Fluid Mechanics and Hydraulic Machines MCQs 2026

80 questions with detailed answers · 28 from past papers · 8 quiz batches available

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Page 1 of 1 Questions 110 of 80
  1. Q1 Past Paper · PPSC/FPSC/NTS medium

    Torricelli theorem gives exit velocity from tank as

    1. A √(gh/2)
    2. B 2gh without root
    3. C zero if orifice is sharp
    4. D √(2gh)
    💡 Explanation:

    Ideal Torricelli: V = √(2gh) from energy balance with free surface.

  2. Q2 hard

    Coefficient of velocity Cv for orifice is ratio of

    1. A actual jet velocity to ideal velocity
    2. B actual discharge to ideal area velocity product
    3. C pressure to density
    4. D head loss to diameter
    💡 Explanation:

    Cv accounts for vena contracta and velocity reduction.

  3. Q3 hard

    Coefficient of contraction Cc is ratio of

    1. A pipe area to orifice
    2. B vena contracta area to orifice area
    3. C velocity to discharge
    4. D Re to friction factor
    💡 Explanation:

    Cc < 1 due to jet contraction downstream of sharp orifice.

  4. Q4 Past Paper · PPSC/FPSC/NTS hard

    Cd for orifice equals approximately

    1. A Cv times Cc
    2. B Cv divided by Cc
    3. C Cv plus Cc
    4. D 1 always
    💡 Explanation:

    Discharge coefficient combines velocity and contraction effects.

  5. Q5 medium

    Blower differs from compressor in that blower provides

    1. A very high pressure ratio like multistage compressor
    2. B relatively small pressure rise at high volume flow
    3. C only vacuum suction
    4. D liquid pumping
    💡 Explanation:

    Fans and blowers handle large volumes at low Δp; compressors higher ratio.

  6. Q6 medium

    Axial flow pump is preferred when

    1. A large discharge at low head is required
    2. B very high head low flow
    3. C handling highly viscous paste
    4. D metering precise microliters
    💡 Explanation:

    Propeller-type impeller for irrigation and cooling water circulation.

  7. Q7 Past Paper · PPSC/FPSC/NTS easy

    Foot valve on pump suction line prevents

    1. A cavitation entirely always
    2. B reverse rotation of motor
    3. C drainage of pipe and loss of prime when pump stops
    4. D increase in NPSHr
    💡 Explanation:

    One-way valve keeps suction line filled with liquid.

  8. Q8 easy

    Priming of centrifugal pump is necessary because

    1. A centrifugal pump cannot handle air and must be filled with liquid
    2. B it increases impeller diameter
    3. C it reduces NPSHa
    4. D it converts reciprocating to rotary motion
    💡 Explanation:

    Without liquid, impeller cannot create sufficient vacuum to lift air.

  9. Q9 easy

    Differential manometer connected across venturi throat and inlet measures

    1. A absolute atmospheric pressure only
    2. B pressure difference used to calculate flow rate
    3. C fluid viscosity directly without formula
    4. D turbine shaft power
    💡 Explanation:

    Manometer deflection with ρ and g gives Δp for venturi/orifice flow equation.

  10. Q10 easy

    Kinematic viscosity is defined as

    1. A dynamic viscosity divided by density
    2. B density times dynamic viscosity
    3. C pressure divided by velocity
    4. D Re times diameter
    💡 Explanation:

    ν = μ/ρ; unit m²/s (Stokes in CGS).

  11. Q11 medium

    For laminar flow in a circular pipe, velocity profile is

    1. A parabolic with maximum at center
    2. B flat plug flow always
    3. C linear from wall to center
    4. D zero everywhere
    💡 Explanation:

    Hagen-Poiseuille flow gives u = umax(1 − r²/R²) parabolic profile.

  12. Q12 Past Paper · PPSC/FPSC/NTS easy

    Turbulent flow in pipes is characterized by

    1. A irregular fluctuations and mixing
    2. B smooth layered streamlines only
    3. C Re below 100 always
    4. D zero wall shear
    💡 Explanation:

    Turbulence has random velocity fluctuations enhancing mixing and wall shear.

  13. Q13 medium

    Darcy-Weisbach equation gives

    1. A pump power directly
    2. B Reynolds number value
    3. C head loss due to friction in pipes
    4. D surface tension force
    💡 Explanation:

    hf = f(L/D)(V²/2g) where f is friction factor.

  14. Q14 hard

    Friction factor for smooth pipes in turbulent region can be estimated by

    1. A Archimedes principle only
    2. B Blasius or Colebrook equation
    3. C Pascal law only
    4. D Carnot efficiency formula
    💡 Explanation:

    Blasius f = 0.316/Re^0.25 for smooth turbulent pipe flow in moderate Re range.

  15. Q15 Past Paper · PPSC/FPSC/NTS medium

    Moody diagram relates friction factor to

    1. A Reynolds number and relative roughness
    2. B only pipe length
    3. C only fluid color
    4. D compressibility only
    💡 Explanation:

    Moody chart plots f vs Re for various ε/D values.

  16. Q16 easy

    Minor losses in pipe systems are caused by

    1. A only straight pipe friction
    2. B gravity alone
    3. C fluid density only
    4. D fittings, bends, valves and sudden expansions
    💡 Explanation:

    K-factor losses h = KV²/2g at fittings add to friction losses.

  17. Q17 medium

    NPSH available must exceed NPSH required to avoid

    1. A laminar flow only
    2. B increased viscosity
    3. C cavitation in pumps
    4. D positive gauge pressure always
    💡 Explanation:

    Insufficient suction head causes vapor bubbles forming and collapsing in the impeller.

  18. Q18 Past Paper · PPSC/FPSC/NTS medium

    Cavitation in pumps is indicated by

    1. A silent smooth operation
    2. B noise, vibration and pitting of impeller
    3. C increased NPSHa always
    4. D decreased temperature only
    💡 Explanation:

    Vapor bubble collapse damages metal and reduces performance.

  19. Q19 hard

    Specific speed of a centrifugal pump indicates

    1. A only electrical power factor
    2. B type and shape suitable for given Q and H
    3. C oil viscosity grade
    4. D steam pressure only
    💡 Explanation:

    Ns classifies pump as radial, mixed or axial flow based on N, Q, H.

  20. Q20 medium

    Multistage centrifugal pumps are used when

    1. A only very low head large flow
    2. B handling pure solids only
    3. C vacuum generation only
    4. D high head is required at moderate flow
    💡 Explanation:

    Stages in series add heads for boiler feed and high-rise water supply.

  21. Q21 Past Paper · PPSC/FPSC/NTS medium

    Reciprocating pump delivers

    1. A only low pressure large flow always
    2. B no pulsating flow ever
    3. C nearly constant volume per stroke at high pressure
    4. D only gases
    💡 Explanation:

    Positive displacement gives high pressure capability with pulsating discharge.

  22. Q22 easy

    Gear pump belongs to category of

    1. A dynamic radial flow pumps
    2. B positive displacement pumps
    3. C gravity pumps only
    4. D turbines
    💡 Explanation:

    Intermeshing gears trap and transfer fixed volume of fluid each revolution.

  23. Q23 medium

    Francis turbine is classified as

    1. A pure impulse only
    2. B wind turbine
    3. C mixed-flow reaction turbine
    4. D reciprocating engine
    💡 Explanation:

    Francis runner has radial inlet and axial outlet; pressure drop occurs in runner passages.

  24. Q24 Past Paper · PPSC/FPSC/NTS medium

    Kaplan turbine is suitable for

    1. A very high head small flow
    2. B zero water availability
    3. C compressed air only
    4. D low head and large discharge
    💡 Explanation:

    Adjustable-blade propeller-type turbine for low head hydro sites.

  25. Q25 medium

    Draft tube in reaction turbines serves to

    1. A recover kinetic energy at outlet and maintain suction head
    2. B increase frictional loss only
    3. C heat the water
    4. D measure flow rate only
    💡 Explanation:

    Diffuser converts outlet velocity head to pressure below atmospheric at runner exit.

  26. Q26 medium

    Hydraulic grade line (HGL) represents

    1. A velocity head only
    2. B piezometric head at each point along pipe
    3. C temperature profile
    4. D Re along pipe
    💡 Explanation:

    HGL = z + p/(ρg); lies below EGL by velocity head V²/2g.

  27. Q27 Past Paper · PPSC/FPSC/NTS medium

    Energy grade line (EGL) includes

    1. A only static pressure
    2. B only elevation
    3. C friction factor value
    4. D velocity head in addition to piezometric head
    💡 Explanation:

    EGL = HGL + V²/2g represents total mechanical energy per unit weight.

  28. Q28 easy

    Pascal law in fluid statics states

    1. A pressure at a point is transmitted equally in all directions
    2. B pressure increases with velocity always
    3. C fluid always flows uphill
    4. D density is constant in gases only
    💡 Explanation:

    Foundation of hydraulic jacks and force multiplication in enclosed fluids.

  29. Q29 Past Paper · PPSC/FPSC/NTS easy

    Hydrostatic pressure at depth h in liquid is

    1. A ρg/h
    2. B h/ρg
    3. C ρgh
    4. D zero at all depths
    💡 Explanation:

    Pressure increases linearly with depth in incompressible static fluid.

  30. Q30 easy

    Buoyant force on submerged body equals

    1. A weight of displaced fluid
    2. B weight of body always
    3. C half displaced volume only
    4. D surface tension force
    💡 Explanation:

    Archimedes principle: Fb = ρgVdisplaced.

  31. Q31 medium

    Metacentric height GM positive indicates

    1. A always capsizing
    2. B neutral stability only
    3. C stable floating equilibrium
    4. D no restoring moment
    💡 Explanation:

    Positive GM gives restoring couple when vessel heels.

  32. Q32 Past Paper · PPSC/FPSC/NTS medium

    Capillary rise in small tube is due to

    1. A surface tension and wetting
    2. B only gravity increase
    3. C turbulent mixing
    4. D compressibility
    💡 Explanation:

    Jurin height h = 2σ cos θ / (ρgr).

  33. Q33 easy

    Newton law of viscosity states shear stress is proportional to

    1. A rate of strain (velocity gradient)
    2. B pressure only
    3. C absolute temperature only
    4. D density squared
    💡 Explanation:

    τ = μ du/dy for Newtonian fluids.

  34. Q34 medium

    Non-Newtonian fluid example is

    1. A blood or polymer solution
    2. B water at 20 °C
    3. C air at low speed
    4. D mercury
    💡 Explanation:

    Non-Newtonian fluids have variable apparent viscosity with shear rate.

  35. Q35 easy

    Steady flow means

    1. A uniform flow at all cross sections always
    2. B zero velocity everywhere
    3. C Re is constant in time only at inlet
    4. D properties at a point do not change with time
    💡 Explanation:

    Steady: partial derivatives with respect to time are zero at a fixed point.

  36. Q36 Past Paper · PPSC/FPSC/NTS medium

    Uniform flow in open channel implies

    1. A only steady in time
    2. B always supercritical
    3. C always laminar
    4. D depth and velocity constant along channel length
    💡 Explanation:

    Uniform: cross-section properties unchanged with distance at steady state.

  37. Q37 easy

    Streamline is a line

    1. A tangent to velocity vector everywhere
    2. B perpendicular to flow always
    3. C along which pressure is zero
    4. D of constant temperature only
    💡 Explanation:

    In steady flow streamlines coincide with particle paths.

  38. Q38 medium

    Path line of fluid particle is

    1. A always straight line
    2. B actual trajectory traced by that particle
    3. C same as streak line always in unsteady flow
    4. D always parallel to wall
    💡 Explanation:

    Path line shows history of single particle motion.

  39. Q39 Past Paper · PPSC/FPSC/NTS medium

    Streak line is

    1. A instantaneous velocity direction only
    2. B constant pressure line
    3. C locus of particles passing through a common point
    4. D pipe centerline always
    💡 Explanation:

    Streak line is what dye visualization shows in flow.

  40. Q40 hard

    Euler equation along streamline for inviscid flow relates

    1. A shear stress to viscosity only
    2. B heat transfer to conductivity
    3. C pressure gradient to velocity and body force
    4. D mass to moles
    💡 Explanation:

    dp/ρ + V dV + g dz = 0 for steady inviscid flow.

  41. Q41 hard

    Navier-Stokes equations include

    1. A only hydrostatic terms
    2. B viscous stress terms in momentum balance
    3. C combustion chemistry
    4. D electromagnetic forces only
    💡 Explanation:

    NS equations add viscous diffusion to Euler momentum equation.

  42. Q42 Past Paper · PPSC/FPSC/NTS medium

    Transition from laminar to turbulent pipe flow depends on

    1. A pipe material color only
    2. B only pipe length
    3. C Reynolds number and disturbances
    4. D absolute pressure only
    💡 Explanation:

    Re > 4000 typically turbulent; roughness and disturbances affect transition.

  43. Q43 medium

    Hydraulic jump energy loss appears as

    1. A increased mechanical energy in flow
    2. B stored elastic energy
    3. C pump head gain
    4. D turbulence and heat dissipation
    💡 Explanation:

    Jump converts kinetic energy of supercritical flow to internal energy.

  44. Q44 Past Paper · PPSC/FPSC/NTS easy

    Bernoulli equation for steady incompressible flow along a streamline states that

    1. A velocity head alone is constant
    2. B pressure always increases with height
    3. C total head remains constant
    4. D flow rate changes with pipe diameter only
    💡 Explanation:

    Bernoulli: p/ρ + V²/2 + gz = constant for ideal steady flow without shaft work or losses.

  45. Q45 easy

    Continuity equation for incompressible flow in a pipe is expressed as

    1. A p1 = p2 always
    2. B A1V1 = A2V2
    3. C Q changes with viscosity
    4. D Re is constant everywhere
    💡 Explanation:

    Mass conservation gives discharge Q = AV constant for incompressible flow.

  46. Q46 easy

    Reynolds number Re is defined as

    1. A μVD/ρ
    2. B VD/g
    3. C p/ρV²
    4. D ρVD/μ
    💡 Explanation:

    Re = inertial forces / viscous forces; Re = ρVD/μ for internal pipe flow.

  47. Q47 Past Paper · PPSC/FPSC/NTS easy

    Dynamic viscosity unit in SI is

    1. A m²/s only
    2. B Pa·s (N·s/m²)
    3. C N/m only
    4. D kg/m only
    💡 Explanation:

    Dynamic viscosity μ has SI unit Pa·s; kinematic viscosity ν = μ/ρ in m²/s.

  48. Q48 easy

    Flow in a smooth pipe is generally laminar when Reynolds number is below

    1. A 4000
    2. B 10000
    3. C 500
    4. D 2300
    💡 Explanation:

    Critical Re for pipe flow is about 2300; above 4000 flow is usually fully turbulent.

  49. Q49 medium

    Boundary layer thickness increases along a flat plate because

    1. A pressure always decreases
    2. B density becomes zero
    3. C viscous effects diffuse momentum outward
    4. D Re decreases to zero
    💡 Explanation:

    Growing boundary layer results from momentum transfer from free stream toward the wall.

  50. Q50 Past Paper · PPSC/FPSC/NTS easy

    Centrifugal pump imparts energy to fluid mainly by

    1. A increasing kinetic energy then converting to pressure
    2. B heating the fluid only
    3. C decreasing angular momentum
    4. D compressing vapor
    💡 Explanation:

    Impeller raises velocity; volute/diffuser converts velocity head to pressure head.

  51. Q51 medium

    Pelton wheel is an example of

    1. A reaction turbine only
    2. B impulse turbine
    3. C positive displacement pump
    4. D reciprocating pump
    💡 Explanation:

    Pelton uses high-velocity jets striking buckets; pressure drop occurs mainly in the nozzle.

  52. Q52 hard

    Hydraulic ram utilizes

    1. A steam expansion only
    2. B water hammer effect to pump a portion of water to higher elevation
    3. C electromagnetic induction
    4. D centrifugal impeller only
    💡 Explanation:

    Ram uses kinetic energy of flowing water and valve closure shock to lift water.

  53. Q53 Past Paper · PPSC/FPSC/NTS easy

    Simple U-tube manometer measures

    1. A pressure difference as liquid column height difference
    2. B mass flow rate directly
    3. C Reynolds number
    4. D turbine power only
    💡 Explanation:

    Δp = ρgh for manometer fluid column height h.

  54. Q54 easy

    Venturi meter measures flow rate based on

    1. A temperature rise in throat
    2. B pressure difference between converging and throat sections
    3. C color change of fluid
    4. D magnetic field strength
    💡 Explanation:

    Bernoulli effect: throat velocity increases and pressure drops; Δp relates to Q.

  55. Q55 Past Paper · PPSC/FPSC/NTS medium

    Orifice meter causes greater permanent pressure loss than venturi because

    1. A it has a longer converging cone
    2. B it measures temperature instead
    3. C discharge coefficient is unity
    4. D no gradual recovery section after restriction
    💡 Explanation:

    Sudden contraction and lack of diffuser cause irrecoverable head loss in orifice.

  56. Q56 Past Paper · PPSC/FPSC/NTS hard

    Stokes law gives drag on small sphere as

    1. A FD independent of viscosity
    2. B FD proportional to V² only
    3. C FD = 3πμDV
    4. D FD zero in viscous flow
    💡 Explanation:

    Valid for Re < 1; used in viscometry and sedimentation.

  57. Q57 medium

    Terminal velocity of falling particle occurs when

    1. A acceleration is maximum
    2. B Re is infinite always
    3. C drag force equals net weight minus buoyancy
    4. D viscosity is zero
    💡 Explanation:

    Equilibrium of forces gives constant maximum settling speed.

  58. Q58 medium

    Pitot tube measures

    1. A static pressure only in all cases
    2. B mass of fluid
    3. C stagnation pressure to find local velocity
    4. D turbine efficiency
    💡 Explanation:

    From stagnation and static pressure, V = √(2Δp/ρ).

  59. Q59 Past Paper · PPSC/FPSC/NTS medium

    Coefficient of discharge for venturi is typically

    1. A zero always
    2. B higher than for sharp-edged orifice
    3. C lower than orifice always
    4. D exactly 1.0 always
    💡 Explanation:

    Gradual area change gives lower separation and Cd closer to unity.

  60. Q60 easy

    Rotameter measures flow using

    1. A electromagnetic induction only
    2. B orifice plate only
    3. C float equilibrium in tapered tube
    4. D thermocouple
    💡 Explanation:

    Variable area meter: float rises until annular area balances drag and weight.

  61. Q61 hard

    Weir flow measurement for rectangular sharp-crested weir varies discharge approximately as

    1. A H linearly only
    2. B H² only
    3. C H^(3/2)
    4. D independent of head
    💡 Explanation:

    Francis formula Q = (2/3)Cdb√(2g)H^(3/2) for rectangular weir.

  62. Q62 Past Paper · PPSC/FPSC/NTS medium

    Chezy and Manning formulas estimate

    1. A closed pipe laminar flow only
    2. B velocity or discharge in open channels
    3. C compressor performance
    4. D Rankine cycle efficiency
    💡 Explanation:

    Open channel uniform flow based on hydraulic radius and slope.

  63. Q63 easy

    Hydraulic radius R is defined as

    1. A perimeter divided by area
    2. B diameter squared
    3. C velocity times area
    4. D flow area divided by wetted perimeter
    💡 Explanation:

    R = A/P used in open channel and pipe flow calculations.

  64. Q64 medium

    Froude number characterizes

    1. A viscous to inertial forces only
    2. B Mach number in liquids
    3. C pump NPSH
    4. D relative importance of inertia to gravity in open channel flow
    💡 Explanation:

    Fr = V/√(gL); Fr = 1 is critical flow.

  65. Q65 Past Paper · PPSC/FPSC/NTS hard

    Critical depth in rectangular channel occurs when

    1. A Re equals 2300
    2. B flow is always subcritical
    3. C Froude number equals unity
    4. D depth is maximum always
    💡 Explanation:

    At critical depth specific energy is minimum for given discharge.

  66. Q66 medium

    Hydraulic jump occurs in

    1. A laminar to turbulent in pipe only
    2. B pump suction line only
    3. C closed valve only
    4. D supercritical to subcritical transition
    💡 Explanation:

    Rapid increase in depth dissipates energy with turbulence.

  67. Q67 easy

    Surface tension σ has unit

    1. A Pa·s
    2. B N/m
    3. C m²/s
    4. D kg/m³
    💡 Explanation:

    Surface tension is force per unit length acting at liquid interface.

  68. Q68 Past Paper · PPSC/FPSC/NTS medium

    Vapor pressure of liquid is important in pumps because

    1. A it increases pipe roughness
    2. B it eliminates friction loss
    3. C it raises NPSHa always
    4. D low pressure can cause boiling and cavitation
    💡 Explanation:

    When local pressure drops below vapor pressure, cavitation begins.

  69. Q69 hard

    Head developed by centrifugal pump for given impeller speed and diameter is independent of

    1. A fluid density
    2. B impeller diameter
    3. C rotational speed
    4. D impeller design
    💡 Explanation:

    Same pump develops same head in meters; pressure rise Δp = ρgH depends on density.

  70. Q70 Past Paper · PPSC/FPSC/NTS medium

    Affinity laws for pumps state flow rate varies with speed as

    1. A Q proportional to N²
    2. B Q proportional to N
    3. C Q independent of N
    4. D Q proportional to 1/N
    💡 Explanation:

    Pump laws: Q ∝ N, H ∝ N², Power ∝ N³ for same pump.

  71. Q71 medium

    System curve for pipe network intersects pump curve at

    1. A shutoff head only
    2. B maximum efficiency always
    3. C zero flow always
    4. D operating point
    💡 Explanation:

    Intersection gives operating Q and H where pump and system losses balance.

  72. Q72 hard

    Water hammer pressure surge depends on

    1. A only pipe color
    2. B only ambient temperature
    3. C Re only
    4. D wave speed and velocity change
    💡 Explanation:

    Δp = ρaΔV for rapid valve closure; a is acoustic wave speed in liquid.

  73. Q73 Past Paper · PPSC/FPSC/NTS medium

    Surge tank in hydro penstock reduces

    1. A turbine efficiency to zero
    2. B reservoir volume
    3. C net head permanently
    4. D water hammer pressure fluctuations
    💡 Explanation:

    Tank absorbs transient flow variations protecting conduit from excessive pressure.

  74. Q74 medium

    Impulse turbine runner operates in

    1. A high vacuum only inside blades always
    2. B pressurized sealed casing only
    3. C atmospheric pressure region
    4. D oil bath
    💡 Explanation:

    Jet expands to atmospheric; buckets deflect water on impulse principle.

  75. Q75 hard

    Degree of reaction for turbine is ratio of

    1. A enthalpy drop in rotor to total enthalpy drop
    2. B power to speed
    3. C inlet to outlet pressure only
    4. D torque to angular velocity only
    💡 Explanation:

    R = (h1−h2)/(h1−h3) indicates fraction of energy converted in runner.

  76. Q76 Past Paper · PPSC/FPSC/NTS hard

    Cavitation parameter σ for turbines relates to

    1. A only steam quality
    2. B NPSH and net head
    3. C fuel air ratio
    4. D COP of refrigerator
    💡 Explanation:

    Adequate sigma prevents turbine cavitation at runner outlet.

  77. Q77 medium

    Hydraulic efficiency of turbine is

    1. A water power output divided by energy supplied in flow
    2. B electrical output only without losses
    3. C volumetric efficiency of pump
    4. D boiler efficiency
    💡 Explanation:

    ηh accounts for hydraulic losses in turbine passages.

  78. Q78 medium

    Inverted U-tube manometer is used for

    1. A high vacuum in steam condenser only always
    2. B liquid flow in open channel only
    3. C measuring torque
    4. D measuring small pressure differences in gases
    💡 Explanation:

    Prevents manometer liquid from entering gas lines; suited for low Δp.

  79. Q79 Past Paper · PPSC/FPSC/NTS easy

    Barometer measures

    1. A gauge pressure in pipe always
    2. B dynamic pressure only
    3. C local atmospheric pressure
    4. D mass flow rate
    💡 Explanation:

    Mercury barometer column height corresponds to atmospheric pressure.

  80. Q80 easy

    Gauge pressure equals

    1. A absolute plus atmospheric
    2. B vacuum pressure always
    3. C twice absolute pressure
    4. D absolute pressure minus atmospheric pressure
    💡 Explanation:

    pgauge = pabs − patm; vacuum is below atmospheric.