Fluid Mechanics and Hydraulic Machines MCQs 2026
80 questions with detailed answers · 28 from past papers · 8 quiz batches available
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- Q1 Past Paper · PPSC/FPSC/NTS medium
Torricelli theorem gives exit velocity from tank as
💡 Explanation:Ideal Torricelli: V = √(2gh) from energy balance with free surface.
- Q2 hard
Coefficient of velocity Cv for orifice is ratio of
💡 Explanation:Cv accounts for vena contracta and velocity reduction.
- Q3 hard
Coefficient of contraction Cc is ratio of
💡 Explanation:Cc < 1 due to jet contraction downstream of sharp orifice.
- Q4 Past Paper · PPSC/FPSC/NTS hard
Cd for orifice equals approximately
💡 Explanation:Discharge coefficient combines velocity and contraction effects.
- Q5 medium
Blower differs from compressor in that blower provides
💡 Explanation:Fans and blowers handle large volumes at low Δp; compressors higher ratio.
- Q6 medium
Axial flow pump is preferred when
💡 Explanation:Propeller-type impeller for irrigation and cooling water circulation.
- Q7 Past Paper · PPSC/FPSC/NTS easy
Foot valve on pump suction line prevents
💡 Explanation:One-way valve keeps suction line filled with liquid.
- Q8 easy
Priming of centrifugal pump is necessary because
💡 Explanation:Without liquid, impeller cannot create sufficient vacuum to lift air.
- Q9 easy
Differential manometer connected across venturi throat and inlet measures
💡 Explanation:Manometer deflection with ρ and g gives Δp for venturi/orifice flow equation.
- Q10 easy
Kinematic viscosity is defined as
💡 Explanation:ν = μ/ρ; unit m²/s (Stokes in CGS).
- Q11 medium
For laminar flow in a circular pipe, velocity profile is
💡 Explanation:Hagen-Poiseuille flow gives u = umax(1 − r²/R²) parabolic profile.
- Q12 Past Paper · PPSC/FPSC/NTS easy
Turbulent flow in pipes is characterized by
💡 Explanation:Turbulence has random velocity fluctuations enhancing mixing and wall shear.
- Q13 medium
Darcy-Weisbach equation gives
💡 Explanation:hf = f(L/D)(V²/2g) where f is friction factor.
- Q14 hard
Friction factor for smooth pipes in turbulent region can be estimated by
💡 Explanation:Blasius f = 0.316/Re^0.25 for smooth turbulent pipe flow in moderate Re range.
- Q15 Past Paper · PPSC/FPSC/NTS medium
Moody diagram relates friction factor to
💡 Explanation:Moody chart plots f vs Re for various ε/D values.
- Q16 easy
Minor losses in pipe systems are caused by
💡 Explanation:K-factor losses h = KV²/2g at fittings add to friction losses.
- Q17 medium
NPSH available must exceed NPSH required to avoid
💡 Explanation:Insufficient suction head causes vapor bubbles forming and collapsing in the impeller.
- Q18 Past Paper · PPSC/FPSC/NTS medium
Cavitation in pumps is indicated by
💡 Explanation:Vapor bubble collapse damages metal and reduces performance.
- Q19 hard
Specific speed of a centrifugal pump indicates
💡 Explanation:Ns classifies pump as radial, mixed or axial flow based on N, Q, H.
- Q20 medium
Multistage centrifugal pumps are used when
💡 Explanation:Stages in series add heads for boiler feed and high-rise water supply.
- Q21 Past Paper · PPSC/FPSC/NTS medium
Reciprocating pump delivers
💡 Explanation:Positive displacement gives high pressure capability with pulsating discharge.
- Q22 easy
Gear pump belongs to category of
💡 Explanation:Intermeshing gears trap and transfer fixed volume of fluid each revolution.
- Q23 medium
Francis turbine is classified as
💡 Explanation:Francis runner has radial inlet and axial outlet; pressure drop occurs in runner passages.
- Q24 Past Paper · PPSC/FPSC/NTS medium
Kaplan turbine is suitable for
💡 Explanation:Adjustable-blade propeller-type turbine for low head hydro sites.
- Q25 medium
Draft tube in reaction turbines serves to
💡 Explanation:Diffuser converts outlet velocity head to pressure below atmospheric at runner exit.
- Q26 medium
Hydraulic grade line (HGL) represents
💡 Explanation:HGL = z + p/(ρg); lies below EGL by velocity head V²/2g.
- Q27 Past Paper · PPSC/FPSC/NTS medium
Energy grade line (EGL) includes
💡 Explanation:EGL = HGL + V²/2g represents total mechanical energy per unit weight.
- Q28 easy
Pascal law in fluid statics states
💡 Explanation:Foundation of hydraulic jacks and force multiplication in enclosed fluids.
- Q29 Past Paper · PPSC/FPSC/NTS easy
Hydrostatic pressure at depth h in liquid is
💡 Explanation:Pressure increases linearly with depth in incompressible static fluid.
- Q30 easy
Buoyant force on submerged body equals
💡 Explanation:Archimedes principle: Fb = ρgVdisplaced.
- Q31 medium
Metacentric height GM positive indicates
💡 Explanation:Positive GM gives restoring couple when vessel heels.
- Q32 Past Paper · PPSC/FPSC/NTS medium
Capillary rise in small tube is due to
💡 Explanation:Jurin height h = 2σ cos θ / (ρgr).
- Q33 easy
Newton law of viscosity states shear stress is proportional to
💡 Explanation:τ = μ du/dy for Newtonian fluids.
- Q34 medium
Non-Newtonian fluid example is
💡 Explanation:Non-Newtonian fluids have variable apparent viscosity with shear rate.
- Q35 easy
Steady flow means
💡 Explanation:Steady: partial derivatives with respect to time are zero at a fixed point.
- Q36 Past Paper · PPSC/FPSC/NTS medium
Uniform flow in open channel implies
💡 Explanation:Uniform: cross-section properties unchanged with distance at steady state.
- Q37 easy
Streamline is a line
💡 Explanation:In steady flow streamlines coincide with particle paths.
- Q38 medium
Path line of fluid particle is
💡 Explanation:Path line shows history of single particle motion.
- Q39 Past Paper · PPSC/FPSC/NTS medium
Streak line is
💡 Explanation:Streak line is what dye visualization shows in flow.
- Q40 hard
Euler equation along streamline for inviscid flow relates
💡 Explanation:dp/ρ + V dV + g dz = 0 for steady inviscid flow.
- Q41 hard
Navier-Stokes equations include
💡 Explanation:NS equations add viscous diffusion to Euler momentum equation.
- Q42 Past Paper · PPSC/FPSC/NTS medium
Transition from laminar to turbulent pipe flow depends on
💡 Explanation:Re > 4000 typically turbulent; roughness and disturbances affect transition.
- Q43 medium
Hydraulic jump energy loss appears as
💡 Explanation:Jump converts kinetic energy of supercritical flow to internal energy.
- Q44 Past Paper · PPSC/FPSC/NTS easy
Bernoulli equation for steady incompressible flow along a streamline states that
💡 Explanation:Bernoulli: p/ρ + V²/2 + gz = constant for ideal steady flow without shaft work or losses.
- Q45 easy
Continuity equation for incompressible flow in a pipe is expressed as
💡 Explanation:Mass conservation gives discharge Q = AV constant for incompressible flow.
- Q46 easy
Reynolds number Re is defined as
💡 Explanation:Re = inertial forces / viscous forces; Re = ρVD/μ for internal pipe flow.
- Q47 Past Paper · PPSC/FPSC/NTS easy
Dynamic viscosity unit in SI is
💡 Explanation:Dynamic viscosity μ has SI unit Pa·s; kinematic viscosity ν = μ/ρ in m²/s.
- Q48 easy
Flow in a smooth pipe is generally laminar when Reynolds number is below
💡 Explanation:Critical Re for pipe flow is about 2300; above 4000 flow is usually fully turbulent.
- Q49 medium
Boundary layer thickness increases along a flat plate because
💡 Explanation:Growing boundary layer results from momentum transfer from free stream toward the wall.
- Q50 Past Paper · PPSC/FPSC/NTS easy
Centrifugal pump imparts energy to fluid mainly by
💡 Explanation:Impeller raises velocity; volute/diffuser converts velocity head to pressure head.
- Q51 medium
Pelton wheel is an example of
💡 Explanation:Pelton uses high-velocity jets striking buckets; pressure drop occurs mainly in the nozzle.
- Q52 hard
Hydraulic ram utilizes
💡 Explanation:Ram uses kinetic energy of flowing water and valve closure shock to lift water.
- Q53 Past Paper · PPSC/FPSC/NTS easy
Simple U-tube manometer measures
💡 Explanation:Δp = ρgh for manometer fluid column height h.
- Q54 easy
Venturi meter measures flow rate based on
💡 Explanation:Bernoulli effect: throat velocity increases and pressure drops; Δp relates to Q.
- Q55 Past Paper · PPSC/FPSC/NTS medium
Orifice meter causes greater permanent pressure loss than venturi because
💡 Explanation:Sudden contraction and lack of diffuser cause irrecoverable head loss in orifice.
- Q56 Past Paper · PPSC/FPSC/NTS hard
Stokes law gives drag on small sphere as
💡 Explanation:Valid for Re < 1; used in viscometry and sedimentation.
- Q57 medium
Terminal velocity of falling particle occurs when
💡 Explanation:Equilibrium of forces gives constant maximum settling speed.
- Q58 medium
Pitot tube measures
💡 Explanation:From stagnation and static pressure, V = √(2Δp/ρ).
- Q59 Past Paper · PPSC/FPSC/NTS medium
Coefficient of discharge for venturi is typically
💡 Explanation:Gradual area change gives lower separation and Cd closer to unity.
- Q60 easy
Rotameter measures flow using
💡 Explanation:Variable area meter: float rises until annular area balances drag and weight.
- Q61 hard
Weir flow measurement for rectangular sharp-crested weir varies discharge approximately as
💡 Explanation:Francis formula Q = (2/3)Cdb√(2g)H^(3/2) for rectangular weir.
- Q62 Past Paper · PPSC/FPSC/NTS medium
Chezy and Manning formulas estimate
💡 Explanation:Open channel uniform flow based on hydraulic radius and slope.
- Q63 easy
Hydraulic radius R is defined as
💡 Explanation:R = A/P used in open channel and pipe flow calculations.
- Q64 medium
Froude number characterizes
💡 Explanation:Fr = V/√(gL); Fr = 1 is critical flow.
- Q65 Past Paper · PPSC/FPSC/NTS hard
Critical depth in rectangular channel occurs when
💡 Explanation:At critical depth specific energy is minimum for given discharge.
- Q66 medium
Hydraulic jump occurs in
💡 Explanation:Rapid increase in depth dissipates energy with turbulence.
- Q67 easy
Surface tension σ has unit
💡 Explanation:Surface tension is force per unit length acting at liquid interface.
- Q68 Past Paper · PPSC/FPSC/NTS medium
Vapor pressure of liquid is important in pumps because
💡 Explanation:When local pressure drops below vapor pressure, cavitation begins.
- Q69 hard
Head developed by centrifugal pump for given impeller speed and diameter is independent of
💡 Explanation:Same pump develops same head in meters; pressure rise Δp = ρgH depends on density.
- Q70 Past Paper · PPSC/FPSC/NTS medium
Affinity laws for pumps state flow rate varies with speed as
💡 Explanation:Pump laws: Q ∝ N, H ∝ N², Power ∝ N³ for same pump.
- Q71 medium
System curve for pipe network intersects pump curve at
💡 Explanation:Intersection gives operating Q and H where pump and system losses balance.
- Q72 hard
Water hammer pressure surge depends on
💡 Explanation:Δp = ρaΔV for rapid valve closure; a is acoustic wave speed in liquid.
- Q73 Past Paper · PPSC/FPSC/NTS medium
Surge tank in hydro penstock reduces
💡 Explanation:Tank absorbs transient flow variations protecting conduit from excessive pressure.
- Q74 medium
Impulse turbine runner operates in
💡 Explanation:Jet expands to atmospheric; buckets deflect water on impulse principle.
- Q75 hard
Degree of reaction for turbine is ratio of
💡 Explanation:R = (h1−h2)/(h1−h3) indicates fraction of energy converted in runner.
- Q76 Past Paper · PPSC/FPSC/NTS hard
Cavitation parameter σ for turbines relates to
💡 Explanation:Adequate sigma prevents turbine cavitation at runner outlet.
- Q77 medium
Hydraulic efficiency of turbine is
💡 Explanation:ηh accounts for hydraulic losses in turbine passages.
- Q78 medium
Inverted U-tube manometer is used for
💡 Explanation:Prevents manometer liquid from entering gas lines; suited for low Δp.
- Q79 Past Paper · PPSC/FPSC/NTS easy
Barometer measures
💡 Explanation:Mercury barometer column height corresponds to atmospheric pressure.
- Q80 easy
Gauge pressure equals
💡 Explanation:pgauge = pabs − patm; vacuum is below atmospheric.