Q1 easy
Coupling used to connect misaligned shafts elastically may be
A rigid flange only for large misalignment always ✓ B flexible coupling with elastomer element ✓ C key only without hub ✓ D set screw on glass shaft ✓ Show Answer 💡 Explanation: Flexible couplings accommodate misalignment.
Q2 hard
Critical speed of shaft occurs when
A torque is maximum only ✓ B stress is zero ✓ C rotational speed equals natural frequency of lateral vibration ✓ D bearing friction is zero only ✓ Show Answer 💡 Explanation: Resonance causes large deflections.
Q3 Past Paper · PPSC/FPSC/NTS hard
Beam with fixed ends carries less maximum moment than simply supported for same central load because
A load disappears ✓ B E is higher always ✓ C I is zero ✓ D negative moments at supports reduce midspan moment ✓ Show Answer 💡 Explanation: Indeterminate structure redistributes moments.
Q4 hard
Macaulay's method is used for
A torsion of non-circular bars only always analytically simple ✓ B beam deflection with discontinuous loading ✓ C rankine cycle analysis ✓ D radiation view factors only ✓ Show Answer 💡 Explanation: Singularity functions simplify integration.
Q5 medium
Principal strain in isotropic material under uniaxial stress includes
A only axial strain without lateral ✓ B zero strain transverse always ✓ C lateral strain from Poisson effect ✓ D shear strain equal to normal strain ✓ Show Answer 💡 Explanation: ε_y = −ν ε_x for uniaxial σ_x.
Q6 Past Paper · PPSC/FPSC/NTS medium
Thermal stress in restrained bar heated uniformly is
A zero always even if restrained ✓ B E α ΔT (compressive if heated and restrained) ✓ C α ΔT only without E ✓ D E/α ΔT ✓ Show Answer 💡 Explanation: Restrained expansion induces σ = EαΔT.
Q7 hard
Compound bar of two materials in parallel under load shares strain and
A total load according to stiffness EA sum ✓ B stress equally always regardless of E ✓ C load only by larger area alone always ✓ D no load in stiffer material ✓ Show Answer 💡 Explanation: ε same; P = σ1A1 + σ2A2.
Q8 medium
Strain rosette measures
A normal strains at three orientations to find principal strains ✓ B temperature only ✓ C hardness only ✓ D flow rate only ✓ Show Answer 💡 Explanation: Used in experimental stress analysis.
Q9 Past Paper · PPSC/FPSC/NTS easy
Section modulus for rectangular section bh²/6 uses
A b and h as width and depth with bending about horizontal NA ✓ B polar diameter only ✓ C radius only ✓ D thickness of cylinder wall only ✓ Show Answer 💡 Explanation: Z = bh²/6 for bending about horizontal axis.
Q10 hard
Shear flow q in thin-walled section equals
A M y / I only always alone for shear flow ✓ B T r / J for open section primary bending shear ✓ C P/A only ✓ D V Q / I ✓ Show Answer 💡 Explanation: q = VQ/I for built-up sections.
Q11 hard
Closed thin-walled tube in torsion resists torque by
A only bending of walls without shear flow ✓ B axial tension only ✓ C internal pressure only ✓ D shear flow around perimeter (Bredt-Batho) ✓ Show Answer 💡 Explanation: Closed sections efficient in torsion.
Q12 Past Paper · PPSC/FPSC/NTS hard
Stress in bolt due to external tensile load increases less than external load when
A plates have zero stiffness ✓ B bolt has zero stiffness ✓ C no preload exists always giving full external load on bolt incorrectly stated as always ✓ D connected plates are stiff and carry share of load ✓ Show Answer 💡 Explanation: Stiff plates reduce ΔP_bolt.
Q13 medium
Gasketed flange joint leakage prevention relies on
A zero bolt torque ✓ B only paint sealant without load ✓ C sufficient gasket compression from bolt preload ✓ D shear keys only ✓ Show Answer 💡 Explanation: Preload maintains gasket seal stress.
Q14 easy
Leaf spring is a form of
A pure torsion spring only ✓ B thin cylinder only ✓ C beam bending with multiple leaves ✓ D rankine cycle component ✓ Show Answer 💡 Explanation: Truck suspensions use laminated leaf springs.
Q15 Past Paper · PPSC/FPSC/NTS hard
Surge in spring occurs when
A spring is static only ✓ B natural frequency of spring-mass matches forcing frequency ✓ C only compression without coils ✓ D temperature is constant only ✓ Show Answer 💡 Explanation: Surge waves cause coil collision.
Q16 medium
Knuckle joint transmits
A pure torsion only always ✓ B tensile load in rods with pin connection ✓ C hydraulic pressure in pipes only ✓ D heat by radiation only ✓ Show Answer 💡 Explanation: Pin joint for tie rods.
Q17 medium
Cotter joint is used for
A sealing steam turbine blades only ✓ B connecting two rods under axial load with wedge pin ✓ C measuring viscosity only ✓ D rankine pump only ✓ Show Answer 💡 Explanation: Cotter wedge provides axial holding.
Q18 Past Paper · PPSC/FPSC/NTS medium
Riveted joint failure modes include
A only buckling of rivet head always alone ✓ B only corrosion without mechanics ✓ C only torsion of plate ✓ D shearing of rivet, bearing, tearing of plate ✓ Show Answer 💡 Explanation: Multiple failure paths analyzed.
Q19 medium
Efficiency of riveted joint is ratio of
A number of rivets to length only ✓ B strength of riveted joint to solid plate strength ✓ C pitch to diameter only without strength ✓ D weight to volume only ✓ Show Answer 💡 Explanation: Joint efficiency < 1 due to holes.
Q20 Past Paper · PPSC/FPSC/NTS hard
Brittle coating method in stress analysis uses
A cracking pattern to indicate strain direction/magnitude ✓ B thermocouples only ✓ C Pitot tube only ✓ D orifice meter only ✓ Show Answer 💡 Explanation: Photoelastic/brittle lacquer techniques.
Q21 easy
Gauge length in tensile test standard specimen affects
A yield strength fundamentally for same material incorrectly always ✓ B modulus E value fundamentally incorrectly always ✓ C measured elongation and reported strain ✓ D density of specimen ✓ Show Answer 💡 Explanation: Extensometer/gauge length standardized (e.g. 50 mm).
Q22 easy
Proportional limit is stress at which
A fracture occurs ✓ B stress-strain deviates from linearity ✓ C necking completes always ✓ D hardness equals toughness ✓ Show Answer 💡 Explanation: End of Hookean region.
Q23 Past Paper · PPSC/FPSC/NTS medium
Yield point for mild steel shows
A perfectly linear behavior to fracture ✓ B no plastic region ✓ C upper and lower yield phenomenon ✓ D negative Poisson ratio always ✓ Show Answer 💡 Explanation: Lüders bands may appear at yield.
Q24 medium
Necking in tensile test begins at
A ultimate tensile strength point ✓ B yield point always ✓ C proportional limit ✓ D elastic limit only for brittle ✓ Show Answer 💡 Explanation: Instability after UTS.
Q25 easy
Hardness test indentation measures
A only thermal conductivity ✓ B only electrical resistivity ✓ C resistance to permanent deformation ✓ D only fatigue life directly always accurately ✓ Show Answer 💡 Explanation: Brinell/Rockwell/Vickers relate to strength empirically.
Q26 Past Paper · PPSC/FPSC/NTS medium
Saint-Venant's principle states localized end effects decay within
A entire beam length always ✓ B zero distance ✓ C infinite distance always ✓ D characteristic dimension of cross-section ✓ Show Answer 💡 Explanation: Far-field stresses independent of end detail.
Q27 Past Paper · PPSC/FPSC/NTS easy
Normal stress on a plane is defined as
A force parallel to area divided by volume ✓ B moment divided by area ✓ C strain times modulus only ✓ D force perpendicular to area divided by area ✓ Show Answer 💡 Explanation: σ = P/A for axial loading.
Q28 Past Paper · PPSC/FPSC/NTS easy
Shear stress τ is given by
A normal force divided by area ✓ B force times moment arm ✓ C tangential force divided by area ✓ D strain divided by time ✓ Show Answer 💡 Explanation: τ = V/A for direct shear.
Q29 easy
Hooke's law in elastic range states
A stress equals strain always ✓ B strain is independent of stress ✓ C stress equals modulus only without strain ✓ D stress is proportional to strain ✓ Show Answer 💡 Explanation: σ = E ε within proportional limit.
Q30 easy
Modulus of elasticity E has units of
A dimensionless only ✓ B m/s ✓ C Pa or N/m² ✓ D N·m ✓ Show Answer 💡 Explanation: E relates stress and strain; same units as stress.
Q31 Past Paper · PPSC/FPSC/NTS medium
Poisson's ratio ν is defined as
A axial strain divided by lateral strain ✓ B shear strain divided by normal strain always ✓ C stress divided by strain squared ✓ D lateral strain divided by axial strain with opposite sign ✓ Show Answer 💡 Explanation: ν = −ε_lateral/ε_axial for uniaxial loading.
Q32 easy
For a bar in simple tension, maximum normal stress occurs on
A plane at 45° to load always for max ✓ B plane parallel to load ✓ C any plane equally ✓ D plane perpendicular to load ✓ Show Answer 💡 Explanation: Axial stress is maximum on cross section normal to force.
Q33 medium
Shear strain γ is approximately
A change in right angle between originally perpendicular lines ✓ B ratio of normal stresses ✓ C change in volume only ✓ D stress divided by E only ✓ Show Answer 💡 Explanation: γ measures angular distortion.
Q34 Past Paper · PPSC/FPSC/NTS medium
Modulus of rigidity G relates
A normal stress and lateral strain only ✓ B bulk modulus and pressure only ✓ C shear stress and shear strain ✓ D thermal expansion and temperature ✓ Show Answer 💡 Explanation: τ = G γ in elastic shear.
Q35 medium
Bulk modulus K measures resistance to
A uniform volumetric compression ✓ B bending only ✓ C torsion only ✓ D fatigue cracking only ✓ Show Answer 💡 Explanation: K = −p / (ΔV/V).
Q36 easy
Factor of safety is generally defined as
A working stress divided by failure strength ✓ B always equal to 1 ✓ C load divided by deflection ✓ D failure strength divided by allowable or working stress ✓ Show Answer 💡 Explanation: FOS > 1 provides design margin.
Q37 Past Paper · PPSC/FPSC/NTS easy
In bending, neutral axis is the locus of points where
A shear stress is maximum always ✓ B normal stress is maximum always ✓ C deflection is maximum ✓ D longitudinal strain is zero ✓ Show Answer 💡 Explanation: NA separates tension and compression zones.
Q38 medium
Flexure formula σ = My/I applies to
A elastic homogeneous beam in pure bending ✓ B plastic collapse always ✓ C any shape without NA ✓ D torsion of circular shaft ✓ Show Answer 💡 Explanation: Bending stress varies linearly with y from NA.
Q39 medium
Section modulus Z equals
A I divided by distance to extreme fiber c ✓ B I times c ✓ C I plus c ✓ D c divided by I ✓ Show Answer 💡 Explanation: Z = I/c used in σ = M/Z.
Q40 Past Paper · PPSC/FPSC/NTS medium
Maximum shear stress in rectangular beam occurs at
A top fiber only ✓ B bottom fiber only ✓ C quarter depth from NA always for all sections ✓ D neutral axis ✓ Show Answer 💡 Explanation: Parabolic shear distribution peaks at NA for rectangle.
Q41 hard
Deflection of simply supported beam with central point load is proportional to
A L³/(E I) ✓ B L only ✓ C 1/I only without E ✓ D E I only without L ✓ Show Answer 💡 Explanation: δ ∝ PL³/(E I) for given loading.
Q42 Past Paper · PPSC/FPSC/NTS medium
Torsion formula τ = T r / J applies to
A circular shafts in elastic range ✓ B any non-circular section without correction ✓ C beams in pure bending ✓ D thick cylinders under internal pressure only ✓ Show Answer 💡 Explanation: Circular cross-section with J polar moment.
Q43 medium
Angle of twist for shaft is φ =
A T G / (L J) ✓ B T L / (G J) ✓ C G J L / T ✓ D J / (T L G) ✓ Show Answer 💡 Explanation: Elastic torsion relation.
Q44 easy
Solid circular shaft polar moment J equals
A π d²/4 ✓ B π d³/16 ✓ C π d⁴/32 ✓ D bh³/12 ✓ Show Answer 💡 Explanation: Standard torsion constant.
Q45 Past Paper · PPSC/FPSC/NTS medium
Hollow shaft is preferred when
A weight reduction with similar torsional strength is needed ✓ B only bending dominates always ✓ C no shear stress exists ✓ D material is brittle only ✓ Show Answer 💡 Explanation: Material farther from axis carries more shear.
Q46 medium
Mohr's circle for plane stress plots
A only principal strains without stress ✓ B normal and shear stress on various planes ✓ C only thermal gradients ✓ D only fatigue cycles ✓ Show Answer 💡 Explanation: Graphical tool for stress transformation.
Q47 medium
Principal stresses are stresses on planes where
A normal stress is zero ✓ B both stresses are equal always ✓ C strain is maximum always ✓ D shear stress is zero ✓ Show Answer 💡 Explanation: Principal planes have τ = 0.
Q48 Past Paper · PPSC/FPSC/NTS hard
Maximum shear stress in plane stress equals
A radius of Mohr's circle ✓ B sum of principal stresses ✓ C difference of principal strains ✓ D zero always ✓ Show Answer 💡 Explanation: τ_max = (σ1 − σ2)/2.
Q49 hard
Euler column buckling load for pinned-pinned column is
A π² E I / L² ✓ B E I / L ✓ C π E I / L ✓ D 4 π² E I / L² always ✓ Show Answer 💡 Explanation: Critical load P_cr = π²EI/L² for end condition factor 1.
Q50 medium
Effective length of column fixed at one end and free at other is
A L/2 ✓ B L ✓ C 2L ✓ D 0.7 L ✓ Show Answer 💡 Explanation: Equivalent pinned length 2L for standard end condition.
Q51 Past Paper · PPSC/FPSC/NTS medium
Slenderness ratio for column is
A diameter divided by length ✓ B stress divided by strain ✓ C effective length divided by least radius of gyration ✓ D load divided by area only ✓ Show Answer 💡 Explanation: λ = Le/k governs buckling mode.
Q52 easy
Fatigue failure occurs at stress
A below static yield strength under cyclic loading ✓ B only above ultimate strength always ✓ C only in single static overload ✓ D only at zero mean stress always ✓ Show Answer 💡 Explanation: Progressive damage under repeated loads.
Q53 medium
Endurance limit on S-N curve for ferrous materials in reversed bending often occurs near
A 10⁶ cycles ✓ B 10³ cycles ✓ C 10⁹ cycles always for all materials ✓ D one cycle only ✓ Show Answer 💡 Explanation: Horizontal asymptote of S-N curve for steel.
Q54 Past Paper · PPSC/FPSC/NTS medium
Stress concentration factor Kt is ratio of
A nominal to maximum stress ✓ B fatigue limit to yield ✓ C maximum local stress to nominal stress ✓ D shear to normal stress always ✓ Show Answer 💡 Explanation: Kt > 1 at geometric discontinuities.
Q55 hard
Goodman line in fatigue relates
A thermal stress and strain only ✓ B mean and alternating stress for failure ✓ C buckling load and length only ✓ D torque and power only ✓ Show Answer 💡 Explanation: Modified Goodman criterion for fatigue.
Q56 hard
Bolt subjected to axial external load shares load with
A only nut always ✓ B connected members due to joint stiffness ✓ C only washer friction without members ✓ D air gap only ✓ Show Answer 💡 Explanation: Load sharing depends on bolt and member stiffness.
Q57 Past Paper · PPSC/FPSC/NTS medium
Initial tightening torque on bolt creates
A preload in shank ✓ B only shear in plate without axial force ✓ C zero stress always ✓ D only bending always ✓ Show Answer 💡 Explanation: Torque induces axial tension via thread friction.
Q58 medium
Square key transmits torque between shaft and hub by
A tension in key only ✓ B torsion in key as primary mode always ✓ C friction only without bearing ✓ D shear and bearing on key sides ✓ Show Answer 💡 Explanation: Key fails in shear/bearing if overloaded.
Q59 hard
Woodruff key is
A square parallel key only ✓ B splined shaft only ✓ C semicircular disk key for tapered hubs ✓ D set screw only ✓ Show Answer 💡 Explanation: Used with tapered hubs on shafts.
Q60 Past Paper · PPSC/FPSC/NTS hard
Shaft design for combined bending and torsion often uses
A only axial stress formula ✓ B equivalent bending or torsion theories ✓ C only thermal expansion ✓ D only Bernoulli equation ✓ Show Answer 💡 Explanation: Equivalent moment/te torque per ASME or other codes.
Q61 medium
Hollow shaft compared to solid of same weight has
A lower torsional stiffness always ✓ B higher polar moment of inertia ✓ C same J always ✓ D zero shear stress ✓ Show Answer 💡 Explanation: Material placed farther from axis increases J.
Q62 hard
Helical compression spring rate k equals
A G d⁴ / (8 D³ N) for active coils N ✓ B E I / L ✓ C P/A only ✓ D T/J only ✓ Show Answer 💡 Explanation: Spring stiffness from wire and coil geometry.
Q63 Past Paper · PPSC/FPSC/NTS medium
Spring index C is ratio of
A wire diameter to coil diameter ✓ B free length to solid length always ✓ C load to deflection only ✓ D mean coil diameter to wire diameter ✓ Show Answer 💡 Explanation: C = D/d affects stress and manufacturability.
Q64 hard
Wahl factor accounts for
A only buckling in columns ✓ B only radiation heat transfer ✓ C curvature and direct shear in spring wire stress ✓ D only entropy generation ✓ Show Answer 💡 Explanation: Corrects τ = 16T/(πd³) for springs.
Q65 medium
Thin cylinder with internal pressure p and radius r has hoop stress
A p r / t ✓ B p t / r ✓ C p r t ✓ D p / (r t) only without relation ✓ Show Answer 💡 Explanation: σ_h = pr/t for thin wall t << r.
Q66 Past Paper · PPSC/FPSC/NTS medium
Longitudinal stress in thin cylinder is
A p r / t ✓ B 2 p r / t ✓ C p r / (2t) ✓ D zero always ✓ Show Answer 💡 Explanation: σ_l = pr/(2t) half of hoop for thin cylinder.
Q67 hard
Thick cylinder analysis uses
A only thin wall formula always ✓ B only Euler buckling formula ✓ C only Fourier law ✓ D Lamé equations with radial and hoop stress variation ✓ Show Answer 💡 Explanation: Lamé solutions account for radial stress gradient.
Q68 hard
Maximum shear stress in thin cylinder under internal pressure occurs at
A inner surface for thick wall; approximately uniform for thin ✓ B outer surface only always ✓ C mid-wall only for thin always incorrectly always ✓ D zero everywhere ✓ Show Answer 💡 Explanation: Inner radius sees highest hoop stress in thick cylinders.
Q69 Past Paper · PPSC/FPSC/NTS medium
Strain energy per unit volume in elastic uniaxial stress is
A σ E ✓ B E/σ ✓ C σ²/(2E) ✓ D σ E² ✓ Show Answer 💡 Explanation: U = ½ σ ε = σ²/(2E).
Q70 hard
Castigliano's theorem relates deflection to
A thermal expansion only ✓ B partial derivative of strain energy with respect to load ✓ C entropy only ✓ D Reynolds number only ✓ Show Answer 💡 Explanation: δ = ∂U/∂P for linear elastic systems.
Q71 medium
Maximum normal stress theory (Rankine) is suitable for
A brittle materials in tension ✓ B ductile combined loading always better with von Mises ✓ C any rubber behavior ✓ D fluid flow only ✓ Show Answer 💡 Explanation: Failure when max principal stress reaches ultimate.
Q72 Past Paper · PPSC/FPSC/NTS hard
von Mises yield criterion is based on
A maximum principal stress only for all materials always ✓ B distortion energy ✓ C volume change only ✓ D thermal stress only ✓ Show Answer 💡 Explanation: Equivalent stress from distortion energy theory.
Q73 medium
Eccentric loading on column introduces
A only torsion ✓ B only shear without axial ✓ C combined axial stress and bending stress ✓ D zero stress ✓ Show Answer 💡 Explanation: M = P e adds bending to axial.
Q74 Past Paper · PPSC/FPSC/NTS hard
Shear center of open thin-walled channel section lies
A at geometric centroid always ✓ B at farthest fiber always ✓ C at infinity always ✓ D outside the cross-section on web side ✓ Show Answer 💡 Explanation: Loads through shear center avoid twisting.
Q75 medium
Deflection curve slope equals
A second derivative only always ✓ B first derivative of deflection with respect to x ✓ C integral of M only without relation ✓ D shear force directly always ✓ Show Answer 💡 Explanation: θ = dy/dx from elastic curve.
Q76 medium
Relation M = E I d²y/dx² assumes
A large deflection plasticity always included ✓ B shear deformation dominant always ✓ C thermal loading absent always required incorrectly ✓ D small deflections and linear elastic material ✓ Show Answer 💡 Explanation: Beam theory with Bernoulli-Euler assumptions.
Q77 Past Paper · PPSC/FPSC/NTS medium
Torsional rigidity of shaft is
A E I ✓ B G J ✓ C P/A ✓ D ρ g h ✓ Show Answer 💡 Explanation: GJ measures resistance to twist per unit length.
Q78 medium
Residual stress in welded joint arises from
A only external tensile load ✓ B only centrifugal force ✓ C non-uniform heating and cooling ✓ D only laminar flow ✓ Show Answer 💡 Explanation: Thermal cycles leave locked-in stresses.
Q79 medium
Creep in materials at high temperature is
A instant elastic recovery only ✓ B time-dependent permanent deformation under constant stress ✓ C fatigue at one cycle ✓ D only buckling ✓ Show Answer 💡 Explanation: Creep important in turbines and boilers.
Q80 Past Paper · PPSC/FPSC/NTS hard
Notch sensitivity in fatigue depends on
A only applied voltage ✓ B only fluid density ✓ C only color of surface ✓ D material and notch geometry ✓ Show Answer 💡 Explanation: q factor relates Kt to fatigue stress concentration.
Q81 medium
Proof load testing of bolt verifies
A ultimate fracture always required ✓ B only torque without tension ✓ C hardness only ✓ D ability to sustain specified load without permanent elongation beyond limit ✓ Show Answer 💡 Explanation: Proof stress checks elastic behavior margin.
Q82 easy
Set screw transmits torque primarily by
A keyway shear always required ✓ B friction and indentation at contact ✓ C splines only always ✓ D welding only ✓ Show Answer 💡 Explanation: Set screws rely on friction/embedding.
Q83 Past Paper · PPSC/FPSC/NTS medium
Splined connection allows
A only welded joint behavior ✓ B no alignment capability ✓ C only tensile load never torque ✓ D torque transmission with axial sliding possible ✓ Show Answer 💡 Explanation: Splines used in gearboxes and clutches.
Q84 Past Paper · PPSC/FPSC/NTS medium
Impact toughness is tested by
A Charpy or Izod notched bar impact test ✓ B tensile test only always ✓ C hardness only always ✓ D creep test at low stress only ✓ Show Answer 💡 Explanation: Energy absorbed indicates toughness.
Q85 hard
Stress relaxation in bolt at constant extension over time causes
A increase in preload always ✓ B decrease in bolt tension ✓ C no change ever ✓ D increase in joint separation always immediately ✓ Show Answer 💡 Explanation: Creep/relaxation reduces preload.
Q86 medium
Shock loading factor accounts for
A dynamic magnification over static load ✓ B only thermal expansion ✓ C only laminar boundary layer ✓ D only isentropic flow ✓ Show Answer 💡 Explanation: Impact factors increase design load.
Q87 Past Paper · PPSC/FPSC/NTS hard
Design against buckling uses critical slenderness to separate
A fatigue vs creep only ✓ B conduction vs convection only ✓ C Euler buckling vs yield failure modes ✓ D Otto vs Diesel only ✓ Show Answer 💡 Explanation: Johnson parabola bridges elastic buckling and yield.
Q88 hard
Hertz contact stress occurs between
A only fluids at rest ✓ B curved bodies in elastic contact ✓ C only ideal gases in piston only without contact mechanics ✓ D only radiation surfaces ✓ Show Answer 💡 Explanation: Point/line contact local pressure.
Q89 hard
Beam column combines
A pure torsion only ✓ B only heat conduction ✓ C axial compression and bending causing instability interaction ✓ D only mass diffusion only ✓ Show Answer 💡 Explanation: P-δ effect reduces capacity.
Q90 medium
Strain hardening increases
A ductility always without limit always ✓ B yield strength after plastic deformation ✓ C elastic modulus greatly always ✓ D density significantly ✓ Show Answer 💡 Explanation: Cold working raises strength, reduces ductility.