Strength of Materials and Machine Design MCQs 2026

90 questions with detailed answers · 32 from past papers · 9 quiz batches available

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Page 1 of 1 Questions 110 of 90
  1. Q1 easy

    Coupling used to connect misaligned shafts elastically may be

    1. A rigid flange only for large misalignment always
    2. B flexible coupling with elastomer element
    3. C key only without hub
    4. D set screw on glass shaft
    💡 Explanation:

    Flexible couplings accommodate misalignment.

  2. Q2 hard

    Critical speed of shaft occurs when

    1. A torque is maximum only
    2. B stress is zero
    3. C rotational speed equals natural frequency of lateral vibration
    4. D bearing friction is zero only
    💡 Explanation:

    Resonance causes large deflections.

  3. Q3 Past Paper · PPSC/FPSC/NTS hard

    Beam with fixed ends carries less maximum moment than simply supported for same central load because

    1. A load disappears
    2. B E is higher always
    3. C I is zero
    4. D negative moments at supports reduce midspan moment
    💡 Explanation:

    Indeterminate structure redistributes moments.

  4. Q4 hard

    Macaulay's method is used for

    1. A torsion of non-circular bars only always analytically simple
    2. B beam deflection with discontinuous loading
    3. C rankine cycle analysis
    4. D radiation view factors only
    💡 Explanation:

    Singularity functions simplify integration.

  5. Q5 medium

    Principal strain in isotropic material under uniaxial stress includes

    1. A only axial strain without lateral
    2. B zero strain transverse always
    3. C lateral strain from Poisson effect
    4. D shear strain equal to normal strain
    💡 Explanation:

    ε_y = −ν ε_x for uniaxial σ_x.

  6. Q6 Past Paper · PPSC/FPSC/NTS medium

    Thermal stress in restrained bar heated uniformly is

    1. A zero always even if restrained
    2. B E α ΔT (compressive if heated and restrained)
    3. C α ΔT only without E
    4. D E/α ΔT
    💡 Explanation:

    Restrained expansion induces σ = EαΔT.

  7. Q7 hard

    Compound bar of two materials in parallel under load shares strain and

    1. A total load according to stiffness EA sum
    2. B stress equally always regardless of E
    3. C load only by larger area alone always
    4. D no load in stiffer material
    💡 Explanation:

    ε same; P = σ1A1 + σ2A2.

  8. Q8 medium

    Strain rosette measures

    1. A normal strains at three orientations to find principal strains
    2. B temperature only
    3. C hardness only
    4. D flow rate only
    💡 Explanation:

    Used in experimental stress analysis.

  9. Q9 Past Paper · PPSC/FPSC/NTS easy

    Section modulus for rectangular section bh²/6 uses

    1. A b and h as width and depth with bending about horizontal NA
    2. B polar diameter only
    3. C radius only
    4. D thickness of cylinder wall only
    💡 Explanation:

    Z = bh²/6 for bending about horizontal axis.

  10. Q10 hard

    Shear flow q in thin-walled section equals

    1. A M y / I only always alone for shear flow
    2. B T r / J for open section primary bending shear
    3. C P/A only
    4. D V Q / I
    💡 Explanation:

    q = VQ/I for built-up sections.

  11. Q11 hard

    Closed thin-walled tube in torsion resists torque by

    1. A only bending of walls without shear flow
    2. B axial tension only
    3. C internal pressure only
    4. D shear flow around perimeter (Bredt-Batho)
    💡 Explanation:

    Closed sections efficient in torsion.

  12. Q12 Past Paper · PPSC/FPSC/NTS hard

    Stress in bolt due to external tensile load increases less than external load when

    1. A plates have zero stiffness
    2. B bolt has zero stiffness
    3. C no preload exists always giving full external load on bolt incorrectly stated as always
    4. D connected plates are stiff and carry share of load
    💡 Explanation:

    Stiff plates reduce ΔP_bolt.

  13. Q13 medium

    Gasketed flange joint leakage prevention relies on

    1. A zero bolt torque
    2. B only paint sealant without load
    3. C sufficient gasket compression from bolt preload
    4. D shear keys only
    💡 Explanation:

    Preload maintains gasket seal stress.

  14. Q14 easy

    Leaf spring is a form of

    1. A pure torsion spring only
    2. B thin cylinder only
    3. C beam bending with multiple leaves
    4. D rankine cycle component
    💡 Explanation:

    Truck suspensions use laminated leaf springs.

  15. Q15 Past Paper · PPSC/FPSC/NTS hard

    Surge in spring occurs when

    1. A spring is static only
    2. B natural frequency of spring-mass matches forcing frequency
    3. C only compression without coils
    4. D temperature is constant only
    💡 Explanation:

    Surge waves cause coil collision.

  16. Q16 medium

    Knuckle joint transmits

    1. A pure torsion only always
    2. B tensile load in rods with pin connection
    3. C hydraulic pressure in pipes only
    4. D heat by radiation only
    💡 Explanation:

    Pin joint for tie rods.

  17. Q17 medium

    Cotter joint is used for

    1. A sealing steam turbine blades only
    2. B connecting two rods under axial load with wedge pin
    3. C measuring viscosity only
    4. D rankine pump only
    💡 Explanation:

    Cotter wedge provides axial holding.

  18. Q18 Past Paper · PPSC/FPSC/NTS medium

    Riveted joint failure modes include

    1. A only buckling of rivet head always alone
    2. B only corrosion without mechanics
    3. C only torsion of plate
    4. D shearing of rivet, bearing, tearing of plate
    💡 Explanation:

    Multiple failure paths analyzed.

  19. Q19 medium

    Efficiency of riveted joint is ratio of

    1. A number of rivets to length only
    2. B strength of riveted joint to solid plate strength
    3. C pitch to diameter only without strength
    4. D weight to volume only
    💡 Explanation:

    Joint efficiency < 1 due to holes.

  20. Q20 Past Paper · PPSC/FPSC/NTS hard

    Brittle coating method in stress analysis uses

    1. A cracking pattern to indicate strain direction/magnitude
    2. B thermocouples only
    3. C Pitot tube only
    4. D orifice meter only
    💡 Explanation:

    Photoelastic/brittle lacquer techniques.

  21. Q21 easy

    Gauge length in tensile test standard specimen affects

    1. A yield strength fundamentally for same material incorrectly always
    2. B modulus E value fundamentally incorrectly always
    3. C measured elongation and reported strain
    4. D density of specimen
    💡 Explanation:

    Extensometer/gauge length standardized (e.g. 50 mm).

  22. Q22 easy

    Proportional limit is stress at which

    1. A fracture occurs
    2. B stress-strain deviates from linearity
    3. C necking completes always
    4. D hardness equals toughness
    💡 Explanation:

    End of Hookean region.

  23. Q23 Past Paper · PPSC/FPSC/NTS medium

    Yield point for mild steel shows

    1. A perfectly linear behavior to fracture
    2. B no plastic region
    3. C upper and lower yield phenomenon
    4. D negative Poisson ratio always
    💡 Explanation:

    Lüders bands may appear at yield.

  24. Q24 medium

    Necking in tensile test begins at

    1. A ultimate tensile strength point
    2. B yield point always
    3. C proportional limit
    4. D elastic limit only for brittle
    💡 Explanation:

    Instability after UTS.

  25. Q25 easy

    Hardness test indentation measures

    1. A only thermal conductivity
    2. B only electrical resistivity
    3. C resistance to permanent deformation
    4. D only fatigue life directly always accurately
    💡 Explanation:

    Brinell/Rockwell/Vickers relate to strength empirically.

  26. Q26 Past Paper · PPSC/FPSC/NTS medium

    Saint-Venant's principle states localized end effects decay within

    1. A entire beam length always
    2. B zero distance
    3. C infinite distance always
    4. D characteristic dimension of cross-section
    💡 Explanation:

    Far-field stresses independent of end detail.

  27. Q27 Past Paper · PPSC/FPSC/NTS easy

    Normal stress on a plane is defined as

    1. A force parallel to area divided by volume
    2. B moment divided by area
    3. C strain times modulus only
    4. D force perpendicular to area divided by area
    💡 Explanation:

    σ = P/A for axial loading.

  28. Q28 Past Paper · PPSC/FPSC/NTS easy

    Shear stress τ is given by

    1. A normal force divided by area
    2. B force times moment arm
    3. C tangential force divided by area
    4. D strain divided by time
    💡 Explanation:

    τ = V/A for direct shear.

  29. Q29 easy

    Hooke's law in elastic range states

    1. A stress equals strain always
    2. B strain is independent of stress
    3. C stress equals modulus only without strain
    4. D stress is proportional to strain
    💡 Explanation:

    σ = E ε within proportional limit.

  30. Q30 easy

    Modulus of elasticity E has units of

    1. A dimensionless only
    2. B m/s
    3. C Pa or N/m²
    4. D N·m
    💡 Explanation:

    E relates stress and strain; same units as stress.

  31. Q31 Past Paper · PPSC/FPSC/NTS medium

    Poisson's ratio ν is defined as

    1. A axial strain divided by lateral strain
    2. B shear strain divided by normal strain always
    3. C stress divided by strain squared
    4. D lateral strain divided by axial strain with opposite sign
    💡 Explanation:

    ν = −ε_lateral/ε_axial for uniaxial loading.

  32. Q32 easy

    For a bar in simple tension, maximum normal stress occurs on

    1. A plane at 45° to load always for max
    2. B plane parallel to load
    3. C any plane equally
    4. D plane perpendicular to load
    💡 Explanation:

    Axial stress is maximum on cross section normal to force.

  33. Q33 medium

    Shear strain γ is approximately

    1. A change in right angle between originally perpendicular lines
    2. B ratio of normal stresses
    3. C change in volume only
    4. D stress divided by E only
    💡 Explanation:

    γ measures angular distortion.

  34. Q34 Past Paper · PPSC/FPSC/NTS medium

    Modulus of rigidity G relates

    1. A normal stress and lateral strain only
    2. B bulk modulus and pressure only
    3. C shear stress and shear strain
    4. D thermal expansion and temperature
    💡 Explanation:

    τ = G γ in elastic shear.

  35. Q35 medium

    Bulk modulus K measures resistance to

    1. A uniform volumetric compression
    2. B bending only
    3. C torsion only
    4. D fatigue cracking only
    💡 Explanation:

    K = −p / (ΔV/V).

  36. Q36 easy

    Factor of safety is generally defined as

    1. A working stress divided by failure strength
    2. B always equal to 1
    3. C load divided by deflection
    4. D failure strength divided by allowable or working stress
    💡 Explanation:

    FOS > 1 provides design margin.

  37. Q37 Past Paper · PPSC/FPSC/NTS easy

    In bending, neutral axis is the locus of points where

    1. A shear stress is maximum always
    2. B normal stress is maximum always
    3. C deflection is maximum
    4. D longitudinal strain is zero
    💡 Explanation:

    NA separates tension and compression zones.

  38. Q38 medium

    Flexure formula σ = My/I applies to

    1. A elastic homogeneous beam in pure bending
    2. B plastic collapse always
    3. C any shape without NA
    4. D torsion of circular shaft
    💡 Explanation:

    Bending stress varies linearly with y from NA.

  39. Q39 medium

    Section modulus Z equals

    1. A I divided by distance to extreme fiber c
    2. B I times c
    3. C I plus c
    4. D c divided by I
    💡 Explanation:

    Z = I/c used in σ = M/Z.

  40. Q40 Past Paper · PPSC/FPSC/NTS medium

    Maximum shear stress in rectangular beam occurs at

    1. A top fiber only
    2. B bottom fiber only
    3. C quarter depth from NA always for all sections
    4. D neutral axis
    💡 Explanation:

    Parabolic shear distribution peaks at NA for rectangle.

  41. Q41 hard

    Deflection of simply supported beam with central point load is proportional to

    1. A L³/(E I)
    2. B L only
    3. C 1/I only without E
    4. D E I only without L
    💡 Explanation:

    δ ∝ PL³/(E I) for given loading.

  42. Q42 Past Paper · PPSC/FPSC/NTS medium

    Torsion formula τ = T r / J applies to

    1. A circular shafts in elastic range
    2. B any non-circular section without correction
    3. C beams in pure bending
    4. D thick cylinders under internal pressure only
    💡 Explanation:

    Circular cross-section with J polar moment.

  43. Q43 medium

    Angle of twist for shaft is φ =

    1. A T G / (L J)
    2. B T L / (G J)
    3. C G J L / T
    4. D J / (T L G)
    💡 Explanation:

    Elastic torsion relation.

  44. Q44 easy

    Solid circular shaft polar moment J equals

    1. A π d²/4
    2. B π d³/16
    3. C π d⁴/32
    4. D bh³/12
    💡 Explanation:

    Standard torsion constant.

  45. Q45 Past Paper · PPSC/FPSC/NTS medium

    Hollow shaft is preferred when

    1. A weight reduction with similar torsional strength is needed
    2. B only bending dominates always
    3. C no shear stress exists
    4. D material is brittle only
    💡 Explanation:

    Material farther from axis carries more shear.

  46. Q46 medium

    Mohr's circle for plane stress plots

    1. A only principal strains without stress
    2. B normal and shear stress on various planes
    3. C only thermal gradients
    4. D only fatigue cycles
    💡 Explanation:

    Graphical tool for stress transformation.

  47. Q47 medium

    Principal stresses are stresses on planes where

    1. A normal stress is zero
    2. B both stresses are equal always
    3. C strain is maximum always
    4. D shear stress is zero
    💡 Explanation:

    Principal planes have τ = 0.

  48. Q48 Past Paper · PPSC/FPSC/NTS hard

    Maximum shear stress in plane stress equals

    1. A radius of Mohr's circle
    2. B sum of principal stresses
    3. C difference of principal strains
    4. D zero always
    💡 Explanation:

    τ_max = (σ1 − σ2)/2.

  49. Q49 hard

    Euler column buckling load for pinned-pinned column is

    1. A π² E I / L²
    2. B E I / L
    3. C π E I / L
    4. D 4 π² E I / L² always
    💡 Explanation:

    Critical load P_cr = π²EI/L² for end condition factor 1.

  50. Q50 medium

    Effective length of column fixed at one end and free at other is

    1. A L/2
    2. B L
    3. C 2L
    4. D 0.7 L
    💡 Explanation:

    Equivalent pinned length 2L for standard end condition.

  51. Q51 Past Paper · PPSC/FPSC/NTS medium

    Slenderness ratio for column is

    1. A diameter divided by length
    2. B stress divided by strain
    3. C effective length divided by least radius of gyration
    4. D load divided by area only
    💡 Explanation:

    λ = Le/k governs buckling mode.

  52. Q52 easy

    Fatigue failure occurs at stress

    1. A below static yield strength under cyclic loading
    2. B only above ultimate strength always
    3. C only in single static overload
    4. D only at zero mean stress always
    💡 Explanation:

    Progressive damage under repeated loads.

  53. Q53 medium

    Endurance limit on S-N curve for ferrous materials in reversed bending often occurs near

    1. A 10⁶ cycles
    2. B 10³ cycles
    3. C 10⁹ cycles always for all materials
    4. D one cycle only
    💡 Explanation:

    Horizontal asymptote of S-N curve for steel.

  54. Q54 Past Paper · PPSC/FPSC/NTS medium

    Stress concentration factor Kt is ratio of

    1. A nominal to maximum stress
    2. B fatigue limit to yield
    3. C maximum local stress to nominal stress
    4. D shear to normal stress always
    💡 Explanation:

    Kt > 1 at geometric discontinuities.

  55. Q55 hard

    Goodman line in fatigue relates

    1. A thermal stress and strain only
    2. B mean and alternating stress for failure
    3. C buckling load and length only
    4. D torque and power only
    💡 Explanation:

    Modified Goodman criterion for fatigue.

  56. Q56 hard

    Bolt subjected to axial external load shares load with

    1. A only nut always
    2. B connected members due to joint stiffness
    3. C only washer friction without members
    4. D air gap only
    💡 Explanation:

    Load sharing depends on bolt and member stiffness.

  57. Q57 Past Paper · PPSC/FPSC/NTS medium

    Initial tightening torque on bolt creates

    1. A preload in shank
    2. B only shear in plate without axial force
    3. C zero stress always
    4. D only bending always
    💡 Explanation:

    Torque induces axial tension via thread friction.

  58. Q58 medium

    Square key transmits torque between shaft and hub by

    1. A tension in key only
    2. B torsion in key as primary mode always
    3. C friction only without bearing
    4. D shear and bearing on key sides
    💡 Explanation:

    Key fails in shear/bearing if overloaded.

  59. Q59 hard

    Woodruff key is

    1. A square parallel key only
    2. B splined shaft only
    3. C semicircular disk key for tapered hubs
    4. D set screw only
    💡 Explanation:

    Used with tapered hubs on shafts.

  60. Q60 Past Paper · PPSC/FPSC/NTS hard

    Shaft design for combined bending and torsion often uses

    1. A only axial stress formula
    2. B equivalent bending or torsion theories
    3. C only thermal expansion
    4. D only Bernoulli equation
    💡 Explanation:

    Equivalent moment/te torque per ASME or other codes.

  61. Q61 medium

    Hollow shaft compared to solid of same weight has

    1. A lower torsional stiffness always
    2. B higher polar moment of inertia
    3. C same J always
    4. D zero shear stress
    💡 Explanation:

    Material placed farther from axis increases J.

  62. Q62 hard

    Helical compression spring rate k equals

    1. A G d⁴ / (8 D³ N) for active coils N
    2. B E I / L
    3. C P/A only
    4. D T/J only
    💡 Explanation:

    Spring stiffness from wire and coil geometry.

  63. Q63 Past Paper · PPSC/FPSC/NTS medium

    Spring index C is ratio of

    1. A wire diameter to coil diameter
    2. B free length to solid length always
    3. C load to deflection only
    4. D mean coil diameter to wire diameter
    💡 Explanation:

    C = D/d affects stress and manufacturability.

  64. Q64 hard

    Wahl factor accounts for

    1. A only buckling in columns
    2. B only radiation heat transfer
    3. C curvature and direct shear in spring wire stress
    4. D only entropy generation
    💡 Explanation:

    Corrects τ = 16T/(πd³) for springs.

  65. Q65 medium

    Thin cylinder with internal pressure p and radius r has hoop stress

    1. A p r / t
    2. B p t / r
    3. C p r t
    4. D p / (r t) only without relation
    💡 Explanation:

    σ_h = pr/t for thin wall t << r.

  66. Q66 Past Paper · PPSC/FPSC/NTS medium

    Longitudinal stress in thin cylinder is

    1. A p r / t
    2. B 2 p r / t
    3. C p r / (2t)
    4. D zero always
    💡 Explanation:

    σ_l = pr/(2t) half of hoop for thin cylinder.

  67. Q67 hard

    Thick cylinder analysis uses

    1. A only thin wall formula always
    2. B only Euler buckling formula
    3. C only Fourier law
    4. D Lamé equations with radial and hoop stress variation
    💡 Explanation:

    Lamé solutions account for radial stress gradient.

  68. Q68 hard

    Maximum shear stress in thin cylinder under internal pressure occurs at

    1. A inner surface for thick wall; approximately uniform for thin
    2. B outer surface only always
    3. C mid-wall only for thin always incorrectly always
    4. D zero everywhere
    💡 Explanation:

    Inner radius sees highest hoop stress in thick cylinders.

  69. Q69 Past Paper · PPSC/FPSC/NTS medium

    Strain energy per unit volume in elastic uniaxial stress is

    1. A σ E
    2. B E/σ
    3. C σ²/(2E)
    4. D σ E²
    💡 Explanation:

    U = ½ σ ε = σ²/(2E).

  70. Q70 hard

    Castigliano's theorem relates deflection to

    1. A thermal expansion only
    2. B partial derivative of strain energy with respect to load
    3. C entropy only
    4. D Reynolds number only
    💡 Explanation:

    δ = ∂U/∂P for linear elastic systems.

  71. Q71 medium

    Maximum normal stress theory (Rankine) is suitable for

    1. A brittle materials in tension
    2. B ductile combined loading always better with von Mises
    3. C any rubber behavior
    4. D fluid flow only
    💡 Explanation:

    Failure when max principal stress reaches ultimate.

  72. Q72 Past Paper · PPSC/FPSC/NTS hard

    von Mises yield criterion is based on

    1. A maximum principal stress only for all materials always
    2. B distortion energy
    3. C volume change only
    4. D thermal stress only
    💡 Explanation:

    Equivalent stress from distortion energy theory.

  73. Q73 medium

    Eccentric loading on column introduces

    1. A only torsion
    2. B only shear without axial
    3. C combined axial stress and bending stress
    4. D zero stress
    💡 Explanation:

    M = P e adds bending to axial.

  74. Q74 Past Paper · PPSC/FPSC/NTS hard

    Shear center of open thin-walled channel section lies

    1. A at geometric centroid always
    2. B at farthest fiber always
    3. C at infinity always
    4. D outside the cross-section on web side
    💡 Explanation:

    Loads through shear center avoid twisting.

  75. Q75 medium

    Deflection curve slope equals

    1. A second derivative only always
    2. B first derivative of deflection with respect to x
    3. C integral of M only without relation
    4. D shear force directly always
    💡 Explanation:

    θ = dy/dx from elastic curve.

  76. Q76 medium

    Relation M = E I d²y/dx² assumes

    1. A large deflection plasticity always included
    2. B shear deformation dominant always
    3. C thermal loading absent always required incorrectly
    4. D small deflections and linear elastic material
    💡 Explanation:

    Beam theory with Bernoulli-Euler assumptions.

  77. Q77 Past Paper · PPSC/FPSC/NTS medium

    Torsional rigidity of shaft is

    1. A E I
    2. B G J
    3. C P/A
    4. D ρ g h
    💡 Explanation:

    GJ measures resistance to twist per unit length.

  78. Q78 medium

    Residual stress in welded joint arises from

    1. A only external tensile load
    2. B only centrifugal force
    3. C non-uniform heating and cooling
    4. D only laminar flow
    💡 Explanation:

    Thermal cycles leave locked-in stresses.

  79. Q79 medium

    Creep in materials at high temperature is

    1. A instant elastic recovery only
    2. B time-dependent permanent deformation under constant stress
    3. C fatigue at one cycle
    4. D only buckling
    💡 Explanation:

    Creep important in turbines and boilers.

  80. Q80 Past Paper · PPSC/FPSC/NTS hard

    Notch sensitivity in fatigue depends on

    1. A only applied voltage
    2. B only fluid density
    3. C only color of surface
    4. D material and notch geometry
    💡 Explanation:

    q factor relates Kt to fatigue stress concentration.

  81. Q81 medium

    Proof load testing of bolt verifies

    1. A ultimate fracture always required
    2. B only torque without tension
    3. C hardness only
    4. D ability to sustain specified load without permanent elongation beyond limit
    💡 Explanation:

    Proof stress checks elastic behavior margin.

  82. Q82 easy

    Set screw transmits torque primarily by

    1. A keyway shear always required
    2. B friction and indentation at contact
    3. C splines only always
    4. D welding only
    💡 Explanation:

    Set screws rely on friction/embedding.

  83. Q83 Past Paper · PPSC/FPSC/NTS medium

    Splined connection allows

    1. A only welded joint behavior
    2. B no alignment capability
    3. C only tensile load never torque
    4. D torque transmission with axial sliding possible
    💡 Explanation:

    Splines used in gearboxes and clutches.

  84. Q84 Past Paper · PPSC/FPSC/NTS medium

    Impact toughness is tested by

    1. A Charpy or Izod notched bar impact test
    2. B tensile test only always
    3. C hardness only always
    4. D creep test at low stress only
    💡 Explanation:

    Energy absorbed indicates toughness.

  85. Q85 hard

    Stress relaxation in bolt at constant extension over time causes

    1. A increase in preload always
    2. B decrease in bolt tension
    3. C no change ever
    4. D increase in joint separation always immediately
    💡 Explanation:

    Creep/relaxation reduces preload.

  86. Q86 medium

    Shock loading factor accounts for

    1. A dynamic magnification over static load
    2. B only thermal expansion
    3. C only laminar boundary layer
    4. D only isentropic flow
    💡 Explanation:

    Impact factors increase design load.

  87. Q87 Past Paper · PPSC/FPSC/NTS hard

    Design against buckling uses critical slenderness to separate

    1. A fatigue vs creep only
    2. B conduction vs convection only
    3. C Euler buckling vs yield failure modes
    4. D Otto vs Diesel only
    💡 Explanation:

    Johnson parabola bridges elastic buckling and yield.

  88. Q88 hard

    Hertz contact stress occurs between

    1. A only fluids at rest
    2. B curved bodies in elastic contact
    3. C only ideal gases in piston only without contact mechanics
    4. D only radiation surfaces
    💡 Explanation:

    Point/line contact local pressure.

  89. Q89 hard

    Beam column combines

    1. A pure torsion only
    2. B only heat conduction
    3. C axial compression and bending causing instability interaction
    4. D only mass diffusion only
    💡 Explanation:

    P-δ effect reduces capacity.

  90. Q90 medium

    Strain hardening increases

    1. A ductility always without limit always
    2. B yield strength after plastic deformation
    3. C elastic modulus greatly always
    4. D density significantly
    💡 Explanation:

    Cold working raises strength, reduces ductility.