Heat and Mass Transfer MCQs 2026

80 questions with detailed answers · 28 from past papers · 8 quiz batches available

📚 Mechanical Engineering📄 28 Past-Paper Qs✓ Free · No Login Needed
🎯 Mock Test

Read each question, think about the answer, then click Show Answer to reveal the correct option and explanation. Load 10 at a time so it stays manageable — perfect for one-topic study sessions on the bus or during a break.

Page 1 of 1Questions 110 of 80
  1. Q1easy

    Greenhouse effect analogy in heat transfer refers to

    1. AFick law only as greenhouse analogy primary
    2. Btransparent cover transmitting shortwave and blocking longwave radiation
    3. CDarcy law only
    4. DHooke law only
    💡 Explanation:

    Spectral radiation properties matter.

  2. Q2Past Paper · PPSC/FPSC/NTSmedium

    Solar collector efficiency involves

    1. Aabsorbed radiation minus losses by convection and radiation
    2. Bonly Fourier conduction in insulation as sole efficiency factor alone
    3. Conly bolt preload
    4. Donly torsion in shaft
    💡 Explanation:

    Optical absorption and thermal losses.

  3. Q3medium

    Cooling tower performance depends on

    1. Aonly conduction through concrete shell as performance primary alone
    2. Bonly nuclear fission
    3. Cevaporative heat and mass transfer between water and air
    4. Donly beam bending
    💡 Explanation:

    Wet bulb approach measures performance.

  4. Q4medium

    Distillation column separation relies on

    1. Adifference in volatility causing mass transfer between phases
    2. Bonly conduction through metal tray as separation mechanism primary alone
    3. Conly radiation between trays
    4. Donly centrifugal force as distillation mechanism
    💡 Explanation:

    Vapor-liquid equilibrium and staged contact.

  5. Q5Past Paper · PPSC/FPSC/NTSmedium

    Adsorption mass transfer at surface differs from absorption by

    1. Aboth identical always
    2. Baccumulation on surface vs penetration into bulk phase
    3. Cadsorption always in bulk only
    4. Dabsorption always surface only reversed always
    💡 Explanation:

    Adsorption is surface phenomenon.

  6. Q6hard

    Knudsen number important in mass transfer indicates

    1. Atransition between continuum and molecular flow regimes
    2. Bturbulent vs laminar heat transfer only as Knudsen meaning alone always
    3. Celastic vs plastic stress only
    4. Dsubsonic vs supersonic only as Knudsen
    💡 Explanation:

    Kn = λ/L.

  7. Q7medium

    Dryer design uses

    1. Aonly Rankine cycle analysis as dryer design primary tool alone
    2. Bheat and mass transfer to remove moisture from solids
    3. Conly Mohr circle
    4. Donly belt friction
    💡 Explanation:

    Convective drying coupled with diffusion in material.

  8. Q8Past Paper · PPSC/FPSC/NTSmedium

    Humidification involves simultaneous

    1. Aheat and mass transfer at air-water interface
    2. Bonly conduction in steel wall as humidification primary
    3. Conly torsion in shaft
    4. Donly buckling in column
    💡 Explanation:

    Evaporation cools water; affects air enthalpy.

  9. Q9medium

    Mass convection over flat plate analog to heat transfer uses

    1. Aonly Darcy law as mass convection model primary
    2. Bonly Euler column formula
    3. Conly Mohr circle
    4. Dsimilar boundary layer equations with concentration instead of temperature
    💡 Explanation:

    Similarity between heat and mass transfer.

  10. Q10Past Paper · PPSC/FPSC/NTShard

    Recovery factor relates

    1. Afin efficiency labeled as recovery factor
    2. Bheat exchanger effectiveness labeled as recovery factor
    3. Cbolt tightening factor labeled as recovery factor
    4. Dactual recovery of kinetic energy to total enthalpy in boundary layer
    💡 Explanation:

    r = (T_aw − T)/(T0 − T).

  11. Q11hard

    Stagnation temperature in high-speed flow includes

    1. Aonly radiation temperature as stagnation T components alone
    2. Bonly wet bulb
    3. Cstatic temperature plus kinetic energy contribution converted to enthalpy
    4. Donly dew point as stagnation T
    💡 Explanation:

    T0 = T + V²/(2cp) approx for calorically perfect gas.

  12. Q12medium

    Gray body reflects radiation such that for opaque surface

    1. Aε + k = 1 mixing emissivity and conductivity
    2. Bh + k = 1
    3. CNu + Pr = 1
    4. Dα + ρ = 1
    💡 Explanation:

    Energy balance on incident radiation.

  13. Q13Past Paper · PPSC/FPSC/NTSmedium

    Radiation shield between two surfaces reduces

    1. Aconduction through vacuum always increases as shield effect primary
    2. Bmass diffusivity always increases as shield effect
    3. CReynolds number always increases as shield effect
    4. Dnet radiant heat exchange
    💡 Explanation:

    Additional surface resistance lowers q.

  14. Q14medium

    Nucleate boiling heat flux increases rapidly with

    1. Adecreasing wall temperature below saturation as increase flux always
    2. Bsuperheat ΔT_excess
    3. Czero pressure always beneficial alone
    4. Dinfinite thermal conductivity of vapor alone
    💡 Explanation:

    Bubble formation enhances convection.

  15. Q15hard

    Pool boiling critical heat flux (CHF) marks

    1. Aonset of conduction only as CHF
    2. Bstart of freezing
    3. Ctransition from efficient nucleate boiling to film boiling regime
    4. Dlaminar flow inception as CHF
    💡 Explanation:

    Burnout point on boiling curve.

  16. Q16Past Paper · PPSC/FPSC/NTSmedium

    Dropwise condensation compared to filmwise generally gives

    1. Alower coefficient always
    2. Bsame coefficient always
    3. Chigher heat transfer coefficient
    4. Dzero heat transfer
    💡 Explanation:

    Drops shed quickly exposing surface.

  17. Q17hard

    Condensation heat transfer on vertical plate often uses

    1. AFourier law alone without convection as condensation model primary
    2. BNusselt film condensation theory
    3. CDarcy law
    4. DBernoulli only as condensation
    💡 Explanation:

    Film theory predicts h ∝ (k³ρ²g/μLΔT)^¼.

  18. Q18easy

    Shell-and-tube heat exchanger baffles serve to

    1. Ablock all flow completely
    2. Breduce heat transfer area intentionally as primary purpose
    3. Cincrease shell-side turbulence and heat transfer
    4. Dmeasure viscosity only
    💡 Explanation:

    Baffles redirect shell flow across tubes.

  19. Q19Past Paper · PPSC/FPSC/NTSmedium

    Parallel flow heat exchanger LMTD is

    1. Aalways larger than counterflow LMTD always
    2. Bzero always
    3. Cgenerally smaller than counterflow for same inlet outlet states
    4. Dindependent of inlet outlet temperatures
    💡 Explanation:

    Counterflow usually gives higher ΔT_lm.

  20. Q20medium

    Heat exchanger effectiveness ε is defined as

    1. ALMTD divided by UA as effectiveness definition
    2. BUA divided by C_min alone always as effectiveness
    3. Cactual heat transfer divided by maximum possible heat transfer
    4. Dpressure drop ratio as effectiveness
    💡 Explanation:

    ε = Q/Q_max.

  21. Q21medium

    Fourier number Fo is

    1. Aα t / L²
    2. Bh L / k which is Bi labeled as Fo
    3. Ck / h L as Fo
    4. Dρ v L / μ which is Re as Fo
    💡 Explanation:

    Fo characterizes transient conduction time scale.

  22. Q22Past Paper · PPSC/FPSC/NTShard

    Heisler charts are used for

    1. Atransient heat conduction in solids with convection boundary
    2. Bfatigue S-N curves
    3. Csteam tables only as Heisler charts purpose
    4. DMohr circle
    💡 Explanation:

    Graphical solution for Bi and Fo.

  23. Q23hard

    Transient conduction in semi-infinite solid with sudden surface temperature uses

    1. Aerror function solution
    2. BEuler buckling formula
    3. CMohr circle
    4. DRankine formula
    💡 Explanation:

    Similarity variable η = x/(2√(αt)).

  24. Q24hard

    Chilton-Colburn j-factor relates

    1. Astress and strain
    2. Bpressure and velocity as j-factor primary
    3. Cheat and mass transfer coefficients dimensionlessly
    4. Dentropy and enthalpy as j-factor
    💡 Explanation:

    j_H = j_D for analogous transfer.

  25. Q25Past Paper · PPSC/FPSC/NTSmedium

    Evaporation rate from liquid surface increases with

    1. Ahigher air velocity and lower ambient vapor concentration
    2. Blower temperature difference always reducing driving force as increase always
    3. Czero concentration difference always beneficial
    4. Dinfinite humidity always beneficial
    💡 Explanation:

    Mass transfer driving force depends on concentration difference.

  26. Q26hard

    Lewis number Le is ratio of

    1. Amass to thermal diffusivity as Le definition if reversed
    2. BRe to Pr as Le
    3. Cthermal diffusivity to mass diffusivity
    4. DNu to Sh always as Le
    💡 Explanation:

    Le = α/D.

  27. Q27Past Paper · PPSC/FPSC/NTShard

    Schmidt number Sc equals

    1. Aν / D
    2. BD / ν as Sc
    3. Cα / k as Sc
    4. Dh / k as Sc
    💡 Explanation:

    Sc = ν/D = μ/(ρ D).

  28. Q28hard

    Sherwood number Sh is analogous to

    1. AReynolds only as Sherwood analog alone
    2. BEuler number as Sherwood analog
    3. CWeber number as Sherwood analog
    4. DNusselt number for mass transfer
    💡 Explanation:

    Sh = k_m L / D_AB.

  29. Q29medium

    Mass diffusivity D has units similar to

    1. Adynamic viscosity μ only as D units similarity context
    2. Bthermal diffusivity α
    3. Cthermal conductivity k only
    4. Dheat transfer coefficient h only
    💡 Explanation:

    Both m²/s.

  30. Q30Past Paper · PPSC/FPSC/NTSmedium

    Fick's first law of diffusion states mass flux is proportional to

    1. Anegative concentration gradient
    2. Bpositive concentration gradient only always
    3. Ctemperature gradient only as Fick first law
    4. Dpressure gradient only as Fick first law
    💡 Explanation:

    J″ = −D dC/dx.

  31. Q31hard

    Wien's displacement law states λ_max T equals

    1. Aσ T⁴ as Wien law
    2. Bk ΔT as Wien law
    3. Ch L/k as Wien law
    4. Dconstant approximately 2898 μm·K
    💡 Explanation:

    Peak wavelength shifts with temperature.

  32. Q32hard

    Kirchhoff's law for radiation at thermal equilibrium relates

    1. Areflectivity and transmissivity only always as Kirchhoff primary alone
    2. Bh and k always
    3. Cemissivity and absorptivity for a surface
    4. DNu and Re always
    💡 Explanation:

    ε = α for gray diffuse surfaces at equilibrium.

  33. Q33Past Paper · PPSC/FPSC/NTSeasy

    Stefan-Boltzmann constant σ appears in

    1. AFourier conduction law only
    2. Bradiation heat transfer calculations
    3. CNewton viscosity law only
    4. DHooke law only
    💡 Explanation:

    σ ≈ 5.67×10⁻⁸ W/m²K⁴.

  34. Q34hard

    Grashof number in natural convection is analogous to

    1. APrandtl number as Gr analog
    2. BNusselt number as Gr analog
    3. CReynolds number with buoyancy driving force replacing inertia
    4. DPeclet number as Gr analog
    💡 Explanation:

    Gr characterizes buoyant flow regime.

  35. Q35medium

    Natural convection heat transfer depends strongly on

    1. Aonly forced velocity always required for natural convection primary
    2. BMach number primarily for natural convection
    3. CFroude number primarily for natural convection
    4. DGrashof and Prandtl numbers
    💡 Explanation:

    Buoyancy drives flow; Gr = g β ΔT L³/ν².

  36. Q36easy

    Electrical analogy for conduction uses

    1. Apressure as heat flow always in analogy
    2. Bvelocity as temperature
    3. Ctemperature difference as driving force and heat flow as current
    4. Dmass flux as voltage
    💡 Explanation:

    Q = ΔT/R_th.

  37. Q37Past Paper · PPSC/FPSC/NTShard

    Critical radius of insulation for cylinder occurs when

    1. ABi = 0 always as critical radius condition
    2. BBi = 1 for cylinder definition r_c = k/h
    3. CRe = 2300 always
    4. DPr = 0.7 always as critical radius
    💡 Explanation:

    Adding insulation can increase heat loss below r_c.

  38. Q38medium

    Overall heat transfer coefficient U in plane wall includes

    1. Aonly radiation always alone without convection conduction
    2. Bconduction and convection resistances in series
    3. Conly mass transfer coefficient
    4. Donly Darcy friction factor
    💡 Explanation:

    1/U = 1/h1 + L/k + 1/h2.

  39. Q39hard

    NTU method in heat exchangers relates

    1. Aonly pressure drop in pipes alone as NTU method scope
    2. Bonly radiation view factors
    3. Csize (UA) and heat capacity rates to effectiveness
    4. Donly Fick diffusion only as NTU
    💡 Explanation:

    ε = f(NTU, C_r) for various flow arrangements.

  40. Q40Past Paper · PPSC/FPSC/NTSmedium

    LMTD for counter-flow heat exchanger uses

    1. Aarithmetic mean always without log as LMTD
    2. Bmaximum difference only always as LMTD
    3. Cminimum difference only always as LMTD
    4. Dlog mean of hot and cold end temperature differences
    💡 Explanation:

    ΔT_lm = (ΔT1 − ΔT2)/ln(ΔT1/ΔT2).

  41. Q41medium

    Lumped capacitance method valid when Bi is

    1. Aless than about 0.1
    2. Bgreater than 10 always as lumped criterion
    3. Cequal to Reynolds number
    4. Dinfinite always required
    💡 Explanation:

    Small Bi ⇒ uniform internal temperature.

  42. Q42medium

    Biot number Bi is defined as

    1. Ak / h L_c
    2. Bh L_c / k
    3. Ch L / ρ v cp
    4. DD / ν as Bi
    💡 Explanation:

    Bi compares internal conduction resistance to external convection.

  43. Q43Past Paper · PPSC/FPSC/NTShard

    Infinite fin heat transfer rate for uniform h and k is

    1. AQ = h A only without fin geometry
    2. BQ = k A/L only as infinite fin
    3. CQ = √(h P k A_c) (T_b − T_∞)
    4. DQ = σ T⁴ only as fin law
    💡 Explanation:

    Exponential decay solution boundary.

  44. Q44medium

    Fin efficiency compares

    1. Aactual heat transferred by fin to heat if entire fin at base temperature
    2. Bfin cost to weight only
    3. CReynolds to Prandtl only without fin context
    4. DLMTD to NTU only as fin efficiency
    💡 Explanation:

    η_f ≤ 1 due to temperature drop along fin.

  45. Q45medium

    Fin effectiveness increases with

    1. Ahigher convection coefficient and higher fin thermal conductivity
    2. Blower k always beneficial
    3. Czero surface area always beneficial
    4. Dinfinite length always without diminishing returns
    💡 Explanation:

    Fins reduce convection resistance side.

  46. Q46Past Paper · PPSC/FPSC/NTShard

    Radiation heat exchange between large parallel gray plates includes factor

    1. A1/(1/ε1 + 1/ε2 − 1) multiplying σ A (T1⁴ − T2⁴)
    2. Bh ΔT only
    3. Ck/L only
    4. DD/L only as radiation exchange
    💡 Explanation:

    Electrical network analogy for surface resistances.

  47. Q47hard

    View factor F_12 between two surfaces represents

    1. Aconductive heat flux fraction
    2. Bconvective coefficient ratio
    3. Cmass transfer coefficient
    4. Dfraction of radiation leaving surface 1 intercepted by surface 2
    💡 Explanation:

    Geometric radiation exchange factor.

  48. Q48Past Paper · PPSC/FPSC/NTSmedium

    Emissivity ε of real surface is

    1. Aalways equal to 1 for all materials
    2. Bratio of surface emissive power to blackbody emissive power at same T
    3. Cratio of absorptivity to reflectivity always as definition of ε alone
    4. Dalways zero for metals
    💡 Explanation:

    0 ≤ ε ≤ 1.

  49. Q49easy

    Stefan-Boltzmann law for gray surface gives emitted power per area as

    1. Aε σ T⁴
    2. Bσ T only linear
    3. Ck ΔT only
    4. Dh ΔT only as radiation law
    💡 Explanation:

    E = ε σ T⁴.

  50. Q50medium

    Reynolds number in forced convection characterizes

    1. Aradiation to conduction ratio
    2. Bratio of inertial to viscous forces
    3. Cmass diffusivity to thermal diffusivity as Re
    4. Dsurface tension effects only always as Re
    💡 Explanation:

    Re = ρ v L / μ.

  51. Q51Past Paper · PPSC/FPSC/NTSmedium

    Prandtl number Pr equals

    1. Aα / ν
    2. Bν / α or μ cp / k
    3. Ch L / k which is Nusselt
    4. Dg β ΔT L³/ν² which is Grashof
    💡 Explanation:

    Pr = momentum diffusivity / thermal diffusivity.

  52. Q52medium

    Nusselt number Nu is defined as

    1. Ah L / k
    2. Bk / h L
    3. Cρ v L / μ which is Reynolds
    4. Dμ cp / k which is Prandtl
    💡 Explanation:

    Nu compares convection to conduction across length L.

  53. Q53easy

    Newton's law of cooling for convection is

    1. Aq″ = k dT/dx only always as convection law
    2. Bq″ = σ T⁴ only as convection
    3. Cq″ = h (T_s − T_∞)
    4. Dq″ = D dC/dx only as convection
    💡 Explanation:

    h is convective heat transfer coefficient.

  54. Q54Past Paper · PPSC/FPSC/NTSmedium

    Composite wall in series has total thermal resistance

    1. Aproduct of resistances
    2. Balways zero
    3. Cequal to smallest layer only
    4. Dsum of individual layer resistances
    💡 Explanation:

    Heat flux same; resistances add.

  55. Q55medium

    Thermal resistance of conduction layer is

    1. Ak A / L
    2. BL / (k A)
    3. Ch A only
    4. D1/(h A) which is convection resistance
    💡 Explanation:

    R_cond = L/(kA) analogous to electrical resistance.

  56. Q56easy

    Steady one-dimensional conduction through plane wall is

    1. AQ = h A ΔT only without conduction path
    2. BQ = σ A ΔT/L
    3. CQ = m cp ΔT only as conduction through wall
    4. DQ = k A ΔT / L
    💡 Explanation:

    Linear temperature profile in homogeneous wall.

  57. Q57Past Paper · PPSC/FPSC/NTSeasy

    Thermal conductivity k has SI units

    1. AJ/kg
    2. BW/(m·K)
    3. CPa·s
    4. DW/m²
    💡 Explanation:

    k measures ability to conduct heat.

  58. Q58easy

    Fourier's law of heat conduction states that heat flux is proportional to

    1. Apositive temperature gradient only always
    2. Bpressure gradient
    3. Cnegative temperature gradient
    4. Dvelocity gradient
    💡 Explanation:

    q″ = −k dT/dx for one-dimensional conduction.

  59. Q59Past Paper · PPSC/FPSC/NTSmedium

    Contact resistance between two solids increases with

    1. Aperfectly smooth surfaces always as increase contact R always
    2. Bhigher pressure always increases contact R
    3. Chigher k always increases contact R
    4. Dsurface roughness and lower contact pressure
    💡 Explanation:

    Air gaps and roughness impede conduction.

  60. Q60medium

    Heat pipe transfers heat effectively by

    1. Asolid conduction only through vacuum as heat pipe mechanism
    2. Bevaporation and condensation of working fluid in closed cycle
    3. Cradiation only through vacuum as primary mechanism alone
    4. Dforced air only without phase change as heat pipe
    💡 Explanation:

    Phase change carries latent heat.

  61. Q61hard

    Thermal boundary layer thickness grows along flat plate because

    1. Aradiation only at leading edge as sole cause
    2. Bphase change only
    3. Cmass diffusion only as thermal BL growth cause alone
    4. Dmomentum and thermal diffusion from wall
    💡 Explanation:

    Blasius/similarity solutions describe growth.

  62. Q62Past Paper · PPSC/FPSC/NTShard

    Dittus-Boelter equation estimates Nu for

    1. Aturbulent flow in smooth tubes
    2. Blaminar tube flow always as Dittus-Boelter primary regime
    3. Cnatural convection on vertical plate always as Dittus-Boelter primary
    4. Dradiation between plates always as Dittus-Boelter
    💡 Explanation:

    Nu = 0.023 Re^0.8 Pr^n.

  63. Q63hard

    For laminar fully developed flow in circular tube with constant heat flux, Nu equals

    1. A0.023 Re^0.8 Pr^n which is turbulent correlation for laminar fully developed
    2. B4.36
    3. C3.66 for constant wall temperature case confused
    4. D1.0 always
    💡 Explanation:

    Classic laminar tube Nu for constant heat flux.

  64. Q64Past Paper · PPSC/FPSC/NTShard

    Log-mean temperature difference correction factor F for shells is used when

    1. ABi < 0.1 only as F factor purpose
    2. Bradiation only as F factor purpose
    3. Cmass transfer only as F factor purpose
    4. Dflow arrangement deviates from true counterflow or multipass
    💡 Explanation:

    F ≤ 1 corrects LMTD for configuration.

  65. Q65medium

    Countercurrent flow heat exchanger achieves

    1. Aalways lower effectiveness always compared to parallel
    2. Bsame effectiveness always regardless of arrangement
    3. Czero heat transfer
    4. Dhigher effectiveness than parallel flow for same UA generally
    💡 Explanation:

    Maintains higher ΔT along length.

  66. Q66medium

    Mass transfer coefficient k_m relates

    1. Aheat flux to temperature difference only as k_m definition
    2. Bmomentum flux to velocity gradient only as k_m
    3. Cpressure drop to flow rate only as k_m
    4. Dmass flux to concentration difference
    💡 Explanation:

    N″ = k_m (C_s − C_∞).

  67. Q67Past Paper · PPSC/FPSC/NTShard

    Equimolar counter-diffusion in gases has molar flux proportional to

    1. Atemperature gradient only as equimolar diffusion driving force alone
    2. Bpressure squared only alone always
    3. Cconcentration gradient and inversely to thickness
    4. Dvelocity cubed
    💡 Explanation:

    J = −D dC/dx for binary equimolar.

  68. Q68easy

    Molecular diffusion in solids is generally

    1. Amuch slower than in gases
    2. Bfaster than gases always
    3. Cidentical rate always
    4. Dindependent of temperature always
    💡 Explanation:

    D much smaller in solids.

  69. Q69medium

    Turbulent eddy diffusivity enhances

    1. Aonly laminar sublayer without effect always
    2. Bboth heat and mass transfer in turbulent flow
    3. Conly radiation
    4. Donly conduction in solids as turbulent eddy effect
    💡 Explanation:

    Mixing increases effective transport.

  70. Q70Past Paper · PPSC/FPSC/NTShard

    Peclet number Pe equals

    1. ARe × Pr or v L / α
    2. BNu × Pr as Pe always
    3. CGr × Pr which is Rayleigh labeled as Pe
    4. DSh × Sc labeled as Pe
    💡 Explanation:

    Pe compares advection to diffusion.

  71. Q71hard

    Rayleigh number Ra equals

    1. ARe × Pr which is Peclet labeled as Ra
    2. BNu × Pr labeled as Ra
    3. CSh × Sc labeled as Ra
    4. DGr × Pr
    💡 Explanation:

    Ra governs natural convection transition.

  72. Q72hard

    Stanton number St relates

    1. Aonly mass diffusivity as St primary alone
    2. Bonly radiation emissivity as St
    3. Cheat transfer coefficient to flow properties in dimensionless form
    4. Donly fin efficiency as St
    💡 Explanation:

    St = Nu/(Re Pr) = h/(ρ v cp).

  73. Q73Past Paper · PPSC/FPSC/NTShard

    Colburn analogy gives relation between

    1. Astress and strain in solids as Colburn analogy scope
    2. Bentropy and enthalpy as Colburn analogy scope
    3. Cbolt preload and torque only as Colburn analogy scope
    4. DStanton and friction factor f/2 for similar transfer mechanisms
    💡 Explanation:

    St Pr^(2/3) = f/2 approximately.

  74. Q74medium

    Thermal diffusivity α equals

    1. Aρ cp / k as α definition
    2. Bk cp / ρ
    3. Ch / k as α
    4. Dk / (ρ cp)
    💡 Explanation:

    α measures temperature propagation rate.

  75. Q75easy

    Insulation purpose on hot pipe is to

    1. Aincrease heat loss always as insulation purpose
    2. Bincrease pipe stress only as primary purpose
    3. Cmeasure flow rate only
    4. Dreduce heat loss to surroundings
    💡 Explanation:

    Lower q by increasing thermal resistance.

  76. Q76Past Paper · PPSC/FPSC/NTSeasy

    Extended surface (fin) material should have

    1. Ahigh thermal conductivity
    2. Blow conductivity always beneficial for fin material choice
    3. Czero conductivity ideally
    4. Dlow density only without conductivity consideration alone always as sole criterion
    💡 Explanation:

    High k minimizes temperature drop along fin.

  77. Q77medium

    Adiabatic tip fin boundary condition means

    1. Afixed temperature at tip always as adiabatic condition
    2. Bzero heat flux at tip
    3. Cinfinite convection at tip as adiabatic
    4. Dconstant heat generation at tip as adiabatic
    💡 Explanation:

    Insulated tip: dT/dx = 0 at end.

  78. Q78hard

    Heat generation in solid modifies conduction equation by adding

    1. Aonly convection term as sole modification always
    2. Bradiation only as sole modification
    3. Cq_gen term to energy balance
    4. Dmass flux only as sole modification in conduction eqn
    💡 Explanation:

    ∇·(k∇T) + q_gen = 0 steady.

  79. Q79Past Paper · PPSC/FPSC/NTShard

    Two-dimensional conduction shape factor S is used when

    1. Aonly turbulent pipe flow as shape factor use case
    2. Bonly radiation view factors conflated always
    3. Canalytical series solutions cumbersome for complex geometries
    4. Donly fatigue analysis
    💡 Explanation:

    Q = k S ΔT for conduction paths.

  80. Q80hard

    Hydrodynamic and thermal entry lengths in tube flow differ because

    1. AReynolds alone makes them identical always
    2. BPrandtl number affects thermal development rate
    3. Cpressure alone determines both equally
    4. Droughness alone determines both equally
    💡 Explanation:

    Lt ~ L Re Pr for thermal, L ~ L Re for hydrodynamic scaling.