Thermodynamics MCQs 2026

90 questions with detailed answers · 32 from past papers · 9 quiz batches available

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Page 1 of 1 Questions 110 of 90
  1. Q1 medium

    Reheat in Rankine cycle primarily reduces

    1. A boiler fuel need to zero
    2. B moisture content at turbine exit and blade erosion
    3. C pump work to zero always
    4. D condenser size to zero always
    💡 Explanation:

    Reheat raises expansion path quality at LP turbine.

  2. Q2 medium

    Regeneration in Rankine cycle uses

    1. A intercooling in Brayton compressor only as Rankine primary incorrectly
    2. B aftercooler in diesel only
    3. C feedwater heaters to preheat water using extracted steam
    4. D radiation shield only
    💡 Explanation:

    Bleed steam preheats feedwater reducing heat input.

  3. Q3 Past Paper · PPSC/FPSC/NTS medium

    Quality (dryness fraction) x in wet steam region is

    1. A mass of vapor divided by total mass of mixture
    2. B volume of liquid only
    3. C pressure divided by temperature
    4. D enthalpy of liquid only
    💡 Explanation:

    x = m_v/(m_v + m_l).

  4. Q4 hard

    On T-s diagram, area under reversible process curve represents

    1. A work always for any process without distinction incorrectly
    2. B heat transfer for that process
    3. C entropy generation equal to area always incorrectly
    4. D mass flow only
    💡 Explanation:

    Q = ∫T ds for reversible boundary heat transfer.

  5. Q5 medium

    On p-v diagram, area under process curve represents

    1. A heat transfer always equal to area on pv incorrectly always
    2. B entropy change directly as area incorrectly
    3. C internal energy always
    4. D boundary work for quasi-static process
    💡 Explanation:

    W = ∫p dv for closed system work.

  6. Q6 Past Paper · PPSC/FPSC/NTS medium

    Critical point on steam property chart is where

    1. A liquid and vapor phases become indistinguishable
    2. B boiling always occurs at 100°C regardless of pressure incorrectly
    3. C entropy is zero always
    4. D quality equals zero only always at critical incorrectly alone
    💡 Explanation:

    At critical T and p, phase boundary vanishes.

  7. Q7 easy

    Dry saturated steam has quality

    1. A 1
    2. B 0
    3. C 0.5 always
    4. D undefined always incorrectly
    💡 Explanation:

    x = 1 means all vapor at saturation.

  8. Q8 easy

    Subcooled liquid has temperature

    1. A above saturation always
    2. B equal to critical always
    3. C below saturation temperature at given pressure
    4. D zero always
    💡 Explanation:

    Compressed liquid region left of saturation curve.

  9. Q9 Past Paper · PPSC/FPSC/NTS easy

    Superheated steam has temperature

    1. A below saturation
    2. B always at triple point
    3. C above saturation temperature at given pressure
    4. D equal to wet bulb always incorrectly
    💡 Explanation:

    Right of saturation dome on T-s diagram.

  10. Q10 hard

    Availability (exergy) of system interacting with environment at T0 is related to

    1. A maximum useful work obtainable to dead state
    2. B total internal energy always equal to availability incorrectly
    3. C only kinetic energy
    4. D only gravitational PE always alone
    💡 Explanation:

    Exergy measures work potential relative to reference environment.

  11. Q11 hard

    Irreversibility I in process equals

    1. A T0 times entropy generation
    2. B work output always
    3. C heat input only without T0
    4. D enthalpy change only
    💡 Explanation:

    I = T0 S_gen for closed systems commonly.

  12. Q12 Past Paper · PPSC/FPSC/NTS medium

    Isothermal expansion of ideal gas in cylinder does

    1. A no work
    2. B decrease U for ideal gas incorrectly in isothermal
    3. C positive work equal to heat added at constant T
    4. D zero heat transfer always
    💡 Explanation:

    ΔU=0 for ideal gas isothermal so Q=W.

  13. Q13 medium

    Polytropic process p v^n = C with n=0 gives

    1. A constant volume
    2. B constant pressure process
    3. C isothermal always
    4. D isentropic always
    💡 Explanation:

    n=0 ⇒ p constant.

  14. Q14 medium

    Polytropic index n=1 corresponds to

    1. A isochoric
    2. B isothermal process for ideal gas
    3. C isentropic
    4. D isobaric
    💡 Explanation:

    n=1: T constant for ideal gas.

  15. Q15 Past Paper · PPSC/FPSC/NTS medium

    Polytropic index n=γ corresponds to

    1. A isentropic process for ideal gas
    2. B isothermal
    3. C isobaric
    4. D isochoric
    💡 Explanation:

    Reversible adiabatic ideal gas: n = γ.

  16. Q16 hard

    Helmholtz function A is

    1. A H − T S incorrectly as Helmholtz
    2. B pV only
    3. C T S only
    4. D U − T S
    💡 Explanation:

    A = U − TS; natural variables T,V.

  17. Q17 hard

    Gibbs function G is

    1. A U + pV only alone defines G incorrectly
    2. B T S − H
    3. C H − T S
    4. D pV − U
    💡 Explanation:

    G = H − TS; useful for constant T,p.

  18. Q18 Past Paper · PPSC/FPSC/NTS hard

    Maxwell relations connect

    1. A only mechanical stress and strain
    2. B partial derivatives of thermodynamic potentials
    3. C only Fourier law
    4. D only Navier-Stokes
    💡 Explanation:

    Cross partial equality from exact differentials.

  19. Q19 hard

    Joule-Thomson coefficient μ_JT is

    1. A (∂p/∂T)_v
    2. B (∂T/∂p)_h
    3. C (∂h/∂p)_T only alone without definition incorrectly
    4. D (∂s/∂v)_T only alone
    💡 Explanation:

    Throttling process is isenthalpic.

  20. Q20 medium

    Throttling of ideal gas causes

    1. A no temperature change
    2. B always cooling regardless of gas incorrectly
    3. C always heating
    4. D phase change always
    💡 Explanation:

    Ideal gas enthalpy depends only on T; h constant ⇒ T constant.

  21. Q21 Past Paper · PPSC/FPSC/NTS hard

    Clausius inequality states for real cycles

    1. A equal to zero always for irreversible too incorrectly
    2. B greater than zero always
    3. C independent of temperature
    4. D ∮ δQ/T ≤ 0
    💡 Explanation:

    Equality for reversible; inequality for irreversible.

  22. Q22 medium

    Entropy generation is always

    1. A negative in irreversible processes incorrectly
    2. B zero for all irreversible processes incorrectly
    3. C non-negative for real processes
    4. D undefined for heat transfer
    💡 Explanation:

    Second law: S_gen ≥ 0.

  23. Q23 medium

    Steady flow energy equation with negligible PE and KE changes reduces to

    1. A Q − W_s = Δh for one stream
    2. B ΔU only always in SFEE incorrectly alone
    3. C ΔS only
    4. D p Δv only always alone sufficient
    💡 Explanation:

    SFEE: q + h1 + V1²/2 = h2 + V2²/2 + ws.

  24. Q24 Past Paper · PPSC/FPSC/NTS medium

    Nozzle converts

    1. A KE into heat only always in nozzle incorrectly
    2. B pressure rise without velocity change always
    3. C enthalpy decrease into kinetic energy increase
    4. D mass into energy
    💡 Explanation:

    Adiabatic nozzle energy conversion.

  25. Q25 medium

    Diffuser converts

    1. A pressure into vacuum always
    2. B heat into work only in closed piston always incorrectly as diffuser primary
    3. C entropy decrease without irreversibility always in real diffuser incorrectly stated as always
    4. D kinetic energy into pressure rise
    💡 Explanation:

    Deceleration increases static pressure.

  26. Q26 Past Paper · PPSC/FPSC/NTS medium

    Dew point temperature is temperature at which

    1. A condensation begins for given moisture content at constant pressure
    2. B boiling occurs always at 100°C incorrectly regardless of pressure
    3. C entropy is maximum always
    4. D dry bulb equals wet bulb always for any air incorrectly
    💡 Explanation:

    Saturation partial pressure reached.

  27. Q27 medium

    Relative humidity is ratio of

    1. A absolute humidity to density of dry air only without saturation reference incorrectly alone always as RH
    2. B wet bulb to dry bulb always as RH incorrectly
    3. C mass of liquid to mass of vapor in tank incorrectly as RH
    4. D partial pressure of vapor to saturation pressure at same temperature
    💡 Explanation:

    φ = p_v/p_g × 100%.

  28. Q28 medium

    Throttling valve process is approximated as

    1. A isentropic always for irreversible throttle incorrectly always
    2. B isochoric always
    3. C isothermal always for real gas always incorrectly
    4. D isenthalpic with negligible heat and work transfer
    💡 Explanation:

    h1 ≈ h2 for throttling.

  29. Q29 Past Paper · PPSC/FPSC/NTS easy

    Mixture of ideal gases total pressure is

    1. A product of partial pressures
    2. B average only without summing incorrectly
    3. C zero if mixed
    4. D sum of partial pressures (Dalton)
    💡 Explanation:

    P = Σ p_i.

  30. Q30 medium

    Partial pressure of component i is

    1. A m_i P only mass fraction without conversion incorrectly always alone
    2. B P/n_i only incorrectly
    3. C y_i P where y_i is mole fraction
    4. D always equal for all components incorrectly
    💡 Explanation:

    p_i = x_i P for ideal gas mixture.

  31. Q31 hard

    Air-standard diesel cycle cut-off ratio affects

    1. A only compression ratio of Otto only incorrectly alone always
    2. B only condenser pressure
    3. C heat addition at constant pressure and cycle efficiency
    4. D only pump work in Rankine incorrectly alone
    💡 Explanation:

    Higher cut-off adds heat at lower average T_add effect.

  32. Q32 Past Paper · PPSC/FPSC/NTS hard

    Mean effective pressure (MEP) in IC engines is

    1. A peak pressure always equal to MEP incorrectly
    2. B work per cycle divided by displaced volume
    3. C fuel energy only without volume incorrectly
    4. D exhaust pressure only
    💡 Explanation:

    MEP compares engine output independent of size.

  33. Q33 medium

    Knocking in SI engine is caused by

    1. A too much steam injection incorrectly
    2. B auto-ignition of end-gas ahead of flame front
    3. C low compression always beneficial incorrectly
    4. D rankine reheat only incorrectly
    💡 Explanation:

    Uncontrolled combustion raises pressure rapidly.

  34. Q34 Past Paper · PPSC/FPSC/NTS easy

    Octane number measures

    1. A cetane for diesel incorrectly labeled as octane primary
    2. B viscosity only
    3. C calorific value only alone always as octane
    4. D knock resistance of fuel
    💡 Explanation:

    Higher octane resists knock.

  35. Q35 easy

    Cetane number measures

    1. A knock resistance of gasoline incorrectly as cetane
    2. B ignition quality of diesel fuel
    3. C steam quality x incorrectly
    4. D hardness of coal incorrectly
    💡 Explanation:

    Higher cetane easier ignition delay shorter.

  36. Q36 Past Paper · PPSC/FPSC/NTS medium

    Turbocharger on engine uses

    1. A exhaust energy to drive compressor for intake boost
    2. B crankshaft only without exhaust incorrectly alone always
    3. C electric battery only primary in standard turbo definition incorrectly alone
    4. D condenser cooling only
    💡 Explanation:

    Waste exhaust enthalpy increases intake density.

  37. Q37 medium

    Supercharger differs from turbocharger by being

    1. A driven only by condenser pump incorrectly
    2. B only on steam turbine incorrectly
    3. C mechanically driven from crankshaft rather than exhaust turbine
    4. D only passive air filter incorrectly
    💡 Explanation:

    Supercharger draws crank work directly.

  38. Q38 medium

    Internal energy of ideal gas depends on

    1. A pressure and volume independently always additionally incorrectly for ideal gas U
    2. B temperature only
    3. C only volume
    4. D only pressure
    💡 Explanation:

    u = u(T) for ideal gas.

  39. Q39 Past Paper · PPSC/FPSC/NTS medium

    Enthalpy of ideal gas depends on

    1. A only pressure independently always for h incorrectly for ideal gas
    2. B only specific volume independently always for h incorrectly
    3. C temperature only
    4. D only quality x of steam always incorrectly for ideal gas air
    💡 Explanation:

    h = h(T) for ideal gas.

  40. Q40 medium

    Heat transfer at constant volume to ideal gas increases

    1. A internal energy by Q since W=0
    2. B enthalpy only without U change incorrectly always
    3. C nothing because W=0 incorrectly
    4. D only pressure without T change incorrectly always
    💡 Explanation:

    Isochoric: Q = ΔU.

  41. Q41 medium

    Heat transfer at constant pressure to ideal gas equals

    1. A change in internal energy only always at cp incorrectly always alone
    2. B zero always
    3. C change in enthalpy ΔH
    4. D only entropy decrease incorrectly
    💡 Explanation:

    Isobaric: Q = ΔH.

  42. Q42 Past Paper · PPSC/FPSC/NTS hard

    Free expansion into vacuum (Joule expansion) of ideal gas has

    1. A no temperature change and no work
    2. B large cooling always for ideal gas incorrectly always
    3. C large heating always
    4. D isentropic behavior always incorrectly
    💡 Explanation:

    Q=0,W=0, ideal gas ΔT=0.

  43. Q43 hard

    Gouy-Stodola theorem links

    1. A stress and strain only
    2. B lost work to irreversibility and T0
    3. C Fourier law only
    4. D Darcy law only
    💡 Explanation:

    W_lost = T0 S_gen.

  44. Q44 medium

    Saturated liquid and vapor lines meet at

    1. A critical point on property diagrams
    2. B triple point only always incorrectly as meeting of sat lines termination on dome
    3. C origin always
    4. D absolute zero always
    💡 Explanation:

    Critical point top of vapor dome.

  45. Q45 Past Paper · PPSC/FPSC/NTS medium

    Isentropic expansion of steam in turbine ideally follows

    1. A constant temperature line always incorrectly as isentropic always
    2. B constant h line on ph chart as isentropic primary incorrectly alone always
    3. C constant entropy line on T-s diagram
    4. D constant quality line in wet region always entire expansion incorrectly always
    💡 Explanation:

    Reversible adiabatic ⇒ Δs=0.

  46. Q46 easy

    Boiler in Rankine cycle operates ideally near

    1. A constant volume heat addition as Otto primary incorrectly alone for boiler
    2. B constant pressure heat addition
    3. C isothermal heat rejection
    4. D adiabatic compression in boiler incorrectly
    💡 Explanation:

    Liquid heated and vaporized at approx constant p.

  47. Q47 medium

    Volumetric efficiency of engine is

    1. A thermal efficiency incorrectly labeled
    2. B actual mass inducted divided by mass at STP filling displacement
    3. C mechanical efficiency incorrectly labeled
    4. D isentropic efficiency of turbine incorrectly labeled
    💡 Explanation:

    Breathing capacity measure.

  48. Q48 Past Paper · PPSC/FPSC/NTS easy

    Zeroth law of thermodynamics establishes

    1. A conservation of energy
    2. B entropy always increases in isolated system
    3. C impossibility of perpetual motion only
    4. D transitivity of thermal equilibrium and temperature concept
    💡 Explanation:

    If A=B and B=C in thermal equilibrium then A=C.

  49. Q49 Past Paper · PPSC/FPSC/NTS easy

    First law of thermodynamics for closed system is

    1. A ΔU = Q + W always regardless of convention
    2. B Q = 0 always
    3. C ΔU = Q − W with work done by system positive in common convention
    4. D W = m g h only
    💡 Explanation:

    Energy conservation: heat minus boundary work changes internal energy.

  50. Q50 easy

    Second law of thermodynamics implies

    1. A energy is created
    2. B efficiency of heat engine can be 100% always
    3. C entropy always decreases in isolated system
    4. D natural processes tend toward increased total entropy of universe
    💡 Explanation:

    Clausius/Kelvin-Planck statements limit direction and efficiency.

  51. Q51 medium

    Third law of thermodynamics states entropy approaches

    1. A infinity at 0 K always for all substances
    2. B constant at all temperatures
    3. C zero as absolute temperature approaches zero for perfect crystals
    4. D negative values only
    💡 Explanation:

    S → 0 at 0 K for perfect crystalline substances.

  52. Q52 Past Paper · PPSC/FPSC/NTS easy

    Enthalpy H is defined as

    1. A U − pV
    2. B p/V
    3. C U/pV
    4. D U + pV
    💡 Explanation:

    H = U + pV convenient for constant pressure processes.

  53. Q53 medium

    Specific heat at constant pressure cp is

    1. A (∂u/∂T)_v only always interchangeable without distinction
    2. B (∂p/∂T)_v
    3. C (∂v/∂T)_p only alone defines cp
    4. D (∂h/∂T)_p
    💡 Explanation:

    cp relates enthalpy change with temperature at constant p.

  54. Q54 medium

    Entropy change for ideal gas between two states

    1. A depends on states not path when computed via reversible path
    2. B depends only on path always for all properties incorrectly
    3. C depends only on pressure always without temperature
    4. D depends only on volume always without mass
    💡 Explanation:

    Entropy is property; use reversible path between states.

  55. Q55 Past Paper · PPSC/FPSC/NTS medium

    Isentropic process for ideal gas satisfies

    1. A p v = constant always for all processes
    2. B T/p = constant only always
    3. C p v^γ = constant
    4. D entropy increases always
    💡 Explanation:

    Reversible adiabatic: s = constant.

  56. Q56 medium

    Carnot cycle efficiency depends on

    1. A temperatures of hot and cold reservoirs only
    2. B working substance only
    3. C pressure ratio only without temperatures
    4. D piston speed only
    💡 Explanation:

    η = 1 − T_L/T_H for reversible Carnot.

  57. Q57 hard

    Carnot theorem states no engine between two reservoirs exceeds efficiency of

    1. A any irreversible engine always lower than Carnot incorrectly as theorem wording
    2. B 100% if operated quickly
    3. C engine independent of temperature difference
    4. D reversible Carnot engine between same reservoirs
    💡 Explanation:

    All reversible engines same η between given T_H and T_L.

  58. Q58 Past Paper · PPSC/FPSC/NTS easy

    Otto cycle is idealized model for

    1. A steam turbine only
    2. B gas turbine Brayton only
    3. C vapor compression refrigerator only as power cycle
    4. D spark-ignition gasoline engine
    💡 Explanation:

    SI engines approximated by Otto cycle.

  59. Q59 medium

    Otto cycle efficiency increases with

    1. A compression ratio
    2. B decreasing compression ratio
    3. C increasing exhaust back pressure only beneficial always
    4. D water injection alone as sole lever incorrectly
    💡 Explanation:

    η = 1 − 1/r^(γ−1) for air-standard Otto.

  60. Q60 medium

    Diesel cycle differs from Otto mainly by

    1. A constant pressure heat addition
    2. B constant volume heat rejection only as sole difference incorrectly
    3. C no compression stroke
    4. D isothermal expansion only entire cycle
    💡 Explanation:

    Diesel: compression ignition with constant p heat addition.

  61. Q61 Past Paper · PPSC/FPSC/NTS hard

    Diesel cycle efficiency compared to Otto at same compression ratio is generally

    1. A always lower without exception
    2. B always equal regardless of cut-off
    3. C zero
    4. D higher due to different heat addition path with cut-off
    💡 Explanation:

    Cut-off ratio affects η; comparison depends on parameters.

  62. Q62 easy

    Rankine cycle is used for

    1. A steam power plants
    2. B gasoline engines only
    3. C vapor compression refrigeration only as primary power
    4. D hydraulic turbines only
    💡 Explanation:

    Boiler-turbine-condenser-pump steam cycle.

  63. Q63 Past Paper · PPSC/FPSC/NTS medium

    Rankine cycle efficiency improves by

    1. A increasing average temperature of heat addition and lowering condenser pressure
    2. B lowering boiler temperature always beneficial incorrectly
    3. C increasing condenser pressure always beneficial incorrectly
    4. D removing pump always
    💡 Explanation:

    Higher T_avg add and lower T_cond increase η.

  64. Q64 easy

    Brayton cycle is model for

    1. A gas turbine engine
    2. B Rankine steam plant only
    3. C Otto SI engine only
    4. D vapor compression refrigerator only as power primary incorrectly
    💡 Explanation:

    Compressor-combustor-turbine cycle.

  65. Q65 Past Paper · PPSC/FPSC/NTS medium

    Brayton cycle efficiency depends on

    1. A only fuel type without cycle parameters incorrectly alone
    2. B only turbine blade count
    3. C pressure ratio and γ
    4. D only condenser temperature as Rankine incorrectly alone
    💡 Explanation:

    η = 1 − 1/rp^((γ−1)/γ) air-standard.

  66. Q66 medium

    Intercooling in multi-stage compression reduces

    1. A turbine work always increases beneficially incorrectly as primary intercooling effect on turbine
    2. B compressor work and final temperature
    3. C mass flow to zero
    4. D cycle efficiency always decreases without exception incorrectly always
    💡 Explanation:

    Cooling between stages lowers work.

  67. Q67 hard

    Reheat in Brayton cycle can

    1. A increase net work but may reduce efficiency if not optimized
    2. B always reduce work
    3. C eliminate combustion
    4. D make cycle identical to Rankine always
    💡 Explanation:

    Trade-off between work and heat input.

  68. Q68 Past Paper · PPSC/FPSC/NTS medium

    Combined cycle plant pairs

    1. A only two Rankine cycles in parallel without GT incorrectly alone
    2. B Brayton topping with Rankine bottoming using exhaust heat
    3. C only refrigeration cycle
    4. D hydraulic and wind only
    💡 Explanation:

    Higher overall efficiency using waste heat.

  69. Q69 medium

    COP of heat pump is

    1. A work divided by heat always inverted incorrectly
    2. B always less than 1 for heat pump incorrectly always
    3. C desired heat effect divided by work input
    4. D independent of temperatures
    💡 Explanation:

    COP_HP = Q_H/W.

  70. Q70 Past Paper · PPSC/FPSC/NTS medium

    COP of refrigerator is

    1. A heating effect divided by work for refrigerator incorrectly
    2. B always greater than Carnot incorrectly always
    3. C Q_H/W for refrigerator incorrectly
    4. D cooling effect divided by work input
    💡 Explanation:

    COP_R = Q_L/W.

  71. Q71 hard

    Carnot COP for refrigerator between T_L and T_H is

    1. A T_H/(T_H − T_L) which is heat pump COP incorrectly labeled as refrigerator
    2. B T_L/(T_H − T_L)
    3. C 1 − T_L/T_H
    4. D (T_H − T_L)/T_L inverted incorrectly
    💡 Explanation:

    Maximum COP from reversible Carnot refrigerator.

  72. Q72 medium

    Triple point of water occurs at approximately

    1. A 100°C and 1 atm always incorrectly as triple point
    2. B 0 K
    3. C 374°C always
    4. D 0.01°C and 611 Pa
    💡 Explanation:

    Unique T,p where solid-liquid-vapor coexist.

  73. Q73 Past Paper · PPSC/FPSC/NTS medium

    Specific volume of saturated mixture equals

    1. A v_g only always
    2. B v_f + x(v_g − v_f)
    3. C v_f only always regardless of x incorrectly
    4. D x v_f only incorrectly
    💡 Explanation:

    Linear interpolation by quality x.

  74. Q74 medium

    Enthalpy of wet steam mixture is

    1. A h_g only always
    2. B h_f only always regardless of quality incorrectly always
    3. C h_f + x h_fg
    4. D x h_g only incorrectly alone always
    💡 Explanation:

    h = h_f + x h_fg.

  75. Q75 hard

    Entropy change of ideal gas between two states can be found using

    1. A only density measurement
    2. B cp ln(T2/T1) − R ln(p2/p1) for ideal gas
    3. C only color of gas
    4. D only piston material
    💡 Explanation:

    Property change from state points.

  76. Q76 Past Paper · PPSC/FPSC/NTS hard

    Van der Waals equation accounts for

    1. A only ideal gas behavior always perfectly
    2. B only radiation heat transfer
    3. C only turbulence
    4. D molecular volume and intermolecular attraction
    💡 Explanation:

    Real gas correction to pV = RT.

  77. Q77 medium

    Compressibility factor Z equals

    1. A RT/(pv) inverted always as definition incorrectly
    2. B γ always
    3. C cp/cv always
    4. D pV/(mRT) or pv/(RT)
    💡 Explanation:

    Z deviates from 1 for real gases.

  78. Q78 hard

    Law of corresponding states suggests

    1. A all gases identical at any T,p without reduced coordinates incorrectly
    2. B real gases at same reduced T and p have similar Z
    3. C only liquids follow
    4. D only solids follow
    💡 Explanation:

    Reduced properties Tr, pr used.

  79. Q79 Past Paper · PPSC/FPSC/NTS medium

    Mollier chart for steam plots

    1. A stress versus strain
    2. B velocity versus time only
    3. C current versus voltage only
    4. D enthalpy versus entropy with pressure overlays
    💡 Explanation:

    h-s diagram used in steam plant analysis.

  80. Q80 medium

    Isentropic efficiency of turbine is ratio of

    1. A isentropic to actual inverted incorrectly as definition
    2. B actual work to isentropic work for same inlet state and exit pressure
    3. C heat transfer to work incorrectly
    4. D inlet KE to exit KE only
    💡 Explanation:

    η_s = w_actual/w_isentropic.

  81. Q81 medium

    Isentropic efficiency of compressor is ratio of

    1. A actual to isentropic inverted for compressor definition incorrectly
    2. B heat to entropy always
    3. C isentropic work to actual work for same states
    4. D mass flow ratios only
    💡 Explanation:

    η_c = w_isentropic/w_actual.

  82. Q82 Past Paper · PPSC/FPSC/NTS easy

    Heat engine thermal efficiency η is

    1. A Q_L/Q_H incorrectly
    2. B Q_H/Q_L inverted beneficial incorrectly
    3. C work input divided by heat
    4. D net work output divided by heat input from hot reservoir
    💡 Explanation:

    η = W_net/Q_H.

  83. Q83 medium

    Kelvin-Planck statement of second law denies

    1. A heat flow from cold to hot without work incorrectly as Kelvin-Planck primary alone
    2. B device producing work from single heat reservoir alone
    3. C conservation of mass
    4. D existence of temperature
    💡 Explanation:

    Need heat rejection to complete cycle.

  84. Q84 medium

    Clausius statement of second law denies

    1. A work from single reservoir incorrectly as Clausius primary
    2. B increase of entropy in universe incorrectly stated as denied
    3. C spontaneous heat transfer from cold to hot body without external work
    4. D phase change existence
    💡 Explanation:

    Refrigerator requires work input.

  85. Q85 Past Paper · PPSC/FPSC/NTS easy

    Perpetual motion machine of first kind violates

    1. A second law only
    2. B first law of thermodynamics
    3. C third law only
    4. D zeroth law only
    💡 Explanation:

    PMM1 creates energy.

  86. Q86 easy

    Perpetual motion machine of second kind violates

    1. A second law of thermodynamics
    2. B first law only
    3. C Newton laws only
    4. D continuity equation only
    💡 Explanation:

    PMM2 converts all heat to work without rejection.

  87. Q87 medium

    Psychrometric chart displays

    1. A properties of moist air including humidity ratio and enthalpy
    2. B only steam inside boiler without air
    3. C only metal stress
    4. D only beam shear flow
    💡 Explanation:

    HVAC analysis tool.

  88. Q88 medium

    Entropy of isolated system during real spontaneous process

    1. A always decreases
    2. B always zero change
    3. C increases or remains constant never decreases
    4. D decreases if heat added incorrectly always
    💡 Explanation:

    Second law for isolated system.

  89. Q89 Past Paper · PPSC/FPSC/NTS medium

    Air-standard Otto cycle consists of

    1. A constant pressure heat addition only as Otto incorrectly
    2. B isothermal compression only entire cycle
    3. C rankine pump stage included
    4. D isentropic compression, constant volume heat addition, isentropic expansion, constant volume heat rejection
    💡 Explanation:

    Four processes modeling SI engine.

  90. Q90 hard

    Steam calorimetry throttling calorimeter measures

    1. A bolt preload only
    2. B quality of wet steam by isenthalpic expansion to superheat region
    3. C shaft diameter only
    4. D Reynolds number only
    💡 Explanation:

    Measure T after throttle to find x.