Engineering Materials and Metallurgy MCQs 2026

78 questions with detailed answers · 27 from past papers · 8 quiz batches available

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Page 1 of 1 Questions 110 of 78
  1. Q1 medium

    Titanium alloys advantage is

    1. A high strength-to-weight ratio and corrosion resistance
    2. B lowest melting point of all metals
    3. C always cheaper than mild steel
    4. D cannot be welded ever
    💡 Explanation:

    Ti used in aerospace and chemical plant.

  2. Q2 easy

    Composite materials combine

    1. A only single pure element always
    2. B matrix and reinforcement for tailored properties
    3. C only water and oil
    4. D only one grain boundary
    💡 Explanation:

    Fibre-reinforced polymers and MMCs examples.

  3. Q3 medium

    Fiber direction in composites primarily controls

    1. A isotropic behaviour in all directions always
    2. B only colour
    3. C anisotropic strength and stiffness
    4. D only density reduction only
    💡 Explanation:

    Loads along fibres carry highest stress.

  4. Q4 hard

    Glass transition temperature Tg of polymer is

    1. A melting of iron carbide
    2. B boiling of water
    3. C temperature where amorphous polymer becomes rubbery on heating
    4. D Curie point of nickel only
    💡 Explanation:

    Below Tg: glassy; above: rubbery (amorphous thermoplastics).

  5. Q5 easy

    Thermoplastics can be

    1. A only cured irreversibly like thermosets always
    2. B re-melted and reshaped repeatedly
    3. C only used as liquids always
    4. D never injection moulded
    💡 Explanation:

    PE, PP, ABS reprocess on heating.

  6. Q6 easy

    Thermosetting plastics once cured

    1. A soften reversibly like wax always
    2. B become metals
    3. C cannot be re-melted without degradation
    4. D evaporate instantly
    💡 Explanation:

    Epoxy, phenolic form cross-linked network.

  7. Q7 medium

    Inoculation in cast iron promotes

    1. A only cementite formation always
    2. B only gas porosity
    3. C only martensite in cast iron
    4. D graphite nucleation for desired graphite form
    💡 Explanation:

    FeSi inoculant controls solidification structure.

  8. Q8 medium

    Segregation in castings causes

    1. A perfect homogeneity always
    2. B only surface polish
    3. C only magnetic alignment
    4. D non-uniform composition and properties
    💡 Explanation:

    Last-to-freeze regions rich or lean in solutes.

  9. Q9 hard

    Hot shortness in metals is cracking during hot work due to

    1. A low-melting grain boundary films (e.g. copper in steel)
    2. B only cold temperature
    3. C only high hardness
    4. D only magnetic fields
    💡 Explanation:

    Sulphur and copper segregation can cause hot shortness.

  10. Q10 hard

    Cold shortness is associated with

    1. A only high temperature forging
    2. B excess phosphorus making steel brittle at low temperature
    3. C only austenite stability
    4. D only copper plating
    💡 Explanation:

    Phosphorus raises ductile-brittle transition temperature.

  11. Q11 hard

    Recrystallization temperature for metals is approximately

    1. A 0.3 to 0.5 times absolute melting temperature
    2. B twice melting point
    3. C room temperature always for steel
    4. D zero kelvin
    💡 Explanation:

    Rule of thumb for annealing after cold work.

  12. Q12 easy

    Allotropy of iron means

    1. A iron never changes structure
    2. B iron exists in different crystal structures (BCC and FCC) at different temperatures
    3. C iron is only liquid at room temperature
    4. D iron has no carbon solubility
    💡 Explanation:

    Alpha iron BCC; gamma austenite FCC.

  13. Q13 hard

    Curie temperature of iron is about

    1. A 770°C where ferromagnetism is lost
    2. B 27°C
    3. C 1538°C melting point
    4. D 1147°C eutectic
    💡 Explanation:

    Above Curie point iron is paramagnetic.

  14. Q14 easy

    Zinc coating on steel sheet is called

    1. A tinning only always
    2. B anodizing
    3. C galvanizing
    4. D chromating only on aluminium
    💡 Explanation:

    Zn sacrificially protects steel.

  15. Q15 medium

    Passivation of stainless steel uses

    1. A nitric or citric acid treatment to strengthen oxide film
    2. B molten zinc dip only
    3. C carburizing gas
    4. D sand blasting only
    💡 Explanation:

    Removes free iron and enhances corrosion resistance.

  16. Q16 hard

    Pearlite lamella spacing affects

    1. A only electrical resistivity of copper wire
    2. B strength and hardness with finer spacing giving higher strength
    3. C only paint viscosity
    4. D only air density at altitude
    💡 Explanation:

    Faster cooling through austenite produces finer pearlite.

  17. Q17 easy

    Bronze traditionally is alloy of

    1. A copper and tin
    2. B copper and zinc
    3. C iron and nickel
    4. D lead and tin only
    💡 Explanation:

    Bronzes used for bearings and statues.

  18. Q18 Past Paper · PPSC/FPSC/NTS hard

    Stress corrosion cracking needs

    1. A only compression in dry nitrogen
    2. B only cyclic impact in vacuum
    3. C only annealing temperature
    4. D tensile stress, susceptible alloy and corrosive medium together
    💡 Explanation:

    SCC can cause sudden failure at low apparent stress.

  19. Q19 medium

    Powder metallurgy process sequence is typically

    1. A casting, forging, welding only
    2. B only electroplating
    3. C only extrusion of billet
    4. D powder production, compaction, sintering
    💡 Explanation:

    Sintering bonds particles below melting point.

  20. Q20 medium

    Sintering temperature in PM is

    1. A always above liquidus
    2. B at room temperature only
    3. C below melting point of main constituent
    4. D above boiling point
    💡 Explanation:

    Diffusion bonds particles retaining porous structure optionally.

  21. Q21 hard

    Phase diagram horizontal line indicates

    1. A variable composition single phase only
    2. B impossible equilibrium
    3. C only mechanical mixing
    4. D invariant reaction (eutectic, eutectoid or peritectic)
    💡 Explanation:

    Three phases coexist at invariant points.

  22. Q22 medium

    Lever rule on phase diagram calculates

    1. A hardness from cooling rate
    2. B mass fractions of two phases in two-phase region
    3. C electrical conductivity only
    4. D surface tension only
    💡 Explanation:

    Tie-line proportions give phase amounts.

  23. Q23 medium

    Solid solution strengthening adds

    1. A only surface paint
    2. B only lubricant oil
    3. C only vacuum
    4. D solute atoms distorting lattice and impeding dislocations
    💡 Explanation:

    Alloying elements raise yield strength.

  24. Q24 Past Paper · PPSC/FPSC/NTS easy

    Work hardening (strain hardening) increases strength by

    1. A dislocation density increase during plastic deformation
    2. B grain growth in annealing
    3. C removing all dislocations
    4. D only heating above melting point
    💡 Explanation:

    Cold working raises strength, reduces ductility.

  25. Q25 medium

    Recrystallization annealing after cold work

    1. A increases dislocation density further
    2. B forms new strain-free grains
    3. C converts metal to gas
    4. D only hardens surface by quench
    💡 Explanation:

    Heating above recrystallization temperature restores ductility.

  26. Q26 Past Paper · PPSC/FPSC/NTS easy

    Brinell hardness test uses

    1. A diamond pyramid only always
    2. B spring hammer rebound only
    3. C ultrasonic pulse only
    4. D hardened steel or carbide ball indenter
    💡 Explanation:

    Large impression averages coarse structures like castings.

  27. Q27 easy

    Rockwell hardness differs from Brinell by

    1. A measuring only scratch width optically always
    2. B using only Charpy hammer
    3. C measuring only electrical resistance
    4. D measuring depth of penetration under load
    💡 Explanation:

    Rockwell gives quick direct dial reading.

  28. Q28 medium

    Vickers hardness uses

    1. A steel ball 10 mm only
    2. B single scratch line only
    3. C pendulum rebound only
    4. D square-based diamond pyramid indenter
    💡 Explanation:

    HV applicable to thin sections and all hardness ranges.

  29. Q29 Past Paper · PPSC/FPSC/NTS easy

    NDT method ultrasonic testing detects

    1. A only surface colour
    2. B only chemical composition quantitatively always
    3. C internal flaws using sound wave reflection
    4. D only magnetic personality
    💡 Explanation:

    UT common for welds and forgings.

  30. Q30 medium

    Radiographic testing (RT) uses

    1. A X-rays or gamma rays to image internal defects
    2. B only visible light photography of surface
    3. C only hammer ringing always
    4. D only acid etching macro only
    💡 Explanation:

    RT reveals porosity, cracks, inclusions.

  31. Q31 hard

    Intergranular corrosion follows

    1. A only crystal interiors uniformly
    2. B grain boundaries preferentially
    3. C only external paint failure
    4. D only magnetic domains
    💡 Explanation:

    Sensitization in stainless weld HAZ example.

  32. Q32 medium

    Pitting corrosion is

    1. A uniform thickness loss only
    2. B only intergranular cracking always
    3. C localized attack forming small cavities
    4. D only high-temperature oxidation
    💡 Explanation:

    Chlorides often initiate pits in stainless steels.

  33. Q33 Past Paper · PPSC/FPSC/NTS medium

    Galvanic corrosion requires

    1. A only one metal isolated in dry air
    2. B only plastic contact
    3. C electrochemically dissimilar metals in common electrolyte with conductive path
    4. D only identical metals touching in oil
    💡 Explanation:

    Noble and active metal couple drives corrosion.

  34. Q34 medium

    Corrosion fatigue combines

    1. A only dry wear
    2. B cyclic loading and corrosive environment
    3. C only static tensile load in vacuum
    4. D only thermal expansion
    💡 Explanation:

    Environment accelerates crack growth rate.

  35. Q35 hard

    Endurance limit (fatigue limit) exists for

    1. A all plastics always
    2. B all ceramics at room temperature always
    3. C many ferrous alloys under reversed stress
    4. D no materials ever
    💡 Explanation:

    Below this stress, fatigue life is very long.

  36. Q36 Past Paper · PPSC/FPSC/NTS easy

    Fatigue failure occurs under

    1. A only single overload above UTS
    2. B only at cryogenic temperatures always
    3. C cyclic stresses below static yield strength
    4. D only compressive static load
    💡 Explanation:

    Crack initiation and growth lead to sudden fracture.

  37. Q37 Past Paper · PPSC/FPSC/NTS medium

    Creep is

    1. A instant elastic stretch only
    2. B fatigue at room temperature only
    3. C time-dependent plastic deformation under constant stress at high temperature
    4. D hardness test indentation
    💡 Explanation:

    Important for turbines and boiler components.

  38. Q38 medium

    Cupronickel alloys resist

    1. A seawater corrosion
    2. B only organic acids in food only always
    3. C zero corrosion in all acids
    4. D only high-temperature creep in gas turbines alone
    💡 Explanation:

    Used in marine heat exchangers and coins.

  39. Q39 medium

    Magnetic particle inspection requires

    1. A only aluminium alloys always
    2. B ferromagnetic material
    3. C only plastics
    4. D only ceramics always
    💡 Explanation:

    Flux leakage at defects attracts particles.

  40. Q40 easy

    Dye penetrant inspection finds

    1. A surface-breaking defects
    2. B only internal voids deep inside always without surface opening
    3. C only magnetic domains
    4. D only thermal conductivity
    💡 Explanation:

    Capillary action draws dye into cracks.

  41. Q41 medium

    Eddy current testing is best for

    1. A only concrete structures
    2. B only wood timber
    3. C only glass only
    4. D detecting surface and near-surface flaws in conductive materials
    💡 Explanation:

    Electromagnetic induction senses conductivity changes.

  42. Q42 hard

    CCT diagram is more useful than TTT for

    1. A only isothermal holding forever
    2. B only tensile testing speed
    3. C only hardness of rubber
    4. D continuous cooling processes like actual quenching
    💡 Explanation:

    Continuous Cooling Transformation matches real quench curves.

  43. Q43 hard

    Bainite microstructure forms at

    1. A only instant quench to martensite always
    2. B only equilibrium slow cooling
    3. C only gas phase
    4. D intermediate temperature below pearlite nose on TTT
    💡 Explanation:

    Bainite: ferrite + carbide; tougher than martensite.

  44. Q44 medium

    Superalloys are used in

    1. A only window glass
    2. B only concrete reinforcement bars at room service only
    3. C only paper production only
    4. D gas turbine hot sections for creep and oxidation resistance
    💡 Explanation:

    Ni-base superalloys withstand high temperature.

  45. Q45 Past Paper · PPSC/FPSC/NTS medium

    Ductile (nodular) cast iron obtains graphite shape by

    1. A rapid oil quench only
    2. B adding magnesium or cerium inoculant
    3. C removing all carbon
    4. D sand casting without cores only
    💡 Explanation:

    Spheroidal graphite improves tensile strength and ductility.

  46. Q46 medium

    White cast iron has carbon as

    1. A graphite flakes only
    2. B graphite nodules only
    3. C no iron carbide
    4. D cementite without free graphite
    💡 Explanation:

    Very hard and brittle; used as wear surface or malleablized.

  47. Q47 Past Paper · PPSC/FPSC/NTS easy

    Stainless steel resists corrosion primarily due to

    1. A chromium forming passive oxide film (typically ≥11% Cr)
    2. B high carbon only
    3. C lead content
    4. D zinc coating only
    💡 Explanation:

    Chromium oxide layer protects base metal.

  48. Q48 Past Paper · PPSC/FPSC/NTS easy

    Annealing heat treatment purpose is to

    1. A maximize hardness always
    2. B soften metal, relieve stress and refine grain structure
    3. C form martensite always
    4. D increase internal stress
    💡 Explanation:

    Heating and slow cooling homogenize structure.

  49. Q49 medium

    Normalizing involves heating above Ac₃ and cooling in

    1. A furnace at 1°C/hour
    2. B oil quench
    3. C liquid nitrogen
    4. D still air
    💡 Explanation:

    Faster than annealing; refines grains.

  50. Q50 Past Paper · PPSC/FPSC/NTS medium

    Tempering of martensite

    1. A increases carbon in martensite by diffusion always instantly
    2. B eliminates all iron
    3. C reduces brittleness and internal stress while lowering hardness somewhat
    4. D converts to liquid
    💡 Explanation:

    Tempering reheats quenched steel below A₁.

  51. Q51 medium

    Carburizing adds carbon to surface using

    1. A only water quench
    2. B only sand blasting
    3. C carbon-rich atmosphere or pack at elevated temperature
    4. D only anodizing
    💡 Explanation:

    Low-carbon steel surface becomes high-carbon after diffusion.

  52. Q52 hard

    Nitriding forms hard surface by

    1. A adding sulphur only
    2. B removing all carbon
    3. C electroplating copper only
    4. D diffusing nitrogen into steel (often alloy steels)
    💡 Explanation:

    Produces wear-resistant case without quench distortion.

  53. Q53 Past Paper · PPSC/FPSC/NTS easy

    Grey cast iron microstructure contains

    1. A graphite flakes in ferrite/pearlite matrix
    2. B nodular graphite spheres primarily
    3. C no graphite
    4. D only martensite
    💡 Explanation:

    Flake graphite gives good machinability and damping.

  54. Q54 easy

    Brass is an alloy of

    1. A copper and zinc
    2. B copper and tin only
    3. C iron and carbon
    4. D aluminium and magnesium only
    💡 Explanation:

    Zn in Cu improves machinability and strength.

  55. Q55 Past Paper · PPSC/FPSC/NTS medium

    Austenitic stainless steels (300 series) are

    1. A always martensitic BCC
    2. B pure iron only
    3. C non-magnetic FCC with nickel and chromium
    4. D always cast iron
    💡 Explanation:

    304, 316 common; good corrosion resistance.

  56. Q56 medium

    Martensitic stainless steels are

    1. A hardenable by heat treatment; magnetic
    2. B always non-magnetic FCC
    3. C cannot be quenched
    4. D contain no chromium
    💡 Explanation:

    410, 420 used for cutlery and blades.

  57. Q57 Past Paper · PPSC/FPSC/NTS medium

    Aluminium alloys are often strengthened by

    1. A only carburizing
    2. B only nitriding
    3. C precipitation hardening (age hardening)
    4. D only white iron formation
    💡 Explanation:

    Duralumin: solution treat and age to form precipitates.

  58. Q58 easy

    Ultimate tensile strength is

    1. A stress at fracture always on same scale
    2. B elastic limit only
    3. C hardness number in Brinell
    4. D maximum stress on engineering stress-strain curve
    💡 Explanation:

    UTS is peak load divided by original area.

  59. Q59 easy

    Ductility is often expressed by

    1. A percent elongation or reduction in area
    2. B Young's modulus value
    3. C melting point in Kelvin
    4. D thermal conductivity only
    💡 Explanation:

    Large elongation indicates ductile material.

  60. Q60 Past Paper · PPSC/FPSC/NTS medium

    Brittle fracture shows

    1. A little plastic deformation before failure
    2. B necking and cup-cone fracture always
    3. C 50% elongation minimum
    4. D only ductile dimple rupture
    💡 Explanation:

    Cleavage or rapid crack propagation typical.

  61. Q61 Past Paper · PPSC/FPSC/NTS medium

    Charpy impact test measures

    1. A energy absorbed by notched specimen at given temperature
    2. B surface roughness Ra
    3. C electrical resistivity
    4. D magnetic permeability only
    💡 Explanation:

    Transition temperature indicates toughness loss.

  62. Q62 Past Paper · PPSC/FPSC/NTS easy

    Iron-carbon equilibrium diagram eutectoid point is at

    1. A 4.3% C at 1147°C
    2. B 0% C at 1538°C
    3. C 0.76% C at 727°C
    4. D 2.11% C at 727°C
    💡 Explanation:

    Eutectoid: austenite → pearlite.

  63. Q63 Past Paper · PPSC/FPSC/NTS easy

    Pearlite microstructure consists of

    1. A only austenite grains
    2. B alternating lamellae of ferrite and cementite
    3. C only martensite plates
    4. D only graphite flakes
    💡 Explanation:

    Eutectoid product in steel near 0.76% C.

  64. Q64 easy

    Cementite chemical formula is

    1. A Fe₃C
    2. B FeO
    3. C Fe₂O₃
    4. D Fe₃O₄
    💡 Explanation:

    Iron carbide intermetallic; hard and brittle.

  65. Q65 Past Paper · PPSC/FPSC/NTS medium

    Austenite is

    1. A BCC ferrite at room temperature
    2. B only liquid iron
    3. C only cementite plates
    4. D solid solution of carbon in gamma iron (FCC)
    💡 Explanation:

    γ-iron stable at high temperature; non-magnetic.

  66. Q66 Past Paper · PPSC/FPSC/NTS medium

    Martensite is formed by

    1. A slow furnace cooling only
    2. B hot rolling only
    3. C rapid quenching of austenite
    4. D annealing above 1000°C for days
    💡 Explanation:

    Diffusionless transformation gives hard brittle structure.

  67. Q67 medium

    Hardenability measures

    1. A only surface hardness of aluminium
    2. B depth to which steel hardens upon quenching
    3. C only copper conductivity
    4. D only cast iron graphite size
    💡 Explanation:

    Jominy end-quench test ranks hardenability.

  68. Q68 Past Paper · PPSC/FPSC/NTS easy

    Young's modulus measures

    1. A stiffness in elastic region (stress/strain slope)
    2. B plastic ductility only
    3. C hardness indentation only
    4. D thermal expansion only
    💡 Explanation:

    E = σ/ε in Hooke's law region.

  69. Q69 Past Paper · PPSC/FPSC/NTS easy

    Yield strength is the stress at which

    1. A fracture occurs always
    2. B material begins significant plastic deformation
    3. C elastic limit is undefined always
    4. D creep starts at all temperatures
    💡 Explanation:

    0.2% offset method common for metals.

  70. Q70 medium

    Slip in crystals occurs on

    1. A random planes only
    2. B close-packed planes in close-packed directions
    3. C only grain boundaries always
    4. D only external surfaces
    💡 Explanation:

    Resolved shear stress on slip systems causes yield.

  71. Q71 medium

    Dislocation is

    1. A a surface scratch only
    2. B a line defect in crystal lattice responsible for plastic deformation
    3. C a gas bubble in casting only
    4. D a type of grain boundary
    💡 Explanation:

    Edge and screw dislocations enable slip at lower stress.

  72. Q72 Past Paper · PPSC/FPSC/NTS medium

    Hall-Petch relation indicates yield strength increases as

    1. A grain size decreases
    2. B grain size increases
    3. C temperature increases
    4. D strain rate decreases always
    💡 Explanation:

    Finer grains block dislocations; σy ∝ 1/√d.

  73. Q73 Past Paper · PPSC/FPSC/NTS easy

    Grain boundaries in polycrystalline metals are

    1. A regions of perfect single crystal
    2. B only surface oxide layers
    3. C interfaces between crystals with different orientations
    4. D molten metal pools
    💡 Explanation:

    Boundaries impede dislocation motion affecting strength.

  74. Q74 medium

    Coordination number in FCC is

    1. A 8
    2. B 6
    3. C 4
    4. D 12
    💡 Explanation:

    Each atom touches 12 nearest neighbours in FCC/HCP.

  75. Q75 medium

    Hexagonal close-packed (HCP) structure is common in

    1. A copper and aluminium primarily
    2. B zinc, magnesium and titanium at room temperature
    3. C pure iron at all temperatures
    4. D lead only
    💡 Explanation:

    HCP metals include Zn, Mg, Ti (alpha).

  76. Q76 Past Paper · PPSC/FPSC/NTS easy

    Face-centered cubic (FCC) structure has atoms at

    1. A body center only with corners
    2. B only one corner
    3. C only edge centers
    4. D corners and face centers
    💡 Explanation:

    FCC: close-packed with 4 atoms per cell effectively.

  77. Q77 Past Paper · PPSC/FPSC/NTS easy

    Body-centered cubic (BCC) structure has atoms at

    1. A corners and face centers only
    2. B corners and body center of the cube
    3. C face centers only
    4. D edge midpoints only
    💡 Explanation:

    BCC: 8 corners + 1 body diagonal center.

  78. Q78 Past Paper · PPSC/FPSC/NTS easy

    Unit cell is

    1. A a biological cell in plants
    2. B a pressure vessel compartment only
    3. C the smallest repeating structural unit of a crystal lattice
    4. D a hydraulic cylinder chamber only
    💡 Explanation:

    Crystals are built by repeating unit cells in 3D.