Control Systems MCQs 2026

70 questions with detailed answers · 46 from past papers · 7 quiz batches available

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Page 1 of 1 Questions 110 of 70
  1. Q1 Past Paper · PPSC/FPSC/NTS easy

    Magnitude in Bode plot for gain K is

    1. A K dB without log scaling incorrectly stated
    2. B 20 log10(K) dB horizontal line
    3. C log10 K without factor 20 only as incorrect variant
    4. D 20 log10(s) always without K
    💡 Explanation:

    Constant gain contributes flat magnitude in dB.

  2. Q2 Past Paper · PPSC/FPSC/NTS easy

    Pole at origin (integrator) contributes to Bode magnitude slope of

    1. A −20 dB/decade
    2. B +20 dB/decade
    3. C −40 dB/decade always for single pole at origin without other poles
    4. D 0 dB/decade always
    💡 Explanation:

    Each integrator adds −20 dB/decade slope.

  3. Q3 Past Paper · PPSC/FPSC/NTS easy

    Zero at origin (differentiator) contributes magnitude slope of

    1. A +20 dB/decade
    2. B −20 dB/decade for zero at origin—positive slope for differentiator
    3. C 0 dB/decade always
    4. D −6 dB/octave only without sign clarity—still +20 dB/decade
    💡 Explanation:

    Differentiator boosts high-frequency gain.

  4. Q4 Past Paper · PPSC/FPSC/NTS medium

    Corner frequency of first-order pole at 1/τ rad/s is

    1. A ω = τ only incorrectly
    2. B ω = 1/τ
    3. C ω = τ² only
    4. D ω = 0 always
    💡 Explanation:

    Break frequency where asymptote bends for real pole.

  5. Q5 Past Paper · PPSC/FPSC/NTS medium

    Phase of first-order lag at corner frequency is approximately

    1. A 0° always
    2. B −90° at corner exactly for asymptotic mid—approx −45° at ω=1/τ
    3. C −45°
    4. D +45° always
    💡 Explanation:

    At break frequency, first-order lag phase is −45°.

  6. Q6 Past Paper · PPSC/FPSC/NTS medium

    Gain crossover frequency is where

    1. A phase equals −180° only without magnitude condition for gain crossover definition
    2. B output equals input in time domain step only without frequency definition
    3. C open-loop magnitude equals 0 dB (unity gain)
    4. D PID integral time constant only
    💡 Explanation:

    ωgc is used with phase margin for stability assessment.

  7. Q7 Past Paper · PPSC/FPSC/NTS medium

    Phase crossover frequency is where

    1. A magnitude equals 0 dB only without phase −180° condition for phase crossover
    2. B system becomes type 2 always
    3. C open-loop phase equals −180°
    4. D derivative action is maximum always
    💡 Explanation:

    ωpc used with gain margin definition.

  8. Q8 Past Paper · PPSC/FPSC/NTS medium

    Gain margin is

    1. A phase increase in degrees at gain crossover only without gain definition
    2. B time delay only without dB definition
    3. C distance relay reach in ohms only
    4. D amount gain can increase before instability at phase crossover
    💡 Explanation:

    GM = −|G(jωpc)| in dB if stable; positive GM means stable.

  9. Q9 Past Paper · PPSC/FPSC/NTS medium

    Phase margin is

    1. A gain increase in dB at phase crossover only
    2. B steady-state error to ramp only without phase definition
    3. C motor slip at full load only
    4. D additional phase lag before −180° at gain crossover frequency
    💡 Explanation:

    PM indicates relative stability; typical design target 30°–60°.

  10. Q10 hard

    Resonant peak in closed-loop frequency response relates to

    1. A only DC gain without dynamics
    2. B damping ratio of dominant second-order poles
    3. C only transport delay only without resonance
    4. D only fuse cut-off current only
    💡 Explanation:

    Low damping gives high resonant peak Mr.

  11. Q11 hard

    Asymptotic Bode magnitude of second-order underdamped pair near ωn shows

    1. A flat 0 dB always without roll-off
    2. B −40 dB/decade slope far above ωn with possible peak near ωn
    3. C +40 dB/decade always above ωn without resonance possibility
    4. D undefined without zeros always
    💡 Explanation:

    Complex pole pair rolls off at −40 dB/decade at high ω.

  12. Q12 easy

    Decade on Bode frequency axis means

    1. A twofold change only
    2. B tenfold change in frequency
    3. C phase change of 45° only without frequency meaning
    4. D one period of oscillation only without factor ten
    💡 Explanation:

    Slope quoted as dB per decade of frequency.

  13. Q13 easy

    Octave corresponds to

    1. A doubling of frequency
    2. B tenfold frequency change which is decade not octave
    3. C tripling frequency always
    4. D zero frequency span only
    💡 Explanation:

    Some slopes expressed as dB/octave (6 dB/oct for pole).

  14. Q14 hard

    Minimum phase system Bode plot is uniquely determined by

    1. A phase curve alone without magnitude for minimum phase systems—magnitude alone suffices
    2. B time delay only without magnitude
    3. C magnitude curve alone
    4. D PID settings only without plant dynamics
    💡 Explanation:

    Hilbert transform relationship links magnitude and phase for minimum phase.

  15. Q15 Past Paper · PPSC/FPSC/NTS hard

    Transport delay adds phase

    1. A constant −90° at all frequencies always
    2. B −ωT radians linearly with frequency
    3. C +ωT always positive linear phase which is wrong sign for delay
    4. D zero phase always regardless of delay
    💡 Explanation:

    e^(−jωT) contributes −ωT phase lag.

  16. Q16 Past Paper · PPSC/FPSC/NTS medium

    Bode plot is useful for designing

    1. A only DC machine commutation timing only without frequency design
    2. B lead-lag compensators and assessing closed-loop bandwidth
    3. C only cable joint stress cones only without control design
    4. D only insulator fog profile only without controls
    💡 Explanation:

    Frequency shaping with compensators uses Bode insights.

  17. Q17 medium

    Slope of −20 dB/decade on Bode magnitude often indicates

    1. A one pole or combination equivalent to first-order roll-off
    2. B two integrators always without checking net order
    3. C zero at origin always without sign
    4. D pure time delay only without magnitude slope contribution like integrator
    💡 Explanation:

    Net pole excess of one gives −20 dB/decade asymptote.

  18. Q18 Past Paper · PPSC/FPSC/NTS easy

    Linear system is BIBO stable if

    1. A bounded input produces bounded output
    2. B any input produces zero output always
    3. C output always unbounded for step input always
    4. D poles need not be considered ever
    💡 Explanation:

    BIBO stability requires impulse response absolutely integrable for LTI.

  19. Q19 Past Paper · PPSC/FPSC/NTS easy

    For continuous-time LTI system, internal stability (asymptotic) requires poles to lie

    1. A strictly in left half of s-plane
    2. B on imaginary axis always without left half plane requirement for asymptotic stability
    3. C right half plane for stability incorrectly
    4. D at origin only always for all stable systems
    💡 Explanation:

    Re(s)<0 for all poles ensures decaying modes.

  20. Q20 Past Paper · PPSC/FPSC/NTS medium

    Marginally stable system has

    1. A all poles in RHP always as marginal definition incorrectly
    2. B only zeros on jω axis without pole condition
    3. C non-repeated poles on jω axis and none in RHP
    4. D always exponentially decaying modes only
    💡 Explanation:

    Undamped sustained oscillations occur for poles on imaginary axis.

  21. Q21 Past Paper · PPSC/FPSC/NTS hard

    Routh-Hurwitz criterion determines stability using

    1. A only Bode phase at DC only without polynomial test
    2. B only Nyquist plot drawing without polynomial
    3. C characteristic equation coefficients without finding roots explicitly
    4. D only motor nameplate data only
    💡 Explanation:

    R-H tabulation signs of first column indicate stability.

  22. Q22 Past Paper · PPSC/FPSC/NTS medium

    Tuning PID by Ziegler-Nichols ultimate gain method uses

    1. A only step response rise time without ultimate gain experiment incorrectly
    2. B only Bode zero placement without experiment incorrectly
    3. C only motor slip measurement incorrectly
    4. D critical gain Ku and oscillation period Pu at stability limit
    💡 Explanation:

    Closed-loop or open-loop Z-N rules based on Ku, Pu.

  23. Q23 Past Paper · PPSC/FPSC/NTS easy

    Increasing Kp too much can cause

    1. A guaranteed stability always incorrectly
    2. B zero overshoot always incorrectly
    3. C instability and excessive oscillations
    4. D elimination of noise always incorrectly
    💡 Explanation:

    Excessive proportional gain reduces margins.

  24. Q24 Past Paper · PPSC/FPSC/NTS medium

    Too much derivative gain amplifies

    1. A DC error only without high-frequency noise concern incorrectly
    2. B measurement noise
    3. C integral windup primarily incorrectly though D does not integrate noise same way
    4. D steady-state reference only incorrectly
    💡 Explanation:

    High Kd boosts high-frequency noise in error signal.

  25. Q25 hard

    PID in parallel form differs from ideal series form in

    1. A being unable to implement derivative ever incorrectly
    2. B requiring no tuning ever incorrectly
    3. C eliminating steady-state error without I incorrectly
    4. D algebraic arrangement but can be made equivalent with conversion
    💡 Explanation:

    Parallel and series PID forms relate by equivalent parameter conversion.

  26. Q26 hard

    Set-point weighting on PID separates

    1. A response to reference changes versus load disturbances
    2. B only fuse blowing from overload incorrectly
    3. C only distance zones incorrectly
    4. D only symmetrical sequences incorrectly
    💡 Explanation:

    Two-degree-of-freedom PID reduces overshoot to set-point steps.

  27. Q27 Past Paper · PPSC/FPSC/NTS medium

    Sampled-data PID implementation must consider

    1. A only analog Bode plot of continuous plant without sampling effects incorrectly
    2. B discretization, aliasing and integral approximation
    3. C infinite sampling rate without implementation constraints incorrectly
    4. D elimination of derivative always incorrectly as requirement
    💡 Explanation:

    Digital control uses difference equations and Tustin etc.

  28. Q28 Past Paper · PPSC/FPSC/NTS medium

    Derivative filter in practical PID limits

    1. A low-frequency gain to zero always incorrectly as filter purpose
    2. B high-frequency noise amplification by filtering D path
    3. C integral action entirely incorrectly
    4. D proportional gain to zero incorrectly
    💡 Explanation:

    First-order filter on derivative term is standard industrial practice.

  29. Q29 hard

    Feedforward control added to PID can

    1. A improve disturbance rejection for measurable disturbances
    2. B replace stability analysis always incorrectly
    3. C guarantee RHP poles always incorrectly
    4. D eliminate need for feedback entirely incorrectly
    💡 Explanation:

    Feedforward anticipates known disturbance effects.

  30. Q30 Past Paper · PPSC/FPSC/NTS medium

    Cascade control uses

    1. A only single P controller always incorrectly
    2. B only open-loop control without feedback incorrectly
    3. C inner fast loop and outer slow loop for improved disturbance rejection
    4. D only fuse in series without controllers incorrectly
    💡 Explanation:

    Inner loop handles fast dynamics; outer sets inner reference.

  31. Q31 Past Paper · PPSC/FPSC/NTS easy

    PI controller is commonly used when

    1. A derivative noise is desired to increase incorrectly
    2. B zero proportional gain is required incorrectly
    3. C system must be type 0 open-loop without closed-loop integrator effect incorrectly stated
    4. D steady-state accuracy needed without excessive noise sensitivity from D
    💡 Explanation:

    PI gives integral action for SSE with simpler tuning than full PID.

  32. Q32 medium

    Closed-loop bandwidth with PID tuning is often traded against

    1. A only cable charging current magnitude incorrectly
    2. B robustness margins and noise rejection
    3. C only tower sag at minimum temperature incorrectly
    4. D only SCR latching current only incorrectly
    💡 Explanation:

    Aggressive tuning raises bandwidth but may reduce PM/GM.

  33. Q33 Past Paper · PPSC/FPSC/NTS medium

    Integral windup occurs when

    1. A derivative term exceeds proportional always incorrectly as windup definition
    2. B actuator saturates while integrator continues accumulating error
    3. C system is always stable during saturation incorrectly
    4. D gain margin is infinite incorrectly
    💡 Explanation:

    Anti-windup schemes freeze or back-calculate integral during saturation.

  34. Q34 Past Paper · PPSC/FPSC/NTS easy

    Transfer function of a linear time-invariant system is defined as

    1. A ratio of time-domain outputs without transformation
    2. B ratio of Laplace transform of output to input with zero initial conditions
    3. C Fourier series coefficients only
    4. D PID tuning constants only
    💡 Explanation:

    G(s) = Y(s)/U(s) with zero initial conditions.

  35. Q35 Past Paper · PPSC/FPSC/NTS easy

    Poles of a transfer function are values of s where

    1. A numerator equals zero only
    2. B output is maximum always
    3. C denominator equals zero
    4. D gain margin is infinite always
    💡 Explanation:

    Poles determine natural modes and stability.

  36. Q36 Past Paper · PPSC/FPSC/NTS easy

    Zeros of a transfer function are values of s where

    1. A denominator equals zero
    2. B system is always unstable
    3. C phase margin is zero only
    4. D numerator equals zero
    💡 Explanation:

    Zeros affect magnitude and phase but not poles of closed loop alone.

  37. Q37 Past Paper · PPSC/FPSC/NTS easy

    Standard first-order system G(s) = K/(τs+1) has time constant

    1. A τ
    2. B K only
    3. C τ/K only
    4. D 1/K only without τ
    💡 Explanation:

    Time constant τ governs exponential response speed.

  38. Q38 Past Paper · PPSC/FPSC/NTS easy

    DC gain of transfer function G(s) is found by

    1. A s approaching infinity only always for DC gain definition—DC is s=0
    2. B only imaginary axis without s=0
    3. C only at resonant frequency always
    4. D evaluating G(s) at s = 0
    💡 Explanation:

    Steady-state gain for step input is G(0) if applicable.

  39. Q39 Past Paper · PPSC/FPSC/NTS medium

    Second-order underdamped system is characterized by

    1. A real distinct poles only always
    2. B complex conjugate poles with damping ratio ζ < 1
    3. C ζ greater than 1 always
    4. D no transient response ever
    💡 Explanation:

    Underdamped response oscillates with decay.

  40. Q40 Past Paper · PPSC/FPSC/NTS medium

    Natural frequency ωn of second-order system appears in standard form

    1. A s² + 2ζωn s + ωn²
    2. B s + ωn only without quadratic term
    3. C ωn² s + 1 only
    4. D PID derivative term only
    💡 Explanation:

    ωn is undamped natural frequency in rad/s.

  41. Q41 Past Paper · PPSC/FPSC/NTS easy

    Block diagram reduction uses rules for

    1. A series, parallel and feedback loop algebra
    2. B only Bode plotting without algebra
    3. C only symmetrical components only on AC faults
    4. D only fuse coordination curves only
    💡 Explanation:

    Transfer functions combine by multiplication, summation and feedback formula.

  42. Q42 Past Paper · PPSC/FPSC/NTS medium

    Closed-loop transfer function with unity feedback H=1 is

    1. A G/(1-G) always
    2. B 1/G always
    3. C G only without feedback effect
    4. D G/(1+G) where G is open-loop transfer function
    💡 Explanation:

    Negative unity feedback gives T = G/(1+G).

  43. Q43 Past Paper · PPSC/FPSC/NTS hard

    Type of a system indicates number of

    1. A zeros at origin only
    2. B delay elements counted twice always without definition
    3. C PID derivative paths only
    4. D integrators (poles at origin) in open-loop transfer function
    💡 Explanation:

    Type determines steady-state error to polynomial inputs.

  44. Q44 hard

    Steady-state error to step input for type 0 system with step input is

    1. A finite and generally non-zero unless gain is infinite
    2. B always zero for any type 0 without integrator—generally non-zero
    3. C always infinite for step on type 0—actually finite non-zero typically
    4. D undefined without Laplace
    💡 Explanation:

    Type 0 cannot track step without error unless loop gain → ∞.

  45. Q45 hard

    Lead compensator transfer function typically has

    1. A pole closer to origin than zero always for lead definition—lead has zero closer
    2. B equal zero and pole at origin only always
    3. C zero closer to origin than pole
    4. D no effect on phase
    💡 Explanation:

    Lead adds positive phase in mid frequencies.

  46. Q46 hard

    Lag compensator provides

    1. A positive phase boost at all frequencies without attenuation ever
    2. B elimination of all poles
    3. C high-frequency gain reduction and improved steady-state accuracy
    4. D only derivative action without lag pole-zero pair
    💡 Explanation:

    Lag increases low-frequency gain while attenuating highs.

  47. Q47 Past Paper · PPSC/FPSC/NTS hard

    Transport delay e^(-Ts) in transfer function causes

    1. A constant gain at all frequencies without phase effect ever
    2. B phase lag increasing linearly with frequency
    3. C elimination of stability issues always
    4. D infinite bandwidth always
    💡 Explanation:

    Pure delay reduces phase margin significantly.

  48. Q48 hard

    Impulse response of LTI system is inverse Laplace transform of

    1. A input only without system dynamics
    2. B PID output only without plant
    3. C distance relay impedance only
    4. D transfer function G(s)
    💡 Explanation:

    Impulse response characterizes system completely with LTI assumption.

  49. Q49 medium

    Convolution in time domain corresponds to

    1. A subtraction of transfer functions only
    2. B division of zeros only
    3. C multiplication in Laplace domain
    4. D Fourier series only without Laplace
    💡 Explanation:

    y(t)=u(t)*g(t) ⟺ Y(s)=U(s)G(s) with zero ICs.

  50. Q50 hard

    State-space model ẋ=Ax+Bu, y=Cx+Du relates to transfer function by

    1. A only Bode magnitude plot without matrices
    2. B G(s)=C(sI−A)⁻¹B+D
    3. C only per unit impedance conversion
    4. D only symmetrical sequence networks only
    💡 Explanation:

    State-space and transfer function are equivalent for LTI SISO/MIMO.

  51. Q51 hard

    Minimum phase system has all zeros in

    1. A left half of s-plane (or on jω axis)
    2. B right half plane always
    3. C origin only always
    4. D infinity only always without left half plane constraint
    💡 Explanation:

    Minimum phase systems have monotonic phase lag with frequency.

  52. Q52 Past Paper · PPSC/FPSC/NTS easy

    Bode plot displays

    1. A only time response without frequency content ever
    2. B only pole-zero map on complex plane without frequency axis as Bode definition
    3. C only Nyquist real axis only without magnitude and phase plots
    4. D magnitude in dB and phase versus frequency on logarithmic scale
    💡 Explanation:

    Bode diagrams aid frequency-domain analysis and controller design.

  53. Q53 Past Paper · PPSC/FPSC/NTS easy

    Derivative (D) action responds to

    1. A only steady-state error magnitude without rate sensitivity incorrectly
    2. B only DC offset always incorrectly
    3. C rate of change of error and adds damping
    4. D integral of error only incorrectly
    💡 Explanation:

    D anticipates error trend and reduces overshoot.

  54. Q54 hard

    Nyquist criterion uses

    1. A only step response overshoot percent only without Nyquist
    2. B only PID integral windup only without frequency encirclement
    3. C only symmetrical components only without Nyquist
    4. D open-loop frequency response encirclements of −1 point
    💡 Explanation:

    N = Z − P relates encirclements to closed-loop RHP zeros.

  55. Q55 medium

    Negative feedback reduces sensitivity of closed-loop gain to

    1. A increases sensitivity always at all frequencies without exception incorrectly as blanket statement
    2. B has no effect ever on sensitivity incorrectly
    3. C plant parameter variations at low frequencies often
    4. D only changes fuse rating without loop effect
    💡 Explanation:

    Feedback can desensitize system to certain perturbations.

  56. Q56 Past Paper · PPSC/FPSC/NTS medium

    Root locus shows

    1. A open-loop zeros only without pole motion
    2. B only Bode magnitude without pole paths
    3. C only steady-state error constants only without locus
    4. D closed-loop pole trajectories as gain varies from 0 to ∞
    💡 Explanation:

    Evans root locus guides gain selection for desired damping.

  57. Q57 Past Paper · PPSC/FPSC/NTS medium

    Adding a pole in forward path generally

    1. A always improves phase margin without exception incorrectly
    2. B has no effect on phase ever incorrectly
    3. C eliminates need for feedback incorrectly
    4. D degrades stability by adding phase lag
    💡 Explanation:

    Extra lag reduces phase margin unless compensated.

  58. Q58 Past Paper · PPSC/FPSC/NTS medium

    Adding a zero in forward path near crossover can

    1. A always destabilize without exception incorrectly
    2. B eliminate all dynamics incorrectly
    3. C improve phase margin
    4. D replace sensor entirely incorrectly
    💡 Explanation:

    Lead zero adds positive phase near crossover.

  59. Q59 Past Paper · PPSC/FPSC/NTS easy

    Stable closed-loop system with adequate gain and phase margins typically has

    1. A guaranteed zero steady-state error to all inputs without type consideration incorrectly as blanket
    2. B infinite bandwidth always incorrectly
    3. C poles in RHP always incorrectly
    4. D well-damped transient response without excessive oscillation
    💡 Explanation:

    Adequate margins correlate with acceptable transient behaviour.

  60. Q60 hard

    Limit cycle in nonlinear system refers to

    1. A exponential decay always in nonlinear system incorrectly for limit cycle definition
    2. B only linear system resonance at natural frequency only without nonlinearity requirement for limit cycle term usage
    3. C only fuse arcing only without control context though arcing is nonlinear oscillation colloquially
    4. D sustained oscillation amplitude determined by nonlinearity
    💡 Explanation:

    Nonlinearities can produce stable amplitude oscillations.

  61. Q61 hard

    Lyapunov stability analysis uses

    1. A only Bode plot asymptotes only without Lyapunov function
    2. B energy-like Lyapunov function with negative semi-definite derivative
    3. C only per unit conversion only without state function
    4. D only distance relay mho circle only without Lyapunov
    💡 Explanation:

    Lyapunov method proves stability without solving differential equation.

  62. Q62 medium

    Phase margin of 45° roughly corresponds to

    1. A unstable response always incorrectly
    2. B overdamped without oscillation always incorrectly for 45° PM typical correlation
    3. C moderately damped closed-loop step response
    4. D zero overshoot always incorrectly as blanket
    💡 Explanation:

    Rule of thumb links PM to damping of dominant second-order approximation.

  63. Q63 Past Paper · PPSC/FPSC/NTS medium

    Gain margin less than 0 dB indicates

    1. A closed-loop instability for unity feedback minimum-phase assumptions typically
    2. B guaranteed stability always incorrectly
    3. C infinite phase margin always incorrectly
    4. D zero steady-state error always incorrectly
    💡 Explanation:

    GM<0 means open-loop gain exceeds unity at −180° phase.

  64. Q64 hard

    Hurwitz polynomial has

    1. A roots on RHP always incorrectly
    2. B only real roots always as Hurwitz requirement incorrectly stated—complex allowed with negative real parts
    3. C all roots with negative real parts
    4. D roots at infinity only incorrectly
    💡 Explanation:

    Characteristic polynomial of stable LTI system is Hurwitz.

  65. Q65 Past Paper · PPSC/FPSC/NTS medium

    Delay in control loop tends to

    1. A reduce phase margin and can destabilize system
    2. B always improve damping without exception incorrectly
    3. C eliminate steady-state error without integrator incorrectly as delay effect
    4. D increase gain margin always incorrectly
    💡 Explanation:

    Time delay adds lag proportional to frequency.

  66. Q66 hard

    Conditional stability may occur when

    1. A system is stable only for limited gain range
    2. B system is stable for all gains always incorrectly
    3. C poles always in RHP incorrectly for conditional stability definition
    4. D only nonlinear systems without gain dependence incorrectly—linear can be conditionally stable with gain
    💡 Explanation:

    Some compensator configurations stable only between gain limits.

  67. Q67 Past Paper · PPSC/FPSC/NTS easy

    PID controller transfer function is

    1. A Gc(s) = Kp + Ki/s + Kd s
    2. B Kp only without integral or derivative paths
    3. C Ki s only incorrectly
    4. D Kd/s only incorrectly
    💡 Explanation:

    Proportional, integral and derivative actions combine in parallel form.

  68. Q68 Past Paper · PPSC/FPSC/NTS easy

    Proportional (P) action primarily

    1. A eliminates all steady-state error always without integrator incorrectly as blanket
    2. B reduces rise time and steady-state error partially but not entirely for type 0 plants typically
    3. C eliminates overshoot always incorrectly
    4. D provides infinite gain at DC always incorrectly—that is integral
    💡 Explanation:

    P gain improves response but often leaves SSE unless plant has integrator.

  69. Q69 Past Paper · PPSC/FPSC/NTS easy

    Integral (I) action eliminates

    1. A all measurement noise always without amplification concern incorrectly
    2. B need for sensor ever incorrectly
    3. C stability margins always improves without limit incorrectly
    4. D steady-state error to step input for stable closed-loop systems when properly applied
    💡 Explanation:

    Integrator provides infinite gain at DC tracking constant references.

  70. Q70 Past Paper · PPSC/FPSC/NTS medium

    Anti-windup methods include

    1. A stopping integration when output saturates or back-calculation
    2. B increasing integral gain during saturation incorrectly
    3. C removing proportional term always incorrectly
    4. D opening feedback loop permanently incorrectly
    💡 Explanation:

    Prevents large overshoot when leaving saturation.