standard normal Z, approximately 68% of probability lies within

    1. AZ = ±2
    2. BZ = ±3
    3. CZ = ±0.5
    4. DZ = ±1
    💡 Explanation:

    Empirical rule: ~68% within 1σ.

  9. Q9Past Paper · PPSC/FPSC/CSSeasy

    Approximately 95% of a normal distribution lies within

    1. Aμ ± 2σ
    2. Bμ ± 1σ
    3. Cμ ± 3σ
    4. Dμ only
    💡 Explanation:

    Empirical rule: ~95% within 2σ.

  10. Q10Past Paper · PPSC/FPSC/CSSeasy

    Approximately 99.7% lies within

    1. Aμ ± 3σ
    2. Bμ ± 2σ
    3. Cμ ± 1σ
    4. Dμ ± 4σ
    💡 Explanation:

    Empirical rule: nearly all within 3σ.

  11. Q11Past Paper · PPSC/FPSC/CSSeasy

    P(Z ≤ 0) for standard normal equals

    1. A0
    2. B0.5
    3. C1
    4. D0.68
    💡 Explanation:

    Symmetry: half below mean 0.

  12. Q12Past Paper · PPSC/FPSC/CSSmedium

    If X ~ N(50, 100), P(X < 60) uses Z equal to

    1. A1
    2. B0.5
    3. C2
    4. D10
    💡 Explanation:

    Z = (60−50)/10 = 1.

  13. Q13Past Paper · PPSC/FPSC/CSSmedium

    If X ~ N(200, 64), P(X > 216) uses Z equal to

    1. A1
    2. B4
    3. C2
    4. D16
    💡 Explanation:

    Z = (216−200)/8 = 2.

  14. Q14Past Paper · PPSC/FPSC/CSSmedium

    P(Z > 1.96) is approximately

    1. A0.05
    2. B0.5
    3. C0.025
    4. D0.975
    💡 Explanation:

    Upper 2.5% tail at ±1.96 for 95% central.

  15. Q15Past Paper · PPSC/FPSC/CSSmedium

    A 95% confidence interval for μ uses critical value approximately

    1. A±1.00 always
    2. B±1.96 for large samples (known σ)
    3. C±3.00 always
    4. D0
    💡 Explanation:

    Standard 95% two-tailed z critical is 1.96.

  16. Q16easy

    The normal PDF f(x) for X ~ N(μ,σ²) is highest at

    1. Ax = σ
    2. Bx = 0 always
    3. Cx = μ
    4. Dx = μ + σ
    💡 Explanation:

    Mode and mean coincide at μ for normal.

  17. Q17easy

    For normal X, median and mean are

    1. Amedian always above mean
    2. Bequal (both μ)
    3. Cmean always zero
    4. Dunequal always
    💡 Explanation:

    Symmetric distribution: mean = median = mode.

  18. Q18medium

    The uniform distribution on [a,b] has PDF

    1. Ab−a everywhere
    2. Ba constant > 1 always
    3. C1/(b−a) on [a,b] and 0 elsewhere
    4. Dzero on [a,b]
    💡 Explanation:

    Uniform density is constant over the interval.

  19. Q19Past Paper · PPSC/FPSC/CSSeasy

    Uniform on [0,10]: E(X) equals

    1. A10
    2. B2.5
    3. C0
    4. D5
    💡 Explanation:

    E(X)=(a+b)/2=5.

  20. Q20medium

    Uniform on [0,10]: Var(X) equals

    1. A25
    2. B100/12 ≈ 8.333
    3. C10
    4. D5
    💡 Explanation:

    Var=(b−a)²/12=100/12.

  21. Q21Past Paper · PPSC/FPSC/CSSmedium

    The exponential distribution is often used for

    1. Awaiting time until an event in a Poisson process
    2. Bcounting discrete successes in n trials
    3. Csampling without replacement
    4. Dhypergeometric counts
    💡 Explanation:

    Exponential models continuous waiting times with memoryless property.

  22. Q22medium

    Exponential(λ) has mean

    1. Aλ
    2. Bλ²
    3. C0
    4. D1/λ
    💡 Explanation:

    Mean waiting time is 1/λ.

  23. Q23hard

    The memoryless property holds for

    1. Anormal distribution
    2. Buniform only
    3. Cbinomial
    4. Dexponential (and geometric discrete counterpart)
    💡 Explanation:

    P(X>s+t|X>s)=P(X>t) for exponential.

  24. Q24Past Paper · PPSC/FPSC/CSSmedium

    For X ~ Bin(100, 0.5), normal approximation uses μ and σ² equal to

    1. A100 and 0.5
    2. B50 and 50
    3. C25 and 50
    4. D50 and 25
    💡 Explanation:

    μ=np=50; σ²=np(1−p)=25.

  25. Q25Past Paper · PPSC/FPSC/CSSmedium

    Continuity correction when approximating P(X=k) for discrete X uses

    1. AP(Y=k) exactly
    2. BP(Y<k) only without adjustment
    3. CP(k−0.5 < Y < k+0.5) for normal Y
    4. Dno correction ever
    💡 Explanation:

    Half-unit adjustment bridges discrete and continuous.

  26. Q26Past Paper · PPSC/FPSC/CSShard

    Bin(100,0.5): approximate P(X ≤ 45) with continuity correction uses

    1. AP(Y < 45.5) for Y ~ N(50,25)
    2. BP(Y < 45)
    3. CP(Y < 50)
    4. DP(Y < 40.5)
    💡 Explanation:

    P(X≤45) ≈ P(Y≤45.5) with correction.

  27. Q27hard

    For Bin(400, 0.25), normal approx: μ=100, σ=√75≈8.66. Z for X=110 uses

    1. A(110−100)/8.66 only
    2. B100/8.66
    3. C(110−100)/75
    4. D(110.5−100)/8.66 with continuity correction
    💡 Explanation:

    Use 110.5 for P(X≤110); σ=√(np(1−p)).

  28. Q28Past Paper · PPSC/FPSC/CSSmedium

    Poisson(λ) can be approximated by N(λ, λ) when

    1. Aλ = 0
    2. Bλ is large (e.g., λ ≥ 10)
    3. Cλ = 1 always
    4. Dλ < 1 only
    💡 Explanation:

    Large λ: Poisson approaches normal.

  29. Q29hard

    For Poisson(100), approximate P(X ≥ 115) uses normal with μ=100, σ=10 and

    1. Ano correction
    2. Bμ=50
    3. Ccontinuity correction at 114.5
    4. Dσ=100
    💡 Explanation:

    σ=√100=10; P(X≥115)≈P(Y>114.5).

  30. Q30Past Paper · PPSC/FPSC/CSSeasy

    The standard normal table typically gives

    1. AP(Z = z)
    2. BP(Z ≥ z) only without conversion
    3. CP(X = μ)
    4. DP(Z ≤ z)
    💡 Explanation:

    Tables tabulate left-tail cumulative probabilities.

  31. Q31Past Paper · PPSC/FPSC/CSSeasy

    To find P(Z > a), compute

    1. AP(Z ≤ a)
    2. B1 − P(Z ≤ a)
    3. CP(Z ≤ −a)
    4. DP(Z = a)
    💡 Explanation:

    Upper tail = 1 minus CDF.

  32. Q32Past Paper · PPSC/FPSC/CSSmedium

    P(−1.5 < Z < 1.5) equals

    1. AP(Z<1.5) + P(Z<−1.5)
    2. B1 − P(Z<1.5)
    3. CP(Z<1.5) − P(Z<−1.5)
    4. DP(Z<3)
    💡 Explanation:

    Interval probability = difference of CDF values.

  33. Q33Past Paper · PPSC/FPSC/CSSeasy

    By symmetry P(Z < −a) equals

    1. AP(Z > a)
    2. BP(Z < a)
    3. C0
    4. D1 − P(Z < 0)
    💡 Explanation:

    Standard normal is symmetric about 0.

  34. Q34hard

    If X ~ N(μ, σ²), then aX + b (a>0) is distributed as

    1. AN(μ, σ²)
    2. BN(aμ + b, a²σ²)
    3. CN(μ + b, σ²)
    4. Duniform
    💡 Explanation:

    Linear transform of normal is normal.

  35. Q35hard

    Sum of independent normal variables is

    1. Aalways standard normal
    2. Bbinomial
    3. CPoisson
    4. Dnormal with mean and variance added
    💡 Explanation:

    Normal family closed under independent sums.

  36. Q36Past Paper · PPSC/FPSC/CSSmedium

    For X ~ N(10, 4), P(8 < X < 12) uses Z bounds

    1. A0 and 1
    2. B−2 and +2
    3. C8 and 12
    4. D−1 and +1
    💡 Explanation:

    Z=(8−10)/2=−1 and (12−10)/2=+1.

  37. Q37Past Paper · PPSC/FPSC/CSSmedium

    P(|Z| > 2) is approximately

    1. A0.0228
    2. B0.9544
    3. C0.0456
    4. D0.5
    💡 Explanation:

    Two tails beyond ±2: ≈0.0456 total.

  38. Q38Past Paper · PPSC/FPSC/CSSmedium

    A test score X ~ N(70, 100). A score of 85 has Z-score

    1. A15
    2. B0.15
    3. C1.5
    4. D2.5
    💡 Explanation:

    Z=(85−70)/10=1.5.

  39. Q39Past Paper · PPSC/FPSC/CSSmedium

    Heights ~ N(170, 25). Proportion with height > 180 cm uses Z equal to

    1. A10
    2. B1
    3. C2
    4. D0.4
    💡 Explanation:

    Z=(180−170)/5=2.

  40. Q40Past Paper · PPSC/FPSC/CSSmedium

    Central Limit Theorem states that

    1. Aany small sample is exactly normal
    2. Bthe sample mean is approximately normal for large n (under conditions)
    3. Cpopulation must be normal always for any n
    4. Dvariance equals zero
    💡 Explanation:

    CLT: X̄ₙ ≈ N(μ, σ²/n) for large n.

  41. Q41Past Paper · PPSC/FPSC/CSSmedium

    For non-normal population with large n, distribution of X̄ is approximately

    1. ABin(n,p)
    2. BPoisson(λ)
    3. Cuniform only
    4. DN(μ, σ²/n)
    💡 Explanation:

    CLT applies regardless of population shape if n large.

  42. Q42Past Paper · PPSC/FPSC/CSSmedium

    Standard error of the mean is

    1. Aσ / √n
    2. Bσ × √n
    3. Cσ²
    4. Dσ / n
    💡 Explanation:

    SE = σ/√n shrinks with sample size.

  43. Q43Past Paper · PPSC/FPSC/CSSeasy

    If σ=20 and n=100, SE equals

    1. A20
    2. B0.2
    3. C200
    4. D2
    💡 Explanation:

    SE = 20/√100 = 2.

  44. Q44hard

    Normal probability plot is used to

    1. Acompute binomial coefficients
    2. Bassess whether data plausibly come from a normal distribution
    3. Cfind Poisson λ exactly
    4. Dprove independence
    💡 Explanation:

    QQ/plot checks normality assumption.

  45. Q45hard

    Using normal approx for Bin(20, 0.4), μ=8, σ≈2.19. P(X≥10) with correction approximates P(Y>9.5)

    1. Ausing Z=(9.5−8)/2.19
    2. BZ=(10−8)/2.19 without correction
    3. CZ=8/2.19
    4. DZ=0
    💡 Explanation:

    P(X≥10)=P(X>9.5) with correction → P(Y>9.5).

  46. Q46medium

    Skewed data with small n should

    1. Anot rely blindly on normal approximation
    2. Balways use Z=1.96
    3. Cignore continuity correction
    4. Dassume σ=0
    💡 Explanation:

    Small n or strong skew violates normal approx assumptions.

  47. Q47hard

    The PDF of N(μ,σ²) has inflection points at

    1. Aμ only
    2. Bμ ± σ
    3. Cμ ± 2σ
    4. D0 only
    💡 Explanation:

    Second derivative zero at one standard deviation from mean.

  48. Q48medium

    For continuous uniform on [a,b], P(X < c) for a < c < b equals

    1. Ac/b
    2. B(c − a)/(b − a)
    3. C1/(b−a)
    4. D0.5 always
    💡 Explanation:

    CDF of uniform is linear: (c−a)/(b−a).

  49. Q49hard

    The 90th percentile of Z is approximately

    1. A1.96
    2. B0.90
    3. C1.28
    4. D2.58
    💡 Explanation:

    P(Z≤1.28)≈0.90.

  50. Q50Past Paper · PPSC/FPSC/CSSmedium

    For manufacturing: bolt diameter ~ N(10, 0.01). σ=0.1 mm. P(diameter < 9.8) uses Z=

    1. A−0.2
    2. B−2
    3. C2
    4. D0
    💡 Explanation:

    Z=(9.8−10)/0.1=−2.